OpenGL screenshot taking too much time on android? - android

I am using OpenGL render method to capture screenshot.but take it takes 7 to 8 seconds on NEXUS 7 to read pixel information. I am using this code to read pixel information and save it as Bitmap.
public Bitmap grabPixels(GL10 mGL) {
final int mWidth = mViewWidth;
final int mHeight = mViewHeight;
IntBuffer ib = IntBuffer.allocate(mWidth * mHeight);
IntBuffer ibt = IntBuffer.allocate(mWidth * mHeight);
mGL.glReadPixels(0, 0, mWidth, mHeight, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, ib);
for (int i = 0; i < mHeight; i++) {
for (int j = 0; j < mWidth; j++) {
ibt.put((mHeight - i - 1) * mWidth + j, ib.get(i * mWidth + j));
}
}
Bitmap mBitmap = Bitmap.createBitmap(mWidth, mHeight, Bitmap.Config.ARGB_8888);
mBitmap.copyPixelsFromBuffer(ibt);
return mBitmap;
}
How can i increase speed of reading the pixel information and convert it into the Bitmap ?

I wrote another answer about saving GIFs on gamedev, which might be useful.
You can't call glReadPixels() on another thread. But it's most likely (as you said) the process of saving the image that takes the majority of time. As such the solution is to do the saving on a separate thread.
new Thread(new Runnable() {
#Override
public void run() {
... save screenshot ...
}
}).start();
Before anybody comes at me with pitchforks. Then yes you can call glReadPixels() on another thread. It however requires a shared context, which can be specified when calling eglCreateContext().
EGLContext shared = ...
EGLDisplay display = ...
EGLConfig eglConfig = ...
int[] attrib_list = { EGL_CONTEXT_CLIENT_VERSION, 2, EGL10.EGL_NONE };
EGLContext context = egl.eglCreateContext(display, eglConfig, shared, attrib_list);
But before you start digging into shared contexts (which can be a pain in themselves) then make sure your bottleneck isn't the saving the image, which it most likely is.

Related

Android Low image quality / altered image when using glReadPixels

I've spend a lot of time trying to figure this out but can't see what I am doing wrong.
This is my original image
Image recaptured 5 times
Recapturing the image multiple times clearly shows that there is something not right. Capturing it once is just ok but twice is enough to clearly see the difference.
I found these similar issues on stackoverflow:
Bitmap quality using glReadPixels with frame buffer objects
Extract pixels from TextureSurface using glReadPixels resulting in bad image Bitmap
(sorry limited to links I can add)
Unfortunately none of the proposed suggestions/solutions fixed my issue.
This is my code:
private Bitmap createSnapshot (int x, int y, int w, int h) {
int bitmapBuffer[] = new int[w * h];
int bitmapSource[] = new int[w * h];
IntBuffer intBuffer = IntBuffer.wrap(bitmapBuffer);
intBuffer.position(0);
try {
glReadPixels(x, y, w, h, GL_RGBA, GL_UNSIGNED_BYTE, intBuffer);
int offset1, offset2;
for (int i = 0; i < h; i++) {
offset1 = i * w;
offset2 = (h - i - 1) * w;
for (int j = 0; j < w; j++) {
int texturePixel = bitmapBuffer[offset1 + j];
int blue = (texturePixel >> 16) & 0xff;
int red = (texturePixel << 16) & 0x00ff0000;
int pixel = (texturePixel & 0xff00ff00) | red | blue;
bitmapSource[offset2 + j] = pixel;
}
}
} catch (GLException e) {
return null;
}
return Bitmap.createBitmap(bitmapSource, w, h, Bitmap.Config.ARGB_8888);
}
I'm using OpenGL 2. For bitmap compression I am using PNG. Tested it using JPEG (quality 100) and the result is the same but slightly worse.
There is also a slight yellowish tint added to the image.

Android GLSurfaceView Saving bitmap causes exception

I've modified this project, which uses GLSurfaceView and Effects to show a ViewPager with some of the effects applied to an image.
Additionally, I created a overlay bitmap, that is put over every image after the effect has been applied.
Up this point, the app is working fine. But now I have to save the displayed image in a file, when a button is pressed.
So i used this code:
private Bitmap createBitmapFromGLSurface(int x, int y, int w, int h, GL10 gl)
throws OutOfMemoryError {
int bitmapBuffer[] = new int[w * h];
int bitmapSource[] = new int[w * h];
IntBuffer intBuffer = IntBuffer.wrap(bitmapBuffer);
intBuffer.position(0);
try {
gl.glReadPixels(x, y, w, h, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, intBuffer);
int offset1, offset2;
for (int i = 0; i < h; i++) {
offset1 = i * w;
offset2 = (h - i - 1) * w;
for (int j = 0; j < w; j++) {
int texturePixel = bitmapBuffer[offset1 + j];
int blue = (texturePixel >> 16) & 0xff;
int red = (texturePixel << 16) & 0x00ff0000;
int pixel = (texturePixel & 0xff00ff00) | red | blue;
bitmapSource[offset2 + j] = pixel;
}
}
} catch (GLException e) {
e.printStackTrace();
return null;
}
return Bitmap.createBitmap(bitmapSource, w, h, Bitmap.Config.ARGB_8888);
}
to obtain a Bitmap. When the button is pressed, I call this method:
protected void onClick() {
read = true;
mEffectView.requestRender();
}
Which forces the rendering, so I generate the bitmap and save it on a file using an AsyncTask.
read is used as a semphore in onDrawFrame(GL10 gl) to generate only the bitmap when I want to save it.
Saving one image works fine. When I save a second one, then I change page, this error comes up:
A/Bitmap: Failed to acquire strong reference to pixels
A/libc: Fatal signal 6 (SIGABRT), code -6 in tid 20475 (GLThread 9540)
Another issue is that the overlay, though is displayed, is not saved in the image.
This is how I apply it:
Generation
EffectFactory effectFactory = mEffectContext.getFactory();
overlayEffect = effectFactory.createEffect(EffectFactory.EFFECT_BITMAPOVERLAY);
overlayEffect.setParameter("bitmap", overlay);
Effect applying
mEffect.apply(mTextures[0], mImageWidth, mImageHeight, mTextures[1]);
overlayEffect.apply(mTextures[1], mImageWidth, mImageHeight, mTextures[2]);
With mEffect is the only effect visible when saving the image.
What I'm doing wrong?
EDIT
I solved the last problem: I find out that you have to release and recreate every Effect object you are using every time is called mEffectView.requestRender().
Apparently, when using
overlayEffect = effectFactory.createEffect(EffectFactory.EFFECT_BITMAPOVERLAY);
overlayEffect.setParameter("bitmap", overlay);
the passed bitmap is recycled!
So I solved the issue passing a copy of it:
overlayEffect = effectFactory.createEffect(EffectFactory.EFFECT_BITMAPOVERLAY);
overlayEffect.setParameter("bitmap", overlay.copy(overlay.getConfig(), false));
Hope this will help somebody else!

Android 4.3 PBO not working

I am using PBO to take screenshot. However, the result image is all black. It works perfectly fine without PBO. Is there any thing that I need to take care before doing this ?
I even tried by rendering to a FBO and then use GLES30.glReadBuffer(GLES30.GL_COLOR_ATTACHMENT0), no hope
public void SetupPBO(){
GLES30.glGenBuffers(1, pbuffers, 0);
GLES30.glBindBuffer(GLES30.GL_PIXEL_PACK_BUFFER, pbuffers[0]);
int size = (int)this.mScreenHeight * (int)this.mScreenWidth * 4;
GLES30.glBufferData(GLES30.GL_PIXEL_PACK_BUFFER, size, null, GLES30.GL_DYNAMIC_READ);
checkGlError("glReadBuffer");
GLES30.glBindBuffer(GLES30.GL_PIXEL_PACK_BUFFER, 0);
}
private void Render(float[] m) {
.......//Normal render logic
exportBitmap();
}
private void exportBitmap() {
int screenshotSize = (int)this.mScreenWidth * (int)this.mScreenHeight;
ByteBuffer bb = ByteBuffer.allocateDirect(screenshotSize * 4);
bb.order(ByteOrder.nativeOrder());
// set the target framebuffer to read
GLES30.glReadBuffer(GLES30.GL_FRONT);
checkGlError("glReadBuffer");
GLES30.glBindBuffer(GLES30.GL_PIXEL_PACK_BUFFER, pbuffers[0]);
GLES30.glReadPixels(0, 0, (int)mScreenWidth, (int)mScreenHeight, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, bb); //<------ not working ?????
int pixelsBuffer[] = new int[screenshotSize];
bb.asIntBuffer().get(pixelsBuffer);
bb = null;
for (int i = 0; i < screenshotSize; ++i) {
// The alpha and green channels' positions are preserved while the
// red and blue are swapped
pixelsBuffer[i] = ((pixelsBuffer[i] & 0xff00ff00))
| ((pixelsBuffer[i] & 0x000000ff) << 16)
| ((pixelsBuffer[i] & 0x00ff0000) >> 16);
}
Bitmap bitmap = Bitmap.createBitmap((int)mScreenWidth, (int)mScreenHeight, Bitmap.Config.ARGB_8888);
bitmap.setPixels(pixelsBuffer, screenshotSize - (int)mScreenWidth, -(int)mScreenWidth, 0, 0, (int)mScreenWidth, (int)mScreenHeight);
SaveBitmap(bitmap);
}
GLES30.glReadPixels(0, 0, (int)mScreenWidth, (int)mScreenHeight, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, bb);
bb is interpret as an offset in your PBO. Thus you're writing out of buffer (On some drivers this code cause crash). You should pass 0 instead of bb. To retrive the data from PBO use glMapBuffer.

How can I make this Bitmap gamma function in Android run faster?

I have written the following function to change the gamma of a Bitmap, but it's kind of slow, even on small (300 by 300) bitmaps. How can I make this function run faster? For example, is there a better way (i.e., faster way) to access individual pixel values from a Bitmap?
public Bitmap apply(Bitmap bmp, float gamma) {
if (bmp == null)
return null;
int width = bmp.getWidth();
int height = bmp.getHeight();
int[] pixels = new int[width * height];
bmp.getPixels(pixels, 0, width, 0, 0, width, height);
int[] powers = new int[256];
for (int i = 0; i < powers.length; i++)
powers[i] = (int)(Math.pow(i / 255.0f, 1.0f / gamma) * 255);
for (int p = 0; p < pixels.length; p++) {
int r = Color.red(pixels[p]);
int g = Color.green(pixels[p]);
int b = Color.blue(pixels[p]);
int newR = powers[r];
int newG = powers[g];
int newB = powers[b];
pixels[p] = Color.rgb(newR, newG, newB);
}
Bitmap newBmp = Bitmap.createBitmap(pixels, 0, width, width, height, Config.ARGB_8888);
return newBmp;
}
As an optimization, I calculate the powers ahead of time on all possible pixel values (0 to 255), which helps, but it's not enough. Also, declaring all the int's outside of the second for loop didn't help much, so I left them in. Thanks in advance.
I would look into using OpenGL or RenderScript for that if you really want it to be fast. Both have nice integration on Android.

Taking screenshot of Android OpenGL

I'm trying to take a screenshot of Android OpenGL.
The code I found is as follows:
nt size = width * height;
ByteBuffer buf = ByteBuffer.allocateDirect(size * 4);
buf.order(ByteOrder.nativeOrder());
glContext.glReadPixels(0, 0, width, height, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, buf);
int data[] = new int[size];
buf.asIntBuffer().get(data);
buf = null;
Bitmap bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.RGB_565);
bitmap.setPixels(data, size-width, -width, 0, 0, width, height);
data = null;
short sdata[] = new short[size];
ShortBuffer sbuf = ShortBuffer.wrap(sdata);
bitmap.copyPixelsToBuffer(sbuf);
for (int i = 0; i < size; ++i) {
//BGR-565 to RGB-565
short v = sdata[i];
sdata[i] = (short) (((v&0x1f) << 11) | (v&0x7e0) | ((v&0xf800) >> 11));
}
sbuf.rewind();
bitmap.copyPixelsFromBuffer(sbuf);
try {
FileOutputStream fos = new FileOutputStream("/sdcard/screeshot.png");
bitmap.compress(Bitmap.CompressFormat.PNG, 100, fos);
fos.flush();
fos.close();
} catch (Exception e) {
// handle
}
I tried also a code from that site
link text
In each case the result is a png file which is completely black.
I found there is some problem with glReadPixels method but I don't know how to bypass it.
Sorry for the late response...
In order to perform a correct screenshot You have to put into Your onDrawFrame(GL10 gl) handler the following code:
if(screenshot){
int screenshotSize = width * height;
ByteBuffer bb = ByteBuffer.allocateDirect(screenshotSize * 4);
bb.order(ByteOrder.nativeOrder());
gl.glReadPixels(0, 0, width, height, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, bb);
int pixelsBuffer[] = new int[screenshotSize];
bb.asIntBuffer().get(pixelsBuffer);
bb = null;
Bitmap bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.RGB_565);
bitmap.setPixels(pixelsBuffer, screenshotSize-width, -width, 0, 0, width, height);
pixelsBuffer = null;
short sBuffer[] = new short[screenshotSize];
ShortBuffer sb = ShortBuffer.wrap(sBuffer);
bitmap.copyPixelsToBuffer(sb);
//Making created bitmap (from OpenGL points) compatible with Android bitmap
for (int i = 0; i < screenshotSize; ++i) {
short v = sBuffer[i];
sBuffer[i] = (short) (((v&0x1f) << 11) | (v&0x7e0) | ((v&0xf800) >> 11));
}
sb.rewind();
bitmap.copyPixelsFromBuffer(sb);
lastScreenshot = bitmap;
screenshot = false;
}
The "screenshot" class field is set to true whenever the user presses the button to create a screenshot
or at any other circumstances You want. Inside the "if" body You may place any screenshot creating code sample You find in th internet - the most important thing is having the current instance of GL10. For example when You just save the GL10 instance to the class variable and then use it outside the event to create the screenshot You'll end up with the completely blank image. That's why You have to take a screenshot inside the OnDrawFrame event handler where the GL10 instance is the current one.
Hope that it helps.
Best regards, Gordon.
Here is the way to do it if you want to preserve the quality (8 bits for every colour channel: red, green, blue and alpha too):
if (this.screenshot) {
int screenshotSize = this.width * this.height;
ByteBuffer bb = ByteBuffer.allocateDirect(screenshotSize * 4);
bb.order(ByteOrder.nativeOrder());
gl.glReadPixels(0, 0, width, height, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, bb);
int pixelsBuffer[] = new int[screenshotSize];
bb.asIntBuffer().get(pixelsBuffer);
bb = null;
for (int i = 0; i < screenshotSize; ++i) {
// The alpha and green channels' positions are preserved while the red and blue are swapped
pixelsBuffer[i] = ((pixelsBuffer[i] & 0xff00ff00)) | ((pixelsBuffer[i] & 0x000000ff) << 16) | ((pixelsBuffer[i] & 0x00ff0000) >> 16);
}
Bitmap bitmap = Bitmap.createBitmap(width, height, Bitmap.Config.ARGB_8888);
bitmap.setPixels(pixelsBuffer, screenshotSize-width, -width, 0, 0, width, height);
this.screenshot = false;
}
Got it!
My mistake was that I was remembering GL context in the class variable. In order to take a screenshot I have to use the gl context passed to the OnDraw in the class implementing GLSurfaceView.Renderer interface. I simply use my code in the "if" clause and everything works as expected. Hope that remark would help anyone.
Best regards,
Gordon

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