I am using HttpUrlConnection to get JSON strings from web, but the response is good for smaller strings but not for larger ones: this is what I am seeing in my app, and this is the data from server to a web page I did not include any HTML from server side.
Here is my code:
URL adr = new URL("http://placeform.tk/forapp.php");
HttpURLConnection connection =(HttpURLConnection) adr.openConnection();
connection.connect();
int rcode = connection.getResponseCode();
Log.d("rcode",Integer.toString(rcode));
if (rcode == HttpURLConnection.HTTP_OK) {
InputStream inputStreamReader = connection.getInputStream();
String c = connection.getHeaderField("content-length");
Reader rd = new InputStreamReader(inputStreamReader);
Log.d("contentsize", Integer.toString(connection.getContentLength()) + c);
chars = new char[connection.getContentLength()];
Log.d("contentsize", Integer.toString((int)connection.getContentLength()) + c);
rd.read(chars);
String output = new String(chars);
use this link and add that class in your project and call webservice from that class. cause that class will build up your response string with use of string builder. have a look at that class. and comment if you have any problem.
Related
I am working on an Android App, App is using GET Request to connect with server.
The code I have written to connect with server is working perfectly on many devices.
But its not giving good response on LENOVO YOGA TAB3, It returns Html tags instead of JSON text, Firstly I was confused that there may be some issue in the API URL but I checked URL using browser, Its returning good response so I am sure URL is correct.
Here are API URL and its response :
API URL
[http://www.xyz.in/xyzapi/?building=on&address=Assotech Sandal Suites, Sector 135, Noida, Uttar Pradesh 201304, India&bill_amount=12500&type=R&fullstatename=Uttar Pradesh&lat=28.496171099999998&lng=77.4027049&state=UP&country=IN&district=Gautam Buddha Nagar&sublocality=Sector 135&calc-sess=59d4beba305f3&netmetering=1][1]
Response on Many Android Phones:
{"lifetimesaving":"25.0 Lacs","proposed_pv_capacity":10,"billWithSolar":3872,"bill_amount":"12500","sanction":10,"project_cost":"6.0 Lacs","return_oninevstment":"20.8","roi_image":"solar_score6_6.png","treeadded":"346 ","treeofftheroad":"9 "}
Response on Lenovo Yoga Tab3:
<head/><style>.personal-details h2{font-size:34px}.netmetering-tgle{position:absolute;left:0;right:0;bottom:5px;width:211px}.netmetering-tgle .wnm{float:left;position:relative;padding:0 10px 0 0;min-width:130px;text-align:center}.netmetering-tgle .wnm a{color:#c97511;background:none}#radioBtn .btn{border:1px solid transparent;border-radius:0!important;font-family:"Din-Bold"}#radioBtn .notActive{color:#c97511;background-color:#e0e1e2;padding:2px 0;width:38px;background-size:100% 100%;border-color:transparent;font-family:"Din-Bold";border-radius:5px}#radioBtn .active{color:#fff;background-color:#addc6f;border-color:transparent;padding:2px 5px;width:38px;cursor:auto;pointer-events:none;border-radius:5px;box-shadow:inset 0 0 10px rgba(0,0,0,.8)}#radioBtn .notActive[data-
So response is incorrect on Yoga Tab3.
Here is the code I am using to connect with Server :
public static String connectToServerUsingGETMethod(String API_COMPLETE_URL){
URL url;
HttpURLConnection urlConnection = null;
try {
url = new URL(API_COMPLETE_URL);
urlConnection = (HttpURLConnection) url.openConnection();
InputStream in = urlConnection.getInputStream();
InputStreamReader isr = new InputStreamReader(in);
String line = "";
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null) {
sb.append(line);
}
//get the string version of the response data
return sb.toString();
} catch (Exception e) {
e.printStackTrace();
} finally {
if (urlConnection != null) {
urlConnection.disconnect();
}
}
return "";
}
Suggest me If I can add something in this code so that it can work on Yoga Tab 3 too.
I think you should set static content type when making request to make sure the response sent back is JSON. Similarly, it looks like below:
HttpURLConnection urlConnection = null;
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
Hope it works for you.
i have tried to fetch the website content from android.
in .NET, it can be done by
WebRequest request = HttpWebRequest.Create(threeROllrl);
WebResponse response = request.GetResponse();
StreamReader vr = new StreamReader(response.GetResponseStream());
string result = vr.ReadToEnd();
however, in android, i tried to use
URL url = new URL(urlstr);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setReadTimeout(8000 /* milliseconds */);
urlConnection.setConnectTimeout(8000 /* milliseconds */);
urlConnection.setRequestMethod("GET");
urlConnection.connect();
BufferedReader reader = null;
reader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
StringBuilder stringBuilder = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
{
stringBuilder.append(line + "\n");
}
but it returned different content (in android httpurlconnection, no html content is fetched at all, but the metadata, style and scripts only), i wanna if it is because the response are the mobile version, i want to how retrieve the desktop content of the website in the android httpurlconnection.
after checked, i have found that the android httpurlconnection is actually fetching the header of the website and some bottom content, but it cannot fetch middle body. or it is stopped for some unknown reason (but no error is found).
thanks
Change the User-agent header in your http request to be as a desktop
here is a list of user agent that you can use
I have a REST service I can't alter, with methods for uploading an image, encoded as a Base64 string.
The problem is that the images can go up to sizes of 5-10MB, perhaps more. When I try to construct a Base64 representation of an image of this size on the device, I get an OutOfMemory exception.
I can however encode chunks of bytes at a time (3000 let's say), but this is useless as I would need the whole string to create a HttpGet/HttpPost object:
DefaultHttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("www.server.com/longString");
HttpResponse response = client.execute(httpGet);
Is there a way of going around this?
Edit: trying to use Heiko Rupp's suggestions + the android doc, I get an exception ("java.io.FileNotFoundException: http://www.google.com") at the following line: InputStream in = urlConnection.getInputStream();
try {
URL url = new URL("http://www.google.com");
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setDoOutput(true);
urlConnection.setChunkedStreamingMode(0);
OutputStream out = new BufferedOutputStream(urlConnection.getOutputStream());
out.write("/translate".getBytes());
InputStream in = urlConnection.getInputStream();
BufferedReader r = new BufferedReader(new InputStreamReader(in));
StringBuilder total = new StringBuilder();
String line;
while ((line = r.readLine()) != null) {
total.append(line);
}
System.out.println("response:" + total);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
Am I missing something? The GET request that I need to execute looks like this:
"http://myRESTService.com/myMethod?params=LOOONG-String", so the idea was to connect to http://myRESTService.com/myMethod and then output a few characters of the long string at a time. Is this correct?
You should try to use the URLConnection instead of the apache http client, as this does not require you to hold the object to send in memory, but instead you can do something like:
pseudocode!
HttpUrlConnection con = restUrl.getConnection();
while (!done) {
byte[] part = base64encode(partOfImage);
con.write (part);
partOfImage = nextPartOfImage();
}
con.flush();
con.close();
Also in Android after 2.2 Google recommends the URLConnection over the http client. See the description of DefaultHttpClient.
The other thing you may want to look into is the amount of data to be sent. 10 MB + base64 will take quite a while to transfer (even with gzip compression, which the URLConnection transparently enables if the server side accepts it) over a mobile network.
You must read docs for this REST service, no such service will require you to send such long data in GET. Images are always sent as POST. POST data is always at the end of request and allows to be added iteratively.
I have an app I am developing that requires me to post data to a 3rd party API. I have been struggling with authentication since the beginning and kept putting off further and further, and now I'm stuck.
I have tried using an Authenticator, but have read all about how there appears to be a bug in certain Android versions: Authentication Example
I have tried several different options, including the Apache Commons HTTP Library with no success. After all of this, I decided to make sure that the API wasn't the pain point. So I wrote a quick WinForms program to test the API, which worked perfectly on the first try. So, the idea that I'm working from and the API I working with both seem fine, but I am in desperate need of some guidance as to why the Java code isn't working.
Examples follow:
C# Code that works everytime:
System.Net.ServicePointManager.Expect100Continue = false;
// Create a request using a URL that can receive a post.
WebRequest request = WebRequest.Create(addWorkoutUrl);
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
string postData = "distance=4000&hours=0&minutes=20&seconds=0&tenths=0&month=08&day=01&year=2011&typeOfWorkout=standard&weightClass=H&age=28";
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
// Set the ContentType property of the WebRequest.
request.Headers["X-API-KEY"] = apiKey;
request.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("username:password"));
request.ContentType = "application/x-www-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.
Stream dataStream = request.GetRequestStream();
// Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close();
// Get the response.
WebResponse response = request.GetResponse();
// Display the status.
MessageBox.Show(((HttpWebResponse)response).StatusDescription);
// Get the stream containing content returned by the server.
dataStream = response.GetResponseStream();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader(dataStream);
// Read the content.
string responseFromServer = reader.ReadToEnd();
// Display the content.
MessageBox.Show(responseFromServer);
// Clean up the streams.
reader.Close();
dataStream.Close();
response.Close();
Java code for Android that currently returns a 500:Internal Server Error, though I believe this is my fault.
URL url;
String data = "distance=4000&hours=0&minutes=20&seconds=0&tenths=0&month=08&day=01&year=2011&typeOfWorkout=standard&weightClass=H&age=28";
HttpURLConnection connection = null;
//Create connection
url = new URL(urlBasePath);
connection = (HttpURLConnection)url.openConnection();
connection.setConnectTimeout(10000);
connection.setUseCaches(false);
connection.setRequestProperty("User-Agent","Mozilla/5.0 ( compatible ) ");
connection.setRequestProperty("Accept","*/*");
connection.setRequestProperty("X-API-KEY", apiKey);
connection.setRequestProperty("Authorization", "Basic " +
Base64.encode((username + ":" + password).getBytes("UTF-8"), Base64.DEFAULT));
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length", "" + Integer.toString(data.getBytes("UTF-8").length));
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.write(data.getBytes("UTF-8"));
wr.flush();
wr.close();
statusCode = connection.getResponseCode();
statusReason = connection.getResponseMessage();
//At this point, I have the 500 error...
I figured out the problem, and the solution finally after stumbling across the root cause as mentioned in the comment above.
I was using Base64.encode() in my example, but I needed to be using Base64.encodeToString().
The difference being that encode() returns a byte[] and encodeToString() returns the string I was expecting.
Hopefully this will help somebody else who is caught by this.
Here's a nicer method to do to the POST.
install-package HttpClient
Then:
public void DoPost()
{
var httpClient = new HttpClient();
var creds = string.Format("{0}:{1}", _username, _password);
var basicAuth = string.Format("Basic {0}", Convert.ToBase64String(Encoding.UTF8.GetBytes(creds)));
httpClient.DefaultRequestHeaders.Add("Authorization", basicAuth);
var post = httpClient.PostAsync(_url,
new FormUrlEncodedContent(new Dictionary<string, string>
{
{ "name", "Henrik" },
{ "age", "99" }
}));
post.Wait();
}
I have tried this in java
import java.io.*;
import java.net.*;
class download{
public static void main(String args[]){
try{
String details = "API-Key=e6d871be90a689&orderInfo={\"booking\":{\"restaurantinfo\":{\"id\":\"5722\"},\"referrer\":{\"id\": \"9448476530\" }, \"bookingdetails\":{\"instructions\":\"Make the stuff spicy\",\"bookingtime\": \"2011-11-09 12:12 pm\", \"num_guests\": \"5\"}, \"customerinfo\":{\"name\":\"Ramjee Ganti\", \"mobile\":\"9345245530\", \"email\": \"sajid#pappilon.in\", \"landline\":{ \"number\":\"0908998393\",\"ext\":\"456\"}}}}";
Authenticator.setDefault(new Authenticator() {
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication("admin", "1234".toCharArray());
}
});
HttpURLConnection conn = null;
//URL url = new URL("http://api-justeat.in/ma/orders/index");
URL url = new URL("http://api.geanly.in/ma/order_ma/index");
conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setDoInput (true);
conn.setRequestMethod("POST");
//conn.setRequestMethod(HttpConnection.POST);
DataOutputStream outStream = new DataOutputStream(conn.getOutputStream());
outStream.writeBytes(details);
outStream.flush();
outStream.close();
//Get Response
InputStream is = conn.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while((line = rd.readLine()) != null) {
System.out.println(line);
}
rd.close();
System.out.println(conn.getResponseCode() + "\n\n");
}catch(Exception e){
System.out.println(e);
}
}
}
this could help.
I have to connect to a webserver from android and I have to access a webservice and a webpage from the webserver. Can anybody help me? Please give step by step process with some code snippets because I am new to android and I don't know anything in connecting to a webserver.
You can use an HttpClient:
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(uri);
HttpResponse httpResponse = httpClient.execute(httpGet);
BufferedReader reader = new BufferedReader(
new InputStreamReader(httpResponse.getEntity().getContent()));
// user reader to read & parse response
reader.close();
Parsing the response obviously depends on the format (e.g. SOAP, JSON, etc.)
You haven't given very much info (what kind of web page, XML/JSON/HTML/etc. ?). But the basic principles of regular Java apply. Using URL and InputStream:
URL url = new URL(...);
InputStream is = url.openStream();
And from there it depends what kind of data you're dealing with.
If you don't want to use an additional library, here is a means for sending an "id" and "name" to a server:
URL url = null;
try {
String registrationUrl = String.format("http://myserver/register?id=%s&name=%s", myId, URLEncoder.encode(myName,"UTF-8"));
url = new URL(registrationUrl);
URLConnection connection = url.openConnection();
HttpURLConnection httpConnection = (HttpURLConnection) connection;
int responseCode = httpConnection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
Log.d("MyApp", "Registration success");
} else {
Log.w("MyApp", "Registration failed for: " + registrationUrl);
}
} catch (Exception ex) {
ex.printStackTrace();
}
You could just as easily send other data via this URI "GET" style, but if you need to send something more detailed a POST will be required.
Note: Originally posted to answer a similar question here: How to connect android to server