How to access Firebase Database node using contains() method? - android

I am working on an app using Firebase Database. In my Firebase Database I have a node like xxxxxx_yyyyyy, where xxxxxx represents first user ID and yyyyyy represents second user ID. Now I want to retrieve only nodes which contains xxxxxx_ from my database. I don't know how to do this. Because all I know is Firebase gives only equalsTo() method.

There is no query like contain(). I recommend to change node structure (locating yyyyy under xxxxx).

There Is no Query Like Contains in Fire base.!
if you dnt want to change structure of your node you can Store Data in list and then simply use list.contains() you will get your desired Result.!
HtBVbQP0qMSrCStroYsIiMSuhMC3 //node userID
Name:XXXXXXX
You can get this Data by using orderbychild(XXXXXX);

There is no contain() method, however, you can solve this problem in two ways:
Using the split() method from String class.
Using Regex Pattern
Here is the code:
String firebaseField = "xxxxxx_yyyyyy";
String[] data = firebaseField.split("_");
System.out.print("Using split method: ");
for(String part : data) {
if (part.equals("xxxxxx")) {
System.out.print(part + " ");
//Add your logic
}
}
Or
System.out.print("\nUsing Regex Pattern: ");
Pattern datePattern = Pattern.compile("_");
data = datePattern.split(firebaseField);
for(String part : data) {
if (part.equals("xxxxxx")) {
System.out.print(part + " ");
//Add your logic
}
}
Hope it helps.

Related

How can i populate a string value to a realtime firebase database with out creating a child nodes from android?

I wanted to add a string values to a realtime firebase database with the firebase UID being the name and the string being the value. When I use the below code it makes the UID a parent node and set the value to a child node.
ReferralCode referralCode = new ReferralCode(refCode); databaseReference.child("referralCodes").child(userId).setValue(referralCode);
I wanted the values to be populated as the second one. But with the above code,i get the first result. I'm going to search for the referral codes afterwards,so i think it would be faster if the values are populated as the second one to avoid accessing a child node which will be time consuming for large database entities.
When you are using a Model like you created ReferralCode and using it to with .setValue(referralCode) then Firebase will automatically create it as the child with attributes your ReferralCode.java has. Example below:
public class Restaurant {
private int code;
private int type;
private String name;
}
So if I create a variable Restaurant tempRest = new Restaurant(111, "Restoran DM", 0) and use it like this:
database.child("restaurants").child("1st restaurant").setValue(tempRest);
Firebase will create something like this:
restaurants
1st restaurant:
code: 111
name: "Restoran DM"
type: 0
But if you use String in setValue() like this:
String someValue = "some value";
database.child("restaurants").child("awpjawpdaw").setValue(someValue);
it will give you what you want. Example, I used this:
DatabaseReference database = FirebaseDatabase.getInstance().getReference();
String refCode = "1231231";
database.child("restaurants").child("wadawdapwodawp").setValue(refCode);
and here is what happened in database:

add/overwrite field of type array in Firestore

I want to add a field of type array inside a collection.
if the field doesn't exist create it. if it exists overwrite it with the new array value.
the field should be called macAddress and it's of type array of String
I have tried the following:
val macInput = setting_mac_text.text.toString()
val macArray = macInput.split(",")
val macList = Arrays.asList(macArray)
val data =
hashMapOf(Pair(FirebaseConstants.USER_MAC_ADDRESS, macArray))
//save it in firebase
db.collection(FirebaseConstants.ORGANIZATION)
.document(orgID + ".${FirebaseConstants.USER_MAC_ADDRESS}")
.set(FieldValue.arrayUnion(macList))
.addOnCompleteListener { task ->
if (task.isSuccessful) {
Log.d(TAG, "successfully inserted")
} else {
Log.d(TAG, " failed ${task.exception}")
}
}
also tried to insert the list itself and hash map like this
val data = hashMapOf(Pair(FirebaseConstants.USER_MAC_ADDRESS, macArray))
db.collection(FirebaseConstants.ORGANIZATION)
.document(orgID)
.set(data))
but it keeps giving me java.lang.IllegalArgumentException: Invalid data. Nested arrays are not supported
what am I doing wrong here?
You're doing three things wrong here:
FieldValue.arrayUnion() is only meant to be used as the value of a field to add elements to that field. The way you are using it now in the first sample, it's being taken as the entire contents of the document.
set() with one parameter is only intended to create or overwrite an entire document. It can't be used to update an existing document. You would have to pass in SetOptions to tell it to merge if you want an update. Or, you would simply use update() to modify an existing document.
Your code that deals with macArray and macList isn't working the way you expect. You are creating a list with one element, which is itself an array. The error message is telling you that you can't have nested arrays like this.
I suggest taking a step back and simplifying your code, removing all the moving parts that don't have to do with Firestore. Just hard code values in your Firestore update until the update works the way you want, then add in the code that works with actual values. Get one simple thing to work, then add to it. If you get an error, you will know that the code you just added was incorrect.
To overwrite an array, you would simply call the set method and have the merge option set to true:
try {
const query = await DatabaseService.queryBuilder({
collection: CollectionName,
});
return await query
.doc(insuranceId)
.set(
{ DOCUMENT_PROPERTY_HERE: ARRAY_HERE },
{ merge: true }
);
} catch (exception) {
return Promise.reject(exception);
}

Can't convert object of type java.lang.String to type com.thesis.joinerapp.Model.Joins

So i want to query my Firebase Database base on the value that i get from other activity.
private String tripID = "";
tripID = getActivity().getIntent().getStringExtra("tripID");
JoinRef = FirebaseDatabase.getInstance().getReference().child("Join").child(tripID);
FirebaseRecyclerOptions<Joins> options = new FirebaseRecyclerOptions.Builder<Joins>().setQuery(JoinRef,Joins.class).build();
Database Structure:
But it shows an exception
com.google.firebase.database.DatabaseException: Can't convert object
of type java.lang.String to type com.thesis.joinerapp.Model.Joins
While FirebaseUI can perform look ups of data for you, your data has to be in a very specific format for that.
If you want to show a subset of the number of trips, the index has to look like this:
"myTrips": {
"tripID1": true,
"tripID2": true
}
Where tripID1 and tripID2 are the -L keys that you have under /Trip.
You can find another example of this data in the FirebaseUI documentation on showing indexed data.
when you want to use the FirebaseUi, your database structure should be like this.
{
"Join" : {
"tripID" : {
"pushUid" : {
"joinID" : "yourJoinID",
"personCount" : "1",
"tripID" : "yourTrioID",
"uid" : "yourUid"
}
}
}
}
You need to add new root child which is pushId.

Firestore - How to update a field that contains period(.) in it's key from Android?

Updating a field contains period (.) is not working as expected.
In docs, nested fields can be updated by providing dot-seperated filed path strings or by providing FieldPath objects.
So if I have a field and it's key is "com.example.android" how I can update this field (from Android)?
In my scenario I've to set the document if it's not exists otherwise update the document. So first set is creating filed contains periods like above and then trying update same field it's creating new field with nested fields because it contains periods.
db.collection(id).document(uid).update(pkg, score)
What you want to do is possible:
FieldPath field = FieldPath.of("com.example.android");
db.collection(collection).document(id).update(field, value);
This is happening because the . (dot) symbol is used as a separator between objects that exist within Cloud Firestore documents. That's why you have this behaviour. To solve this, please avoid using the . symbol inside the key of the object. So in order to solve this, you need to change the way you are setting that key. So please change the following key:
com.example.android
with
com_example_android
And you'll be able to update your property without any issue. This can be done in a very simple way, by encoding the key when you are adding data to the database. So please use the following method to encode the key:
private String encodeKey(String key) {
return key.replace(".", "_");
}
And this method, to decode the key:
private String decodeKey(String key) {
return key.replace("_", ".");
}
Edit:
Acording to your comment, if you have a key that looks like this:
com.social.game_1
This case can be solved in a very simple way, by encoding/decoding the key twice. First econde the _ to #, second encode . to _. When decoding, first decode _ to . and second, decode # to _. Let's take a very simple example:
String s = "com.social.game_1";
String s1 = encodeKeyOne(s);
String s2 = encodeKeyTwo(s1);
System.out.println(s2);
String s3 = decodeKeyOne(s2);
String s4 = decodeKeyTwo(s3);
System.out.println(s4);
Here are the corresponding methods:
private static String encodeKeyOne(String key) {
return key.replace("_", "#");
}
private static String encodeKeyTwo(String key) {
return key.replace(".", "_");
}
private static String decodeKeyOne(String key) {
return key.replace("_", ".");
}
private static String decodeKeyTwo(String key) {
return key.replace("#", "_");
}
The output will be:
com_social_game#1
com.social.game_1 //The exact same String as the initial one
But note, this is only an example, you can encode/decode this key according to the use-case of your app. This a very common practice when it comes to encoding/decoding strings.
Best way to overcome this behavior is to use the set method with a merge: true parameter.
Example:
db.collection(id).document(uid).set(new HashMap<>() {{
put(pkg, score);
}}, SetOptions.merge())
for the js version
firestore schema:
cars: {
toyota.rav4: $25k
}
js code
const price = '$25k'
const model = 'toyota.rav4'
const field = new firebase.firestore.FieldPath('cars', model)
return await firebase
.firestore()
.collection('teams')
.doc(teamId)
.update(field, price)
Key should not contains periods (.), since it's conflicting with nested fields. An ideal solution is don't make keys are dynamic, those can not be determined. Then you have full control over how the keys should be.

How to add array value in Firebase

I want to add some certain data to a Firebase as arrays. Example:
groups : ['a','b','c']
How can I add and read data in Firebase from Android?
When you have a structure like that, you actually shouldn't be using an array to model it. It seems much more like a set in my eyes.
In the Firebase Database sets are best modeled as keys, since that automatically guarantees that items are unique. So your structure then becomes:
groups: {
"a": true,
"b": true,
"c": true
}
The true values are just markers, since Firebase won't allow you to store keys without a value.
Now to add a group to this, you'd use Firebase's setValue() function:
DatabaseReference root = FirebaseDatabase.getInstance().reference();
DatabaseReference groupsRef = root.child("groups");
groupsRef.child("d").setValue(true);
From the documentation:
setValue() - Record or change exists values
If you want to only append datas, you can to use updateChildren().
In Java, if we know that the data is array-like, it can be cast as a List:
Firebase julieRef = new Firebase("https://SampleChat.firebaseIO-demo.com/users/julie/");
julieRef.addValueEventListener(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot snapshot) {
GenericTypeIndicator<List<String>> t = new GenericTypeIndicator?<List<String>>() {};
List messages = snapshot.getValue(t);
if( messages === null ) {
System.out.println('No messages');
}
else {
System.out.println("The first message is: " + messages.get(0) );
}
}
// onCancelled...
});
Check this best practices post from the Firebase Blog.

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