Develop Reference

Json object returns with brackets

I'm trying to parse an Json object and it has this data:
"ingredients":["White bread","Bratwurst","Onions","Tomato ketchup","Mustard","Curry powder"]
When I return the value, the textview prints this :
[White bread,Bratwurst,Onions,Tomato ketchup,Mustard,Curry powder]
I want to remove the brackets but I cant. I'm doing this so far:
List<String> mIngredientArray = new ArrayList<>();
JSONArray ingredients = null;
Sandwich mSandwich = new Sandwich();
ingredients = mJsonObject.getJSONArray("ingredients");
for(int i=0; i<ingredients.length();i++){
mIngredientArray.add(ingredients.getString(i));
}
mSandwich.setIngredients(mIngredientArray);
The textview code:
ingredientsTV.setText(sandwich.getIngredients().toString());
But doesnt works. Any idea about how to solve it?
REQUIRED OUTPUT:-
White bread, Bratwurst, Onions, Tomato ketchup, Mustard, Curry powder

If you just want to remove the brackets, you can use regex like this
strIngredients = sandwich.getIngredients().toString();
strIngredients = strIngredients.replaceAll("\\[", "").replaceAll("\\]","");
ingredientsTV.setText(strIngredients);

You could just replace the bracket characters as suggested, but that doesn’t strike me as the most direct solution. You need to specify how the List object is converted to a string — something like:
String.join(“, “, mIngredientArray)

Finally, I used this line of code to solve my problem:
ingredientsTv.setText(sandwich.getIngredients().toString().replace("[","").replace("]",""));
When I tried to use ReplaceAll, the IDE said that I need to use 24 as minimunSdkVersion but I was using 16 so that's the reason I use replace instead of ReplaceAll. And it works finally.

Android edit/insert into string

I was wondering how I could programmatically edit strings in android. I am displaying strings from my device to my website, and the apostrophes ruin the PHP output. so in order to fix this, I needed to add character breaks, ie: the backslash '\'.
For example, if I have this string: I love filiberto's!
I need android to edit it to: I love filiberto\'s!
However, each string is going to be different, and there will also be other characters that I have to escape from . How can I do this?
I was wondering how I could programmatically edit strings in android. I am displaying strings from my device to my website, and the apostrophes ruin the PHP output. so in order to fix this, I needed to add character breaks, ie: the backslash '\'.
This is what I have so far, thanks to ANJ for base code...:
if(title.contains("'")) {
int i;
int len = title.length();
char[] temp = new char[len + 1]; //plus one because gotta add new
int k = title.indexOf("'"); //location of apostrophe
for (i = 0; i < k; i++) { //all the letters before the apostrophe
temp[i] = title.charAt(i); //assign letters to array based on index
}
temp[k] = 'L'; // the L is for testing purposes
for (i = k+1; i == len; i++) { //all the letters after apostrophe, to end
temp[i] = title.charAt(i); //finish the original string, same array
}
title = temp.toString(); //output array to string (?)
Log.d("this is", title); //outputs gibberish
}
Which outputs random characters.. not even similar to my starting string. Does anyone know what could be causing this? For example, the string "Lol'ok" turns into >> "%5BC%4042ed0380"

I am assuming you are storing the string somewhere. Lets say the string is: str.
You can use a temporary array to add the '/'. For a single string:
int len = str.length();
char [] temp = new char[len+1]; //Temporary Array
int k = str.indexOf("'"), i; //Finding index of "'"
for(i=0; i<k-1; i++)
{
temp[i] = str.charAt(i); //Copying the string before '
}
temp[k] = '/'; //Placing "/" before '
for(i=k; j<len; j++)
{
temp[i+1] = str.charAt(i); //Copying rest of the string
}
String newstr = temp.toString(); //Converting array to string
You can use the same for multiple strings. Just make it as a function and call it whenever you want.

The String API has a number of API calls that could help, for example String.replaceAll. But...
apostrophes ruin the PHP output
Then fix the PHP code rather than require "clean" input. Best option would be to select a well supported transport format (say JSON or XML) and let the Json API on each end handle escape code.

how to get text with using substring

I try to get only this part "9916-4203" in "Region Code:9916-4203 " in android. How can I do this?
I tried below code, I used substring method but it doesn't work:
firstNumber = Integer.parseInt(message.substring(11, 19));

If you know that string contains "Region Code:" couldn't you do a replace?
message = message.replace("Region Code:", "");

Assumed that you have only one phone number in your String, the following will remove any non-digit characters and parse the resulting number:
public static int getNumber(String num){
String tmp = "";
for(int i=0;i<num.length();i++){
if(Character.isDigit(num.charAt(i)))
tmp += num.charAt(i);
}
return Integer.parseInt(tmp);
}
Output in your case: 99164203
And as already mentioned, you won't be able to parse any String to Integer in case there are any non-digit characters

Im going to guess that what you want to extract is the full region code text minus the title. So maybe using regex would be a good simple fit for you?
String myString = "Region Code:9916-4203";
String match = "";
String pattern = "\:(.*)";
Pattern regEx = Pattern.compile(pattern);
Matcher m = regEx.matcher(myString);
// Find instance of pattern matches
Matcher m = regEx.matcher(myString);
if (m.find()) {
match = m.group(0);
}
Variable match will contain "9916-4203"
This should work for you.
Java code sourced from http://android-elements.blogspot.in/2011/04/regular-expressions-in-android.html

In Java the substring() method works with the first parameter being inclusive and the second parameter being exclusive. Meaning "Hello".substring(0, 2); will result in the string He.
In addition to excluding the parsing of something that isn't a number like #Opiatefuchs mentioned, your substring method should instead be message.substring(12, 21).

Parse a string and get certain values

I have a string like this:
_id:2 thread_id:189 address:0292 m_size:null person:0 date:1372494272447 date_sent:0 protocol:0 read:1 status:-1 type:1 reply_path_present:0 subject:null body:Ok. Reply message. service_center:051108 locked:0 sim_id:0 error_code:0 seen:1 _id:1 thread_id:189 address:292 m_size:null person:0 date:1372493695831 date_sent:0 protocol:null read:1 status:-1 type:2 reply_path_present:null subject:null body:Test message service_center:null locked:0 sim_id:0 error_code:0 seen:0
I want to retrieve only parts of this string, for example the address:0292 and the body:xyz from the entire string. I want all instances of these two from a very large String (above is just a sample). Let's assume its more than 20000 characters.
How can I achieve this?

Looks like every address is followed by m_size, so use the string.split() function, to split over the keyword address then select the string.substring() (from each string in the resulting array) until reaching the keyword m_size. And repeat the entire thing for the keywords body and service_center. I can't think of any other way.

You are right, it doesn't seem pretty. But it works :)
String[] splitString = string.split(" ");
for (int i = 0; i < splitString.length; i++) {
if (splitString[i].startsWith("body") || splitString[i].startsWith("address"))
Log.i(TAG, "Found: " + splitString[i]);
// Do whatever you need to do
}

How can I pull individual characters from a string and convert them to numbers?

What I'm trying to do is find a way I can take the word "camel" for example from a EditText field and make for instance c=2 a=1 m=4 e=5 l=3. Is there anyway I can pull the individual characters from a string and convert them to numbers?
I've tried using "split" to separate each character into an array but I can't figure out how to convert the letters into numbers
so I can do something like:
a=1
b=2
c=3
int temp = (int)(array[1]+array[2]+array[3]+etc...)
using the example of "camel" would equal 15
This is what I have so far:
String name = inputarea.getText().toString();
String[] array = name.split("");
for(int i =0; i < array.length ; i++)
The biggest problem I keep having is if I try to pull from the 7th position in the array and nothing is there. (camel only has 5 characters) then I get a nice big error.
Thank you for any help that can be provided.
Edit: I figured it out after a few hours of playing with it here is my working code:
String firstname = inputarea.getText().toString();
char[] array = firstname.toCharArray();
final char[] array2 = new char[15];
System.arraycopy(array, 0, array2, 0, array.length);
if (array2[0] == 'A' ) {
array2[0] = '1';
}

suggestion:
first, need define all letter, from a-z (A-Z), the ASCII code 'a' to 'z' is 97 to 122, if you want support the upper letter, you need add A-Z.
then, get the letter in the string, u can use this:
for(int i=0;i<string.length();i++){
int number = string.charAt(i);
}
when you get the number size, you can reduce to the base number('a' is 97), you will get the individual number

Does String.charAt() works for you?
As for converting to number, if the numbers are consecutive you can define a fixed string with all the characters you want to map and use String.indexOf(). If not, you can have a parallel array with ints or use a Map.