What I want is to share the link of specific page of my application. Suppose I am in a profile page of some user in my app and I want to share that user to some of my friends so I would like to share it via WhatsApp and other applications.
So basically I want to share a link to my app.
This is what I am doing right now
Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
shareIntent.setType("text/plain");
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, "https://play.google.com/store/apps/details?id=" + activity.getPackageName());
activity.startActivity(Intent.createChooser(shareIntent, "Share"));
I know this is not what I really want but it's partially done.
if user hasn't installed my app then this code redirect him to google play store page to download this app.
Main problem is when user have already this app this link just opens the app. I want to redirect user to that specific page when he clicks on a link.
How can I do this?
I heard something about intent-filter but not sure how to use them.
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.BROWSABLE" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="application/pdf" />
UPDATED
Now I am trying to share my app link like this
Intent shareIntent = new Intent(android.content.Intent.ACTION_SEND);
shareIntent.setType("text/plain");
shareIntent.putExtra("PostID", postID);
shareIntent.putExtra("UserID", userID);
shareIntent.putExtra(android.content.Intent.EXTRA_TEXT, "https://play.google.com/store/apps/details?id=" + activity.getPackageName());
activity.startActivity(Intent.createChooser(shareIntent, "Share"));
Inside my manifest I have declared an activity like this
<activity
android:name=".activities.ShareActivity"
android:screenOrientation="sensorPortrait"
android:theme="#style/Theme.AppCompat.Light.NoActionBar.FullScreen">
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="details"
android:scheme="market" />
<data
android:host="play.google.com"
android:pathPattern="/store/apps/details?id=my_package_name"
android:scheme="http" />
<data
android:host="play.google.com"
android:pathPattern="/store/apps/details?id=my_package_name"
android:scheme="https" />
</intent-filter>
</activity>
But I am still not able to see my app when I click on the link I shared using WhatsApp or any other means.
Please help me
Any help will be really appreciated.
Thanks in advance.
Add the following intent-filters to your activity declaration, in the AndroidManifest of your project :
<intent-filter>
<action android:name="android.intent.action.SEND"/>
<category android:name="android.intent.category.DEFAULT"/>
<data android:mimeType="text/plain"/>
</intent-filter>
Now, in the onCreate(), onResume() or onNewIntent() method of your activity lifecycle, you can use the getData() of the intent that has fired your activity.
In my android application, I have an intent filter linked to one of my activities in my AndroidManifest.xml like so:
<activity
android:name=".MainActivity"
android:label="#string/name >
<intent-filter>
<action android:name="android.intent.action.SEND />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</activity>
By my understanding this should add my app the list of apps in my browser (Chrome) that are under the "Share..." section so that my app can use the URL of the current web page. This list contains Flipboard, Android Beam, Twitter, Keep, Google+, etcetera.
I've found many examples on how to do this, they all use the above code. However, my app doesn't show up on that list for some reason. What could be the reason for this and how can I solve this issue?
Thanks!
You are including the action and category correctly but you also need to include the mimeTypes so that the Intent knows what type of sharing you want to support. Try including these two lines in order to support both text and image sharing:
<data android:mimeType="text/plain" />
<data android:mimeType="image/*" />
Like so:
<intent-filter>
<action android:name="android.intent.action.SEND />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
<data android:mimeType="image/*" />
</intent-filter>
If you then want to retrieve the URL from the Intent to utilise in your app then you'll want to add this code to your onCreate() method in MainActivity:
String action = intent.getAction();
if (action.equalsIgnoreCase(Intent.ACTION_SEND) && intent.hasExtra(Intent.EXTRA_TEXT)) {
String URL = intent.getStringExtra(Intent.EXTRA_TEXT);
}
Request OAuth (when twitter button cliked)
final String TW_CALLBACK_URL_STRING = "http://test.com/callback";
final Uri TW_CALLBACK_URI = Uri.parse(TW_CALLBACK_URL_STRING);
twitter4j.auth.RequestToken twRequestToken =
twitter.getOAuthRequestToken(TW_CALLBACK_URI.toString());
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse(twRequestToken.getAuthorizationURL()));
activity.startActivityForResult(intent, TWITTER_REQUEST_CODE);
Manifest
<activity android:name=".TwitterLinkActivity" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<data
android:scheme="http"
android:host="test.com" />
<category android:name="android.intent.category.BROWSABLE" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</activity>
Twitter Developer App Settings
Clicking twitter button on my app, Web Browser (chrome android) is opened.
And I log in twitter account and click "accept app" button ("애플리케이션 승인" in below image, UZTest is my test twitter app name.)
I am not native English speaker. So I do not know exactly words in English...
I think browser link to http://test.com/callback?~~~~. And My app catch this url, and start activity.
But my app can not... It just link http://www.test.com in chrome android browser.
I tried change callback url = "myapp://test.com", but only http(or https) is only available. (Twitter Developer)
How can I receive oauth token?
I did sovle it!
Below two value is not same value (?)
final String TW_CALLBACK_URL_STRING = "http://test.com/callback";
Callback URL: http://test.com/callback (OAuth Setting in Twitter Developer)
1 is only use my app. So I change to "myscheme://myhost" in java code and manifest file.
2 is not oauth request callback url (I do not know exactly what.)
Then It works fine.
The web and stackoverflow contain several examples how to get a file from another Android app (e.g., to use it as email attachment) using an ACTION_GET_CONTENT intent. But what kind of class do I have to implement to create an application providing content for the ACTION_GET_CONTENT event such as I can choose this app (e.g., for selecting an email attachment).
Is a ContentProvider the right solution? And what do I have to add to my AndroidManifest.xml?
After some hours of web search I found the following solution.
Implement an Activity handling intents. Within, use the following or more specific code:
Uri resultUri = // the thing to return
Intent result = new Intent();
result.setData(resultUri);
setResult(Activity.RESULT_OK, result);
finish();
Add the following to the Manifest:
<activity
android:name="ActivityName"
android:label="Some label" >
<intent-filter>
<action android:name="android.intent.action.GET_CONTENT" />
<category android:name="android.intent.category.OPENABLE" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="*/*" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.PICK" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="*/*" />
</intent-filter>
</activity>
starting from api level 18 incoming intent can also have EXTRA_ALLOW_MULTIPLE set to true and in this case you can send back in result more than one file. To do so you need to set it as ClipData:
resultIntent.setClipData(clipData)
Can anybody please guide me regarding how to launch my android application from the android browser?
Use an <intent-filter> with a <data> element. For example, to handle all links to twitter.com, you'd put this inside your <activity> in your AndroidManifest.xml:
<intent-filter>
<data android:scheme="http" android:host="twitter.com"/>
<action android:name="android.intent.action.VIEW" />
</intent-filter>
Then, when the user clicks on a link to twitter in the browser, they will be asked what application to use in order to complete the action: the browser or your application.
Of course, if you want to provide tight integration between your website and your app, you can define your own scheme:
<intent-filter>
<data android:scheme="my.special.scheme" />
<action android:name="android.intent.action.VIEW" />
</intent-filter>
Then, in your web app you can put links like:
<a href="my.special.scheme://other/parameters/here">
And when the user clicks it, your app will be launched automatically (because it will probably be the only one that can handle my.special.scheme:// type of uris). The only downside to this is that if the user doesn't have the app installed, they'll get a nasty error. And I'm not sure there's any way to check.
Edit: To answer your question, you can use getIntent().getData() which returns a Uri object. You can then use Uri.* methods to extract the data you need. For example, let's say the user clicked on a link to http://twitter.com/status/1234:
Uri data = getIntent().getData();
String scheme = data.getScheme(); // "http"
String host = data.getHost(); // "twitter.com"
List<String> params = data.getPathSegments();
String first = params.get(0); // "status"
String second = params.get(1); // "1234"
You can do the above anywhere in your Activity, but you're probably going to want to do it in onCreate(). You can also use params.size() to get the number of path segments in the Uri. Look to javadoc or the android developer website for other Uri methods you can use to extract specific parts.
All above answers didn't work for me with CHROME as of 28 Jan 2014
my App launched properly from http://example.com/someresource/ links from apps like hangouts, gmail etc but not from within chrome browser.
to solve this, so that it launches properly from CHROME you have to set intent filter like this
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="example.com"
android:pathPrefix="/someresource/"
android:scheme="http" />
<data
android:host="www.example.com"
android:pathPrefix="/someresource/"
android:scheme="http" />
</intent-filter>
note the pathPrefix element
your app will now appear inside activity picker whenever user requests http://example.com/someresource/ pattern from chrome browser by clicking a link from google search results or any other website
Please see my comment here: Make a link in the Android browser start up my app?
We strongly discourage people from using their own schemes, unless they are defining a new world-wide internet scheme.
In my case I had to set two categories for the <intent-filter> and then it worked:
<intent-filter>
<data android:scheme="my.special.scheme" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE"/>
</intent-filter>
For example, You have next things:
A link to open your app: http://example.com
The package name of your app: com.example.mypackage
Then you need to do next:
Add an intent filter to your Activity
(Can be any activity you want. For more info check the documentation).
<activity
android:name=".MainActivity">
<intent-filter android:label="#string/filter_title_view_app_from_web">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<!-- Accepts URIs that begin with "http://example.com" -->
<data
android:host="example.com"
android:scheme="http" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
Create a HTML file to test the link or use this methods.
Open your Activity directly (just open your Activity, without a choosing dialog).
Open this link with browser or your programm (by choosing dialog).
Use Mobile Chrome to test
That's it.
And its not necessary to publish app in market to test deep linking =)
Also, for more information, check documentation and useful presentation.
There should also be <category android:name="android.intent.category.BROWSABLE"/> added to the intent filter to make the activity recognized properly from the link.
The following link gives information on launching the app (if installed) directly from browser. Otherwise it directly opens up the app in play store so that user can seamlessly download.
https://developer.chrome.com/multidevice/android/intents
Please note if your icon is disappear from android launcher when you implement this feature, than you have to split intent-filter.
<activity
android:name=".MainActivity"
android:label="#string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="your-own-uri" />
</intent-filter>
</activity>
Yeah, Chrome searches instead of looking for scheme. If you want to launch your App through URI scheme, use this cool utility App on the Play store. It saved my day :)
https://play.google.com/store/apps/details?id=com.naosim.urlschemesender
Xamarin port of Felix's answer
In your MainActivity, add this (docs: Android.App.IntentFilterAttribute Class):
....
[IntentFilter(new[] {
Intent.ActionView },
Categories = new[] { Intent.CategoryDefault, Intent.CategoryBrowsable },
DataScheme = "my.special.scheme")
]
public class MainActivity : Activity
{
....
Xamarin will add following in the AndroidManifest.xml for you:
<activity
android:label="Something"
android:screenOrientation="portrait"
android:theme="#style/MyTheme"
android:name="blah.MainActivity">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="my.special.scheme" />
</intent-filter>
</activity>
And in order to get params (I tested in OnCreate of MainActivity):
var data = Intent.Data;
if (data != null)
{
var scheme = data.Scheme;
var host = data.Host;
var args = data.PathSegments;
if (args.Count > 0)
{
var first = args[0];
var second = args[1];
...
}
}
As far as I know, above can be added in any activity, not only MainActivity
Notes:
When user click on the link, Android OS relaunch your app (kill prev instance, if any, and run new one), means the OnCreate event of app's MainLauncher Activity will be fired again.
With this link: <a href="my.special.scheme://host/arg1/arg2">, in above last code snippet values will be:
scheme: my.special.scheme
host: host
args: ["arg1", "arg2"]
first: arg1
second: arg2
Update: if android creates new instance of your app, you should add android:launchMode="singleTask" too.
Felix's approach to handling deep links is the typical approach to handling deep links. I would also suggest checking out this library to handle the routing and parsing of your deep links:
https://github.com/airbnb/DeepLinkDispatch
You can use annotations to register your Activity for a particular deep link URI, and it will extract out the parameters for you without having to do the usual rigmarole of getting the path segments, matching it, etc. You could simply annotate and activity like this:
#DeepLink("somePath/{someParameter1}/{someParameter2}")
public class MainActivity extends Activity {
...
}
Hey I got the solution. I did not set the category as "Default". Also I was using the Main activity for the intent Data. Now i am using a different activity for the intent data. Thanks for the help. :)
You need to add a pseudo-hostname to the CALLBACK_URL 'app://' doesn't make sense as a URL and cannot be parsed.
example.php:
<?php
if(!isset($_GET['app_link'])){ ?>
<iframe src="example.php?app_link=YourApp://blabla" style="display:none;" scrolling="no" frameborder="0"></iframe>
<iframe src="example.php?full_link=http://play.google.com/xyz" style="display:none;" scrolling="no" frameborder="0"></iframe>
<?php
}
else { ?>
<script type="text/javascript">
self.window.location = '<?php echo $_GET['app_link'];?>';
window.parent.location.href = '<?php echo $_GET['full_link'];?>';
</script>
<?php
}
Look #JRuns answer in here. The idea is to create html with your custom scheme and upload it somewhere. Then if you click on your custom link on your html-file, you will be redirected to your app. I used this article for android. But dont forget to set full name Name = "MyApp.Mobile.Droid.MainActivity" attribute to your target activity.
As of 15/06/2019
what I did is include all four possibilities to open url.
i.e, with http / https and 2 with www in prefix and 2 without www
and by using this my app launches automatically now without asking me to choose a browser and other option.
<intent-filter android:autoVerify="true">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="https" android:host="example.in" />
<data android:scheme="https" android:host="www.example.in" />
<data android:scheme="http" android:host="example.in" />
<data android:scheme="http" android:host="www.example.in" />
</intent-filter>