I am new to android developer. I convert the GMT to local mobile time. I got am /pm issues in this code. After 6'o clock evening time . I got am in conversion.
sorry for my English. Advance thanks for help.
public String formatDate(String s)
{
String outputText=null;
try {
// Tue May 21 14:32:00 GMT 2012
String inputText =s;
SimpleDateFormat inputFormat = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm 'GMT'", Locale.US);
inputFormat.setTimeZone(TimeZone.getTimeZone("Etc/UTC"));
if(android.text.format.DateFormat.is24HourFormat(CalloutAvalibality.this))
{
SimpleDateFormat outputFormat = new SimpleDateFormat("MMM dd,yy HH:mm");
// Adjust locale and zone appropriately
Date date = inputFormat.parse(inputText);
outputText= outputFormat.format(date)+" "+"Hrs";
System.out.println(outputText);
}
else
{
SimpleDateFormat outputFormat = new SimpleDateFormat("MMM dd, yyyy hh:mm a");
// Adjust locale and zone appropriately
Date date = inputFormat.parse(inputText);
outputText= outputFormat.format(date);
// outputText=outputText.replace("AM","am");
// outputText=outputText.replace("PM","pm");
System.out.println(outputText);
}
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return outputText;
}
datefomater.format() will return you a string which is converted to timezone you initially set with the formatter object.
datefomater.parse() will return you a Date object which is in you local timezone
The Date object will set to default timezone
TimeZone timeZone = TimeZone.getTimeZone("America/Chicago");
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
formatter.setTimeZone(timeZone);
String result = formatter.format(YOUR_DATE_OBJECT);
Related
I am working on Android application in which I am saving and getting date from ORMLITE. I am using SimpleDateFormat for the formatting of the desire date, but except this pattern yyyy-MM-dd HH:mm it is not formatting it. My current date from server with desired dates with code is given below:
try {//EEEE , MMMM dd , yyyy hh:mm a
SimpleDateFormat mDBSDF = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
if(cursor.getString(cursor.getColumnIndex("mLastMessageDate"))==null){//.equals("") ||cursor.getString(cursor.getColumnIndex("mLastMessageDate")).toString()==null){
mTxtLastMessageDate.setText("");
mTxtLastMessageLabel.setText("");
}else{
mTxtLastMessageDate.setText(mDBSDF.parse(cursor.getString(cursor.getColumnIndex("mLastMessageDate"))).toString());
}
}catch(Exception ex) {
ex.printStackTrace();
}
This is my server date:
2015-04-28 12:57:04.000297
After using above format i am getting this:
Tue Apr 28 12:57:04 GMT+04:00 2015
I want the pattern like this:
Tuesday, April 28, 2015 1:00 pm
Except above yyyy-MM-dd HH:mm format even if i am changing "-" to "," it is not working without any error
SimpleDateFormat.parse(String) returns a Date not a formatted String.
Use SimpleDateFormat.format(Date) instead.
Try this to format the date and time...
DateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
Date date = new Date();
System.out.println(dateFormat.format(date));
Try this base on your requirement.
Input date as string
protected String dateFormat(String sqlDate) {
String strDate = "";
java.util.Date utilDate;
SimpleDateFormat sqlDateFormat = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss");//input format
try {
Calendar calTempDate = Calendar.getInstance();
calTempDate.setFirstDayOfWeek(Calendar.MONDAY);
utilDate = sqlDateFormat.parse(sqlDate);
calTempDate.setTime(utilDate);
strDate = new SimpleDateFormat("EEEE MMMM dd,yyyy HH:mm a")
.format(calTempDate.getTime());//output format
} catch (Exception e) {
e.printStackTrace();
}
return strDate;
}
You can use this code to find out your solution.
SimpleDateFormat fromdateformate=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try {
Date date=fromdateformate.parse("2015-04-28 12:57:04.000297");
SimpleDateFormat todtaeFormate=new SimpleDateFormat("EEEE MMMM yyyy hh:mm aa");
String finaldate= todtaeFormate.format(date);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I get a data from server like this:
data = "2015-04-24T23:00:17+08:00"
I am in UTC+8,I want get
data = "2015-04-24 23:00:17"
I program this
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
Data = formatter.parse(data);
But I get that
Fri Apr 24 23:00:17 格林尼治标准时间+0800 2015
How can I correct it?
if I use
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-M-dd HH:mm:ss",Locale.ENGLISH);
I get
Fri Apr 24 23:00:17 GMT+08:00 2015
It is not I want
You are missing a Locale.
new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.ENGLISH);
See the documentation.
Once you parse the date you returned from server, you have a java.util.Date object. If you want to convert to your own format you have to again format the date object.
private String getDate(String serverDate) {
SimpleDateFormat serverFormatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
try {
Date date = serverFormatter.parse(serverDate);
SimpleDateFormat myFormatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String formattedDate = myFormatter.format(date);
return formattedDate;
} catch (Exception e) {
e.printStackTrace();
}
return "";
}
For your desired output you need to change the date format to
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.ENGLISH);
I want to change my date format that is in as
String date ="29/07/13";
But it is showing me the error of *Unparseable date: "29/07/2013" (at offset 2)*
I want to get date in this format 29 Jul 2013.
Here is my code that i am using to change the format.
tripDate = (TextView) findViewById(R.id.tripDate);
SimpleDateFormat df = new SimpleDateFormat("MMM d, yyyy");
try {
oneWayTripDate = df.parse(date);
} catch (ParseException e) {
e.printStackTrace();
}
tripDate.setText(oneWayTripDate.toString());
Try like this:
String date ="29/07/13";
SimpleDateFormat input = new SimpleDateFormat("dd/MM/yy");
SimpleDateFormat output = new SimpleDateFormat("dd MMM yyyy");
try {
oneWayTripDate = input.parse(date); // parse input
tripDate.setText(output.format(oneWayTripDate)); // format output
} catch (ParseException e) {
e.printStackTrace();
}
It's a 2-step process: you first need to parse the existing String into a Date object. Then you need to format the Date object into a new String.
Change the format string to MM/dd/yyyy, while parse() and use dd MMM yyyy while format().
Sample :
String str ="29/07/2013";
// parse the String "29/07/2013" to a java.util.Date object
Date date = new SimpleDateFormat("dd/MM/yyyy").parse(str);
// format the java.util.Date object to the desired format
String formattedDate = new SimpleDateFormat("dd MMM yyyy").format(date);
DateFormat df = new SimpleDateFormat("dd / MM / yyyy, HH:mm");
String date = df.format(Calendar.getInstance().getTime());
I am having a date string 2012-11-21 13:11:25 which I get from local database. I have to convert this according to UTC settings and display it on a particular screen. So if its GMT+05:30 it should be displayed as 2012-11-21 18:41:25 on the screen. How can I do this conversion. I have checked some of the questions but that didn't work out.
I am able to get a Date object that returns something like Wed Nov 21 13:11:25 GMT+05:30 2012 after this I need to get the time as 18:41:25 and date as 11-21-2012
Thanks in advance
Your df and inputFmt must use the same format.
But I think you should do it like this:
Date myDate = new Date();
Calendar calendar = Calendar.getInstance();
calendar.setTimeZone(TimeZone.getTimeZone("UTC"));
calendar.setTime(myDate);
Date time = calendar.getTime();
SimpleDateFormat outputFmt = new SimpleDateFormat("MMM dd, yyy h:mm a zz");
String dateAsString = outputFmt.format(time);
System.out.println(dateAsString);
Get UTC from current time :
public String getCurrentUTC(){
Date time = Calendar.getInstance().getTime();
SimpleDateFormat outputFmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
outputFmt.setTimeZone(TimeZone.getTimeZone("UTC"));
return outputFmt.format(time);
}
Best way to get formatted string of Date in required format is
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
String formatted = dateFormat.format(date);
//This is my input date
String dtStart = "2019-04-24 01:22 PM";
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd hh:mm a");
Date date = null;
try {
date = format.parse(dtStart);
getDateInUTC(date)
} catch (ParseException e) {
e.printStackTrace();
}
//This Method use for convert Date into some UTC format
public static String getDateInUTC(Date date) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
String dateAsString = sdf.format(date);
System.out.println("UTC" + dateAsString);
return dateAsString;
}
I am trying to convert the following string in to date, I am able to convert the string into to date object successfully,But the Problem is in this string I want to convert the time in to am/pm i.e. 12 hr format, I tried different ways but unable to get the solution.
How to get the 12hr format time from this string ?
Here is my code:
SimpleDateFormat formatter = new SimpleDateFormat("EEE MMM dd hh:mm:ss zzz yyyy"); //please notice the capital M
Date date;
try {
date = formatter.parse("Fri Jul 01 10:00:00 CDT 2011");
Log.e("ThankYou Block", ""+date.toString());
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
TRY
public static String StringToDate(String dateToParse) {
Date formatter = new Date(HttpDateParser.parse(dateToParse));
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSS");
int offset = TimeZone.getDefault().getRawOffset();
formatter.setTime(formatter.getTime() + offset);
String strCustomDateTime = dateFormat.format(formatter);
return strCustomDateTime;
}