I need to implement a function where if the Package name of the App is changed, the App will stop i.e. this.finish();
But it isn't working, here is the code I am Using -
public void chk(){
String ucci = getApplicationContext().getPackageName();
if (ucci!=("my.package.name"))
{
//do nothing
}
else {
this.finish();
Toast.makeText(this, "Name Changed", Toast.LENGTH_LONG)
.show();
}
}
& then I use it in onCreate like this.chk(); but doesn't work
Logically if package name is equal to "my.package.name" then finish() called otherwise nothing happen.
Please use !ucci.equals("my.package.name") instead of !=.
== and != work on object identity. While the two Strings have the same value, they are actually two different objects.
Related
I am working with FireBase Notifications and I can send a notification which will send the user to the webview page I input on the console.
The problem is that when it matches the IF statement is fires the else statement too, what could be the cause of this?
if(getIntent().getExtras()!=null) {
for (String key : getIntent().getExtras().keySet()) {
if (key.equals("url")){
mwebView.loadUrl("http://example.com/" + getIntent().getExtras().getString(key));
}else {
mwebView.loadUrl("http://example.com");
}
}
}
Because it executes both at the same time the app crashes.
Also when I load the app the usual way it matches the with:
if(getIntent().getExtras()!=null)
and then loads the else statement. Shouldnt getExtras be null?
When I first install a new instance of the app it uses the following statement:
if(getIntent().getExtras()==null) {
if (haveNetworkConnection()) {
mwebView.loadUrl("http://example.com");
} else {
mwebView.loadUrl("file:///android_asset/myerrorpage.html");
}
}
Update:
As I cannot find out why this it happening I am trying another approach, How would I get the variable outside of the loop to use like the following:
if(getIntent().getExtras()!=null) {
for (String key : getIntent().getExtras().keySet()) {
String valuex = getIntent().getExtras().getString(key);
}
}
if (haveNetworkConnection()) {
mwebView.loadUrl("http://example.com/" + valuex);
} else {
mwebView.loadUrl("file:///android_asset/myerrorpage.html");
}
If and Else can not both be executed in one go.
You should check your other code and ensure, that this code section is not executed twice for some reason (once with TRUE and once with FALSE).
In my android app I want to change the input method. So I start a new Activity which shows the language settings in the device. Then user can change it. However then I want to know that if the user has changed it. So I wrote a function for that also. My code so far is...
Intent enableIME = new Intent(android.provider.Settings.ACTION_INPUT_METHOD_SETTINGS);
startActivityForResult(enableIME,0);
if(isInputMethodEnabled()){
activateshadow.setBackgroundDrawable(getResources().getDrawable(R.drawable.button_pressed));
activateshadow.setText("Deactivate Shadow");
prefs.edit().putBoolean("Activate", false).commit();
}else{
Toast.makeText(MainActivity.this,"You haven't change the input method to simpleIME.In order to activate you must change it.",Toast.LENGTH_SHORT).show();
}
my is inputMethodEnabled function is....
public boolean isInputMethodEnabled() {
boolean isIME ;
String id = Settings.Secure.getString(getApplicationContext().getContentResolver(), Settings.Secure.DEFAULT_INPUT_METHOD);
String [] name = id.split("/.");
// Toast.makeText(MainActivity.this,"s:"+name[1]+":s",Toast.LENGTH_SHORT).show();
if(name[1].contains("SimpleIME") ){
isIME = true ;
}else{
isIME = false;
}
// Toast.makeText(MainActivity.this,"Returning..."+isIME,Toast.LENGTH_SHORT).show();
return isIME;
}
if(isInputMethodEnabled()) always fails because when the new intent(settings) opens and it take some time to change the input method to simpleIME . How to fix this problem?
You catch when a launched Activity returns in onActivityResult. The requestCode you supplied to startActivityForResult will be a parameter, as will the Activity's result. The Activity may also set other data which you didn't ask about.
public void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 555) {//555 is the intent ID you gave in startActivityForResult(enableIME,555);
if (resultCode == /*Result1*/)
//Do something
else {
//Do something else
}
}
}
You need a unique id when calling startActivityForResult(enableIME,0);
startActivityForResult(enableIME, 555);
Better still replace 555 with a named variable.
if u look at android life cycle, when activity is finished whole android call onDestroy() method.
so u can call and override this method.
just need write:
#override
protected void onDestroy(){
// code
super.onDestroy();
}
u can manage and override all of life cycle's parts in android
e.g: onResume to get current activity
i hope this help u
Scenario: when the focus is lost from an EditText, I'm checking if it contains null (in the first if block).
If so, then I'll show a Toast.
In the else-if block I'm checking if the EditText doesn't contain letters.
Then I'll show a toast, but when I run the application, the Toast is shown even on a correct input.
I.e.: If I enter any letter the Toast should not be shown, it should be shown only when a null or digit/special symbol is entered.
Here is the code
et1.setOnFocusChangeListener(new View.OnFocusChangeListener() {
#Override
public void onFocusChange(View v, boolean hasFocus) {
// TODO Auto-generated method stub
if(!hasFocus)
{
a = et1.getText().toString();
if (a.equals(""))
{
Toast.makeText(getApplicationContext(), "Your entry is incorrect!!", Toast.LENGTH_LONG).show();
}
else if (!a.contains("[a-z]")||!a.contains("[A-Z]")) {
Toast.makeText(getApplicationContext(), "Your entry is incorrect!!", Toast.LENGTH_LONG).show();
}
else
{
}
Please help
The '==' operator only compares references. To compare string values you must use the equals() method.
Instead of
if (a == "")
use
if (a.equals(""))
See: What is the difference between == vs equals() in Java?
It's not working because:
if (a == "")
won't work in Java
Use
if (a.equals(""))
instead
Also, String.contains doesn't use regular expressions, but CharacterSequences.
So, unless your string doesn't contain the exact character sequences "[a-z]" or "[A-Z]" (and only one of these 2 strings), you'll never get a match.
See: http://developer.android.com/reference/java/lang/String.html#contains(java.lang.CharSequence)
The problem is:
if (a == "")
Strings can't be compared like this. Instead, check for size equal to 0, or against a specific string with the equals() method.
Previously i am using if else condition for checking the edit text field its working but i need to change into switch case.I am not getting to implement switch case inside my code.please tell me how to implement that in switch case.
btnSave.setOnClickListener(new View.OnClickListener() {
public void onClick(View v)
{
/**
* Validation
*/
if(tvStartLocation.getText().toString().equalsIgnoreCase(""))
{
Toast.makeText(getActivity(),"Please enter start location", Toast.LENGTH_SHORT).show();
}
else if(tvEndLocation.getText().toString().equalsIgnoreCase(""))
{
Toast.makeText(getActivity(),"Please enter end location", Toast.LENGTH_SHORT).show();
}
else if(etStartOdometer.getText().toString().equalsIgnoreCase(""))
{
Toast.makeText(getActivity(),"Please enter Trip Start Odometer reading", Toast.LENGTH_SHORT).show();
}
else
{
gotonextfraggment();
}
You cannot use a switch-case construct in your case. In a switch-case, only one argument is matched with the case labels and if there is a match, that label is executed.
switch(arg) {
case "label1":
case "label2":
.
.
.
default:
}
arg is tested with label1, label2 and so on.
In your case, in every else-if, you are trying to test the equality of the text in different EditTexts with "". So your arg changes in every else-if. Even if you try to implement switch-case, the arg of your switch-case will change continuously and you'll not be able to go any further. You cannot even do this:
switch("") {
case edittext1.getText():
case edittext2.getText();
.
.
.
default:
}
Because the case labels must be literals not variable values.
So it is impossible to implement switch-case for the problem that you are facing
In fact what you've done right now is the perfect way to do it.
I have an Android app which I use to register users on my web site. My first task is to register a user if my shared preferences file shows there is no registered user information.
If my app has a registered user, I provide the following code to simply and automatically switch to a "homepage" activity:
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.signin);
if( USERPREFERENCES.getString(USERPREFERENCES_USERMAIL, "") == null && USERPREFERENCES.getString(USERPREFERENCES_USERID, "") == null && USERPREFERENCES.getString(USERPREFERENCES_USERNAME, "") == null){
//setContentView(R.layout.signin);
Toast.makeText(SignIn.this, "testing...", Toast.LENGTH_LONG).show();
}else{
Intent intent = new Intent(SignIn.this, Confirmed.class);
startActivity(intent);
}
... other code
So, from my default activity, signin.java, the app will either switch to the Confirmed activity or stay on and display the signin activity.
My problem is, when the system works and I get switched to the the Confirmed activity, I provide a logout onclick listener which is below:
signout.setOnClickListener(new OnClickListener() {
#Override
public void onClick(View v) {
// TODO Auto-generated method stub
//USERPREFERENCES.cl
Toast.makeText(Confirmed.this, "signout responding!", Toast.LENGTH_LONG).show();
USERPREFERENCES.edit().clear().commit();
}
});
It responds and clears all my shared preferences variables. But, when I use my menu to manually switch to the sign-in activity, I still get switched back to the Confirmed activity.
This happens even though I can confirm the variables are empty.
This hardly ever will be true:
USERPREFERENCES.getString(USERPREFERENCES_USERMAIL, "") == null
What if you use this instead?
if( USERPREFERENCES.getString(USERPREFERENCES_USERMAIL, null) == null && USERPREFERENCES.getString(USERPREFERENCES_USERID, null) == null && USERPREFERENCES.getString(USERPREFERENCES_USERNAME, null) == null){
//setContentView(R.layout.signin); TRY TO AVOID DOING THIS THING!!!!!
Toast.makeText(SignIn.this, "testing...", Toast.LENGTH_LONG).show();
}else...
Also, as a recommendation... instead of being switching between activities... what if you create just a Signing.java activity and put a ViewFlipper in its layout. That way your app will be not only faster but also easier to maintain.
This is Because When you will switch back to LoginActivity, this will be resumed instead of being created , Means your Login code which you written inOnCreate will not be called because Dthis time Overrider OnResume has been called , not onCreate .
So either write this code again in onResume or call finish() before moving to second activity , so that next time it will call onCreate()
If you navigate back to the first activity, the onCreate is not called again (unless the activity was destroyed for lack of resources). Move the authentication code in onResume.