I am developing an Android application. In that i need to get the user mobile sim number for calling purposes automatically. But i am facing the problem in getting the mobile number of the user.
I have tried this.
TelephonyManager telemamanger = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
String getSimSerialNumber = telemamanger.getSimSerialNumber();
String deviceID = telemamanger.getDeviceId();
String getSimNumber = telemamanger.getLine1Number();
and this
TelephonyManager tm = (TelephonyManager) this.getSystemService(Context.TELEPHONY_SERVICE);
String network;
ConnectivityManager cm = (ConnectivityManager) this.getSystemService(Context.CONNECTIVITY_SERVICE);
if(cm.getActiveNetworkInfo().getTypeName().equals("MOBILE"))
network = "cellnetwork/4G";
else if(cm.getActiveNetworkInfo().getTypeName().equals("WIFI"))
network = "wifi";
else
network ="na";
String uphone = tm.getLine1Number();
Toast.makeText(getApplicationContext(),uphone+" "+network,Toast.LENGTH_LONG).show();
In these, i am getting all the information i want except the mobile number.
Is there any alternate method to get mobile number like in BHIM app.
In BHIM app they are getting the mobile numbers automatically(whether it is single or dual sim).
Sure!
These are some informations that you can get both on SubscriptionManager and SubscriptionInfo.
Though I'm not really sure on what permissions you need to do that on a 3rd party app. This is how I do on my company's framework:
private void fillSimNumber(TelephonyManager tm, SubscriptionInfo subscriptionInfo) {
final String rawNumber = tm.getLine1Number(subscriptionInfo.getSubscriptionId());
if (!TextUtils.isEmpty(rawNumber)) {
mSimNumber.setText(rawNumber);
}
}
Best of Luck!
Related
My code successfully sends MMS. The approach uses ConnectivityManager
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP)
{
NetworkRequest.Builder builder = new NetworkRequest.Builder();
builder.addTransportType(NetworkCapabilities.TRANSPORT_CELLULAR);
builder.addCapability(NetworkCapabilities.NET_CAPABILITY_MMS);
NetworkRequest networkRequest = builder.build();
cm.requestNetwork(networkRequest, new ConnectivityManager.NetworkCallback()
{
#Override
public void onAvailable(Network network)
{
super.onAvailable(network);
// do MMS sending here using HTTP/network APIs
cm.unregisterNetworkCallback(this);
}
});
}
In a dual SIM phone, this approach seems to pick a default SIM and send MMS out of that number (I am not sure how the default is picked).
How does one specify a SIM slot or a Subscription ID as part of the NetworkRequest? Or is there another way?
Just a reiterate this question is only about MMS, not SMS. Also, the question is not about sending MMS programmatically (that is discussed elsewhere in SO). The question is specific to dual SIM devices.
Thank you
You can get sim info by below method
//above Android API 22
if (Build.VERSION.SDK_INT > 22) {
//for dual sim mobile
SubscriptionManager localSubscriptionManager = SubscriptionManager.from(this);
if (localSubscriptionManager.getActiveSubscriptionInfoCount() > 1) {
//if there are two sims in dual sim mobile
List localList = localSubscriptionManager.getActiveSubscriptionInfoList();
SubscriptionInfo simInfo = (SubscriptionInfo) localList.get(0);
SubscriptionInfo simInfo1 = (SubscriptionInfo) localList.get(1);
final String sim1 = simInfo.getDisplayName().toString();
final String sim2 = simInfo1.getDisplayName().toString();
}else{
//if there is 1 sim in dual sim mobile
TelephonyManager tManager = (TelephonyManager) getBaseContext()
.getSystemService(Context.TELEPHONY_SERVICE);
String sim1 = tManager.getNetworkOperatorName();
}
}else{
//below android API 22
TelephonyManager tManager = (TelephonyManager) getBaseContext()
.getSystemService(Context.TELEPHONY_SERVICE);
String sim1 = tManager.getNetworkOperatorName();
}
This code is not working...It giving null...
TelephonyManager tMgr = (TelephonyManager)HomeActivity.this.getSystemService(Context.TELEPHONY_SERVICE);
String mPhoneNumber = tMgr.getLine1Number();
Log.e("Mobile No. :",""+mPhoneNumber);
Toast.makeText(getApplicationContext(),mPhoneNumber,Toast.LENGTH_SHORT).show();
Here is the code for it:
TelephonyManager telemamanger = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
String getSimSerialNumber = telemamanger.getSimSerialNumber();
String getSimNumber = telemamanger.getLine1Number();
and you also have to add "READ_PHONE_STATE" permission in Androidmanifest.xml file.
and if you are testing the app on higher OS device then you also have to ask for the permission externally.
hope this will help you. :)
Check in Phone--> Settings --> About --> Phone identity If you are able to view the number then you will get phone number otherwise won't able to get number
I got result by using of below code,
TelephonyManager telephonyMananger = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
String mobNumber = telephonyMananger.getLine1Number();
developed an app using a mobile phone
used this code to pick imei number
Utill.class
static TelephonyManager telephonyManager;
public static String getDeviceID(){
telephonyManager=(TelephonyManager) MyApplication.getInstance().getSystemService(MyApplication.getInstance().TELEPHONY_SERVICE);
return telephonyManager.getDeviceId();
}
in my job.class
String imeino = Util.getDeviceID();
tested with mobile devises and it works properly but when apk installed a tab (in client side ) imei number does not pick and give a null pointer
Note. for tab i have added different layouts and it also works properly in my tab
is this a matter of base url or
how can i avoid this issue of imei number ?
java Class and add following code
TelephonyManager tel;
TextView imei;
tel = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
imei = (TextView) findViewById(R.id.textView2);
imei.setText(tel.getDeviceId().toString());
AndroidManifest.xml and add following code
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
Have this common method. Devices without SIM slot will return null IMEI. So pick ANDROID_ID.
public String getDeviceID(){
String devcieId;
TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null){
devcieId = mTelephony.getDeviceId();
}else{
devcieId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID);
}
return devcieId;
}
Try this code it will return you IMEI number if device GSM based or if not get back the Android ID.
String devcieId;
TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null){
devcieId = mTelephony.getDeviceId();
}else{
devcieId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID);
}
Also give the read phone state permission in your manifest.
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
Is there a way that I can access the other sim in my android? I have an android Cherry Mobile Orbit which is a dual sim android phone. I want to develop an SMS application for my phone, but only the 1st sim will be access. I want to access the other sim, so that when i press enter to send the message, there will be a prompt, that which sim the message will be sent.
I know that it's propreitary, but the phone manufacturer has no feedback about it. Is there any other way? tweaking or something?
I think you can use dex2jar or apktool to reverse those app which runs on dual sim card devices, once you found the related "service manager", "telephony manager",some interface stub, or some key words like "Gemini" you can then use Java Reflection, reflects all of method of this class. Then you can achieve this goal.
This method can be used to select one SIM from 2 SIMs!
//above Android API 22
if (Build.VERSION.SDK_INT > 22) {
//for dual sim mobile
SubscriptionManager localSubscriptionManager = SubscriptionManager.from(this);
if (localSubscriptionManager.getActiveSubscriptionInfoCount() > 1) {
//if there are two sims in dual sim mobile
List localList = localSubscriptionManager.getActiveSubscriptionInfoList();
SubscriptionInfo simInfo = (SubscriptionInfo) localList.get(0);
SubscriptionInfo simInfo1 = (SubscriptionInfo) localList.get(1);
final String sim1 = simInfo.getDisplayName().toString();
final String sim2 = simInfo1.getDisplayName().toString();
}else{
//if there is 1 sim in dual sim mobile
TelephonyManager tManager = (TelephonyManager) getBaseContext()
.getSystemService(Context.TELEPHONY_SERVICE);
String sim1 = tManager.getNetworkOperatorName();
}
}else{
//below android API 22
TelephonyManager tManager = (TelephonyManager) getBaseContext()
.getSystemService(Context.TELEPHONY_SERVICE);
String sim1 = tManager.getNetworkOperatorName();
}
Then to send an SMS you can use the below method
public static boolean sendSMS(Context context, String smsText) {
SmsManager smsMan = SmsManager.getDefault();
SharedPreferences prefs = context.getSharedPreferences("uinfo", MODE_PRIVATE);
String sim = prefs.getString("sim", "No name defined");
String simName = prefs.getString("simName", "No name defined");
String toNum = "";
try {
if (Build.VERSION.SDK_INT > 22) {
SubscriptionManager localSubscriptionManager = SubscriptionManager.from(context);
if (localSubscriptionManager.getActiveSubscriptionInfoCount() > 1) {
int simID = Integer.parseInt(sim);
List localList = localSubscriptionManager.getActiveSubscriptionInfoList();
SubscriptionInfo simInfo = (SubscriptionInfo) localList.get(simID);
ArrayList<String> parts = smsMan.divideMessage(smsText);
SmsManager.getSmsManagerForSubscriptionId(simInfo.getSubscriptionId()).sendMultipartTextMessage(toNum, null, parts, null, null);
}else{
ArrayList<String> parts = smsMan.divideMessage(smsText);
smsMan.sendMultipartTextMessage(toNum, null, parts, null, null);
}
return true;
}else{
ArrayList<String> parts = smsMan.divideMessage(smsText);
smsMan.sendMultipartTextMessage(toNum, null, parts, null, null);
}
} catch (Exception e) {
}
return false;
}
Officially right now there is no API to support this, you have to contact the device manufacturer.
Assuming that you are developing the app for your own phone, and you are willing to go through the trouble of finding out the IDs (sim_id) assigned to each of your SIM cards (probably via checking the phone's log outputs, searching for sim_id, which was what I did), you can use the following code to set the default SIM for SMS sending:
int simId = <place desired SIM ID here>;
Intent simIntent = new Intent("android.intent.action.SMS_DEFAULT_SIM");
simIntent.putExtra("simid", simId);
sendBroadcast(simIntent);
Combined with some other UI prompt stuff (for actually 'picking' the preferred SIM), this should do the trick.
I'm not at all sure if this approach would work for you (although the code seems quite 'standard'); I figured it out with trial and error on my Mlais MX28 (with a customized ROM). But it's still worth a shot, I suppose. :)
UPDATE:
Strangely, the solution stopped working unexpectedly after a few updates to the app I was working on. But I came across another way (which seems to be more promising). (I believe this can be extended for other SIM selection scenarios as well, as the settings cache contains entries with names gprs_connection_sim_setting, voice_call_sim_setting, video_call_sim_setting and the like.)
ContentValues val = new ContentValues();
val.put("value", "here goes the preferred SIM ID");
getContentResolver().update(Uri.parse("content://settings/system"), val, "name='sms_sim_setting'", null);
(Unfortunately, this requires the android.permission.WRITE_SETTINGS permission.)
I want to get the device id that will be unique for each Android device. I am presently developing for a Tablet device. Want to get unique device id and store the corresponding values...
So, i want to know whether Tablet devices will return a value if i use TelephonyManager.getDeviceId()...???Or is there any other value that is unique for each device???
TelephonyManger.getDeviceId() Returns the unique device ID, for example, the IMEI for GSM and the MEID or ESN for CDMA phones.
final TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
String myAndroidDeviceId = mTelephony.getDeviceId();
But i recommend to use:
Settings.Secure.ANDROID_ID that returns the Android ID as an unique 64-bit hex string.
String myAndroidDeviceId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID);
Sometimes TelephonyManger.getDeviceId() will return null, so to assure an unique id you will use this method:
public String getUniqueID(){
String myAndroidDeviceId = "";
TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null){
myAndroidDeviceId = mTelephony.getDeviceId();
}else{
myAndroidDeviceId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID);
}
return myAndroidDeviceId;
}
This is not a duplicate question. As it turns out, Google's CTS require that getPhoneType of TelephonyManager needs to be none and getDeviceId of TelephonyManager needs to be null for non-phone devices.
So to get IMEI, please try to use:
String imei = SystemProperties.get("ro.gsm.imei")
Unfortunately, SystemProperties is a non-public class in the Android OS, which means it isn't publicly available to regular applications. Try looking at this post for help accessing it: Where is android.os.SystemProperties
Since Android 8 everything's changed. You should use Build.getSerial(), to get the serial number of the device and add the permission READ_PHONE_STATE.
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
serial = Build.getSerial(); // Requires permission READ_PHONE_STATE
} else {
serial = Build.SERIAL; // Will return 'unknown' for device >= Build.VERSION_CODES.O
}
And get the IMEI or MEID this way:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
String imei = tm.getImei(); // Requires permission READ_PHONE_STATE
serial = imei == null ? tm.getMeid() : imei; // Requires permission READ_PHONE_STATE
} else {
serial = tm.getDeviceId(); // Requires permission READ_PHONE_STATE
}