Develop Reference

Convert string into LocalDateTime

I have the following String:
18/07/2019 16:20
I try to convert this string into LocalDateTime with the following code:
val stringDate = expiration_button.text.toString()
val date = LocalDateTime.parse(stringDate, DateTimeFormatter.ofPattern("dd/MM/yyyy hh:mm")).toString()
java.time.format.DateTimeParseException: Text '18/07/2019 04:30:00'
could not be parsed: Unable to obtain LocalDateTime from
TemporalAccessor
What I'm missing?

I think this will answer your question:
val stringDate = expiration_button.text.toString()
val formatter = DateTimeFormatter.ofPattern("dd/MM/yyyy hh:mm");
val dt = LocalDate.parse(stringDate, formatter);
Edit 1:
It's probably crashing because you are using a 12hr Hour, instead of a 24hr pattern.
Changing the hour to 24hr pattern by using a capital H should fix it:
val dateTime = LocalDateTime.parse(stringDate, DateTimeFormatter.ofPattern("dd/MM/yyyy HH:mm"));

Use below to convert the time from String to LocalDateTime, but make sure you are getting the time in String form.
String str = "2016-03-04 11:30";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm");
LocalDateTime dateTime = LocalDateTime.parse(str, formatter);
Btw, If your String contains seconds as well like "2016-03-04 11:30: 40", then you can change your date time format to yyyy-MM-dd HH:mm:ss" as shown below:
String str = "2016-03-04 11:30: 40";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime dateTime = LocalDateTime.parse(str, formatter);

Change your datetime format to "dd/MM/yyyy hh:mm a" and provide a string date with additional AM/PM information, e.g. val stringDate = "18/07/2019 04:20 PM" or just use the 24 hour format "dd/MM/yyyy HH:mm".

You may try using "-" instead of "/" on the date.

Joda time convert ISO8601 GMT to local

I have this from my server:
2017-04-07T11:00:00.000Z
How can I convert it to local time? Here is my code, but all I got is an exception:)
java.lang.IllegalArgumentException: Invalid format: "2017-04-07T11:00:00.000Z" is malformed at "Z"
DateTimeFormatter inputFormatter = DateTimeFormat
.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSSZZZZZ") //yyyy-MM-dd'T'HH:mm:ss.SSSZZZZZ
.withLocale(Locale.US);
DateTime parsed = inputFormatter.parseDateTime(gmtDate);
DateTimeFormatter outputFormatter = DateTimeFormat
.forPattern("HH:mm")
.withLocale(Locale.US)
.withZone(DateTimeZone.getDefault());
return outputFormatter.print(parsed);

Just change your pattern to yyyy-MM-dd'T'HH:mm:ss.SSSZ, like this:
DateTimeFormatter inputFormatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSSZ")
.withLocale(Locale.US);
In my case, the result of outputFormatter.print(parsed) is 08:00 (my local time, as my default timezone is America/Sao_Paulo)

Convert 12 hour time to 24 hour using Joda time

I am getting this error
Invalid format: "09:30 PM" is malformed at " PM"
LocalTime start = new LocalTime();
LocalTime end = new LocalTime();
DateTimeFormatter formatter = DateTimeFormat.forPattern("hh:mm a");
start = formatter.parseLocalTime(from.toLowerCase());
end = formatter.parseLocalTime(to.toLowerCase());

Your Pattern is incorrect. Please use the following:
DateTimeFormatter formatter= DateTimeFormat.forPattern("hh:mm aa");
Edit: Here is a link to the Documentation for DateTimeFormat.

android convert utc time in 24 hours format

In my app i need to convert my current date into UTC format, i can successfully converted, now problem is i need 24 hours format check it out my below code
public static String CurrentDate() {
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
df.setTimeZone(TimeZone.getTimeZone("UTC"));
LogUtil.d("new Date()" + new Date());
return df.format(new Date());
}
now my CurrentDate returns 1.45 but i need 13.45 how can i convert utc in 24 hours format?
i have search through google but dint get proper answer, all suggestions are most welcome
Thanks in advance

Changing the hour part at your SimpleDateFormat constructor call from hh to HH does the job:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Output:
2015-07-13 13:53:02
See also Table of Date and Time Patterns

As Jon Skeet said, check the String you pass on SimpleDateFormat() : http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
You need to replace "hh" with "HH" so it will become "yyyy-MM-dd HH:mm:ss"
Of course if you only need the hour and minute that should be "HH:mm"

Android date time parsing

I am trying to parse the following str to Date:
2013-10-23T11:00:00EDT
I am using follwoing to do so:
String TIMEZONE_DATE_TIME_FORMAT = "yyyy-MM-dd'T'HH:mm:ssz";
Date date = new SimpleDateFormat(TIMEZONE_DATE_TIME_FORMAT, Locale.US).parse(strDate);
its working good on most devices but on some it throws the following exception:
java.text.ParseException: Unparseable date: "2013-10-23T11:00:00EDT" (at offset 19)
Can someone explain why?

Try this code. This may help you to fix the exception
SimpleDateTime format = new SimpleDateTime("yyyy-MM-dd'T'HH:mm:ssX", Locale.US);
Date date = format.parse(text);
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ssZ")
.withLocale(Locale.US);
DateTime dateTime = formatter.parseDateTime(text);
In fact, there's an ISODateTimeFormat class to make this even simpler:
DateTimeFormatter formatter = ISODateTimeFormat.dateTimeNoMillis();