Develop Reference

Auto send push notification from app server

Is there any way to send a push notification from server when a user complete a task? For example: A todo app will notify on that date with push notification. I want to use firebase and firestore for storing user tokens.
Alarm manager can be a solution that I have found but I don't wanna use it.

Yes, you can use scheduler to send notification from server to your app:
You may follow my working code:
Emplement IJob:
public class SendNotificationViaFcm: IJob
{
public void Execute(IJobExecutionContext context)
{
bool isNotificationSent=false;
try
{
var taskToSendNotification = FirebaseCloudMessaging.SendMessage();
Task.WaitAll(taskToSendNotification);
isNotificationSent = taskToSendNotification.Result;
}
catch (Exception exception)
when (
exception is ObjectDisposedException || exception is ArgumentNullException ||
exception is AggregateException)
{
}
catch (Exception exception) when (exception is InvalidOperationException)
{
}
catch (Exception exception)
{
// ignored
}
}
}
Call FCM Api from your server:
public class FirebaseCloudMessaging
{
private static readonly Uri FcmUri = new Uri(
uriString: #"https://fcm.googleapis.com",
uriKind: UriKind.Absolute);
private const string FcmApiKey = "Your Legacy Server Key";
public static async Task<bool> SendMessage()
{
using (var httpClient = new HttpClient())
{
httpClient.BaseAddress = FcmUri;
httpClient.DefaultRequestHeaders.Clear();
httpClient.DefaultRequestHeaders.TryAddWithoutValidation("Authorization",
"key=" + FcmApiKey);
var response = await httpClient.PostAsJsonAsync(#"/fcm/send", new
{
to = "/topics/global",
priority = "high",
data = new
{
title = "Warning",
message = "Please start app to track movemoent!"
}
//to = "/topics/global",
//priority = "high",
//notification = new
//{
// title = "Warning!",
// body = "Please start app to track movemoent!"
//}
});
Debug.Write(response.Content.ReadAsStringAsync());
var ck = response.IsSuccessStatusCode;
return response.IsSuccessStatusCode;
}
}
}
Implement schedular for your time interval:
public class Scheduler
{
public static void Start()
{
try
{
IScheduler scheduler = StdSchedulerFactory.GetDefaultScheduler();
scheduler.Start();
// scheduler.Shutdown();
var sentCloudNotification = JobBuilder.Create<SendNotificationViaFcm>().Build();
var cloudNotificationTrigger = TriggerBuilder.Create().WithSimpleSchedule(x => x.WithIntervalInMinutes(1).RepeatForever()).Build();
scheduler.ScheduleJob(sentCloudNotification, cloudNotificationTrigger);
}
catch (SchedulerException exception)
{
Debug.Write(exception.Message);
}
catch (Exception exception)
{
Debug.Write(exception.Message);
}
}
}
Finally Run in from your Global.asax.cs
protected void Application_Start()
{
Scheduler.Start();
}

It sounds like you're looking for a tool that allows you to schedule transactional notifications. What sort of server technology are you using?
From a high level you could do something like this:
1) user adds a task in the Android application
2) android application sends request to server to save the task
3) you have some code that runs in some sort of on task save callback that schedules a block of code to run in the future using crontab, celery or something similar.
4) the block of code that runs in the future is an api call to twilio to send a push notification
relevant links: https://www.twilio.com, https://firebase.google.com/docs/cloud-messaging/, http://www.celeryproject.org/, https://en.wikipedia.org/wiki/Cron

Forbidden in Call connection Android Pjsip Sip library

How to perform call in Pjsip Android with local server?
I used
User-Agent: Pjsua2 Android 2.6-svn
I made successful registraion after which i tried to call but it throws forbidden(503)
My Registraion Code :
AccountConfig accCfg = new AccountConfig();
accCfg.setIdUri("sip:localhost");
accCfg.getNatConfig().setIceEnabled(true);
accCfg.getVideoConfig().setAutoTransmitOutgoing(true);
accCfg.getVideoConfig().setAutoShowIncoming(true);
//Like 123.12.12.23
accCfg.getRegConfig().setRegistrarUri("sip:172.16.4.124");
AuthCredInfoVector creds = accCfg.getAuthCreds();
creds.clear();
if (username.length() != 0) {
creds.add(new AuthCredInfo("Digest", "*", "abc#172.16.4.124", 0,
"123"));
}
StringVector proxies = accCfg.getSipConfig().getProxies();
proxies.clear();
if (proxy.length() != 0) {
proxies.add("sip:172.16.4.124");
}
accCfg.getSipConfig().setProxies(proxies);
/* Enable ICE */
accCfg.getNatConfig().setIceEnabled(true);
try {
account.add(accCfg);
} catch (Exception e) {
e.printStackTrace();
Log.i(TAG, "Exception in Dialog");
}
}
For Making call I used
public void makeCall(View view) {
if (buddyListSelectedIdx == -1)
return;
/* Only one call at anytime */
if (currentCall != null) {
return;
}
HashMap<String, String> item = (HashMap<String, String>) buddyListView.
getItemAtPosition(buddyListSelectedIdx);
String buddy_uri = item.get("uri");
MyCall call = new MyCall(account, -1);
SendInstantMessageParam param = new SendInstantMessageParam();
param.setContent("Hello Pjsip");
param.setContentType("text");
CallOpParam prm = new CallOpParam(true);
try {
call.makeCall(buddy_uri, prm);
// call.delete();
// call.sendInstantMessage(param);
} catch (Exception e) {
e.printStackTrace();
call.delete();
return;
}
currentCall = call;
showCallActivity();
}
I am able to connect call with sip default client like sip:localhost and other sip provider like linphone but getting forbidden with our server.
Experts please help.

Thanks alot to myself, finally i get the solution after 3 day workout,
had missing portnumber for my amazon server, makes me to get connected and made a sippy call between sip ends.

how detect if the message fails on XMPP Smack to Android?

I making a android chat app. Im use the api level 23, the Xmpp Smack lib version 4.1.8, and on server I use ejabberd, version 16.06.
I use this code to build a XMPP connection.
(TIMEOUT = 5000)
private void buildConnection() {
XMPPTCPConnectionConfiguration.Builder builder = XMPPTCPConnectionConfiguration.builder()
.setServiceName(mServiceName)
.setHost(mServiceName)
.setConnectTimeout(TIMEOUT)
.setResource("Smack")
.setUsernameAndPassword(mUsername, mPassword)
.setSendPresence(true)
.setSecurityMode(ConnectionConfiguration.SecurityMode.disabled);
mConnection = new XMPPTCPConnection(builder.build());
mConnection.setPacketReplyTimeout(TIMEOUT);
chatManager = ChatManager.getInstanceFor(mConnection);
chatManager.addChatListener(this);
PingManager pingManager = PingManager.getInstanceFor(mConnection);
pingManager.setPingInterval(5);
pingManager.registerPingFailedListener(this);
ReconnectionManager reconnectionManager = ReconnectionManager.getInstanceFor(mConnection);
reconnectionManager.enableAutomaticReconnection();
mConnection.addConnectionListener(this);
if (mConnection != null) {
DeliveryReceiptManager.getInstanceFor(mConnection).addReceiptReceivedListener(new ReceiptReceivedListener() {
#Override
public void onReceiptReceived(String fromJid, String toJid, String receiptId, Stanza receipt) {
updateMessageStatusReceived(receipt);
Log.i(TAG, "Confirmation stanza Got: " + receipt);
}
});
}
}
(the updateMessageStatusReceived(receipt) method is only to refresh the view).
after that, I connect and authenticate.
Everthing is normal, but when the connection is down, I need to resend the failed messages when the connection is restored. I didn't find any solution or event in Smack to detected if a message fails. Sometimes the delay of confirmation server stanza is high, and my app assumes that message fails but don't, and the other side receive many times the same message.
I build a Message object and send using this code:
try {
Chat chat = chatManager.createChat(chatMessage.getJid());
chat.sendMessage(message);
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
} catch (Exception e) {
e.printStackTrace();
}
When the connection is lost and I send message, no one exception is throw.
my question is: How I know the message realy fail, to try again?
Thanks, and sorry about the english.

Android Smack MUC 400 Bad Request sending group Chat Message

Hey i am developing Chat Application using XMPP Smack Library. Recently i am working on Group Chat While sending Group message some message will be drop so receiver wouldn't receives message from the sender side. it will gives me 400 bad request.
it is working sometimes. and sometimes not work
here i found this kind of message in 400 bad request.
<?xml version="1.0" encoding="UTF-8"?>
<message to="156#abc.com/Android" id="nXlV6-1144" type="error" from="24#confrence.abc.com/156#abc.com.com">
<received xmlns="urn:xmpp:receipts" id="nXlV6-1142" />
<error code="400" type="modify">
<bad-request xmlns="urn:ietf:params:xml:ns:xmpp-stanzas" />
</error>
</message>
if successfully send message it will give this kind of message.
<?xml version="1.0" encoding="UTF-8"?>
<message to="156#abc.com/Android" id="nXlV6-1411" type="groupchat" from="24#conference.abc.com/156#abc.com">
<body>eyu4u4</body>
<chatDetail xmlns="jabber:x:oob">
<UID>156</UID>
<time>04:20 PM</time>
<user_icon>24_group_icon.jpg</user_icon>
<SentTime>1474368652960</SentTime>
<USERName>vasudev89</USERName>
<user_name>cryan</user_name>
<message>eyu4u4</message>
<type>group</type>
<phone_number>24</phone_number>
</chatDetail>
<request xmlns="urn:xmpp:receipts" />
</message>
how i can send message persistently? Any idea?
Thank You in Advance.
here is my code sending muc message:
public boolean sendGroupMessage(Message message, String strGroupID) {
DeliveryReceiptRequest.addTo(message);
try {
Log.i(TAG, "sendGroupMessage");
//Log.i("JOIN MUC","To join group chat: " + groupChat.getClassId());
// Get the MultiUserChatManager
MultiUserChatManager manager = MultiUserChatManager.getInstanceFor(AbstractXMPPConnection);
// Create a MultiUserChat using an XMPPConnection for a room
MultiUserChat muc = manager.getMultiUserChat(strGroupID + AppWSConstants.XMPP_JID_GROUP_CHAT_SUFFIX);
muc.sendMessage(message);
return true;
} catch (NotConnectedException e) {
e.printStackTrace();
}
return false;
}

#LearnPainLess, follow these steps to solve group chat issue
-when creating groups, save the jid of group in the database, like "somegroup#conference.{domain}.com"
-create background task for creating xmpp connection (this way it will always be connected)
-after logging in to xmpp, get the group names from the database and connect to them
also, in openfire, Group Chat > Group Chat Settings > Edit Icon > Default Room Settings > Check "Make Room Persistant"
also, in other settings > Never kick idle users

I have an XmppBase class where i put all my xmpp code
All listeners in seperate folder
Connection is stored in static variable and i retrive it using
Utils.getConnection()
// this function m calling from background service and everywhere if not connectect to xmpp
public static XMPPConnection CreateXmppConnection() {
if (Utils.getConnection() == null) {
try {
Boolean isConnected = new XmppAsync(mUsername, mPassword,context).execute().get();
if (isConnected && Utils.getConnection() != null) {
RegisterConnListeners(Utils.getConnection());
updateMyProfileImg();
// connect to all groups
DBAdapter adapter = new DBAdapter(context);
adapter.openForRead();
List<UserDetail> groups = new ArrayList<>();
adapter.addAllGroups(groups);
adapter.addPastChatGroups(groups);
adapter.close();
for(UserDetail g : groups)
{
CreateXmppMUCSession(g.getGroupTemp());
}
return Utils.getConnection();
}
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
}
return null;
} else
return Utils.getConnection();
}
// get muc chat manager
public static MultiUserChatManager getMucManager() {
if(mucManager != null)
return mucManager;
if (Utils.getConnection() != null) {
return MultiUserChatManager.getInstanceFor(Utils.getConnection());
} else {
if (CreateXmppConnection() != null)
return MultiUserChatManager.getInstanceFor(Utils.getConnection());
else {
Log.v("error", "Some Error Occured");
Toast.makeText(context, "Cant Connect to Xmpp", Toast.LENGTH_SHORT).show();
return null;
}
}
}
// create muc session and m passing group name - call when you open chat page
public static void CreateXmppMUCSession(String gName)
{
RegisterGroupChatListeners(gName);
}
// connect to muc if not already connected
public static void RegisterGroupChatListeners(String groupName)
{
try {
mStateManager = getChatStateManager();
multiUserChat = getMUC(groupName);
// if(multiUserChat != null) {
multiUserChat.addMessageListener(new MyMUCMessageListener());
try {
if (!multiUserChat.isJoined()) {
DiscussionHistory discussionHistory = new DiscussionHistory();
discussionHistory.setMaxStanzas(0);
multiUserChat.join(new MyPrefrence(context).getUsername().split("#")[0], "123",
discussionHistory, SmackConfiguration.getDefaultPacketReplyTimeout());
}
} catch (SmackException.NoResponseException e) {
e.printStackTrace();
} catch (XMPPException.XMPPErrorException e) {
e.printStackTrace();
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
// }
}
catch (Exception ex)
{
//
}
}
// get muc
public static MultiUserChat getMUC(String groupName)
{
// Log.v("nick",multiUserChat.getNickname() + " , g = " + groupName);
// if(multiUserChat != null && multiUserChat.getRoom().contains(groupName))
// {
// return multiUserChat;
// }
if (Utils.getConnection() != null) {
MultiUserChatManager chatManager = getMucManager();
if (chatManager != null) {
return chatManager.getMultiUserChat(groupName);
} else {
Toast.makeText(context, "Cannot create Chat", Toast.LENGTH_SHORT).show();
return null;
}
} else {
if (CreateXmppConnection() != null) {
MultiUserChatManager chatManager = getMucManager();
if (chatManager != null) {
return chatManager.getMultiUserChat(groupName);
} else {
Toast.makeText(context, "Cannot create Chat", Toast.LENGTH_SHORT).show();
return null;
}
}
else {
Toast.makeText(context, "Cannot create Chat", Toast.LENGTH_SHORT).show();
return null;
}
}
}
and whenever i want to send message i just call this
public static Boolean sendMUCChatMsg(Message msg)
{
if(multiUserChat != null)
try {
multiUserChat.sendMessage(msg);
return true;
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
}
return false;
}
Sorry if it looks clumpsy, if I missed any function there let me know, but this is working code which i am using

try this,
I modified your last function
static MultiUserChat multiUserChat;
// call this function when you open the chat window
private void CreateGroupConnection(String strGroupID ) {
// Get the MultiUserChatManager
MultiUserChatManager manager = MultiUserChatManager.getInstanceFor(AbstractXMPPConnection);
// Create a MultiUserChat using an XMPPConnection for a room
MultiUserChat multiUserChat = manager.getMultiUserChat(strGroupID + AppWSConstants.XMPP_JID_GROUP_CHAT_SUFFIX);
return multiUserChat;
}
// whenever sending message from chat call this
publilc static void sendMucMessage(Message message){
if(multiUserChat != null)
multiUserChat.sendMessage(message);
}

I am working on "seen and delivered" in MUC and facing with this issue when replying back with the same packet id, still testing but I think in your case you should move your xmpp connection to background service and after connecting to xmpp on device launch up, connect to all the muc in your database. This way you will always be connected to groups.
cause : according to me, when the other user is not connected to the muc and you send a message or when you reply to the group with the same packet id.
Note: I am using multiuserchat.sendmessage to send group message and chat.sendmessage to send message to single user
SMACK 4.1
** update **
I fixed it by creating new packet instead of modifying the one i am receiving
here is the packet
Message msgg = new Message();
msgg.setBody(message.getPacketID());
msgg.setSubject(MessageModel.CHAT_STATUS_SEEN + "");
XmppBase.sendMUCChatMsg(msgg);
in your case, try with simple packet first. if all works well, then add extension one by one and see where you get the error, Thanks

Using Netty ( tcp ), sending message from client in android to server

I successed connection bitween client in android and server.
but, when I want to send message like "hello" or whatever, message was disappear.
this is my client code:
group = new OioEventLoopGroup();
Bootstrap b = new Bootstrap();
b.group(group);
b.channel(OioSocketChannel.class);
b.option(ChannelOption.SO_KEEPALIVE, true);
b.handler(new ChannelInitializer<SocketChannel>() {
#Override
public void initChannel(SocketChannel ch) throws Exception {
ch.pipeline().addLast(handler);
}
});
Channel ch = null;
ChannelFuture f = null;
try {
f = b.connect(new InetSocketAddress(host, port)).sync();
ch = f.channel();
} catch (InterruptedException e) {
e.printStackTrace();
}
ch.writeAndFlush("hello!");
and this is my server code:
#Override
public void channelActive(ChannelHandlerContext ctx){
channels.add(ctx.channel());
ctx.channel().writeAndFlush("Welcome My Server");
System.out.println(ctx.channel().remoteAddress());
}
#Override
public void channelRead(ChannelHandlerContext ctx, Object msg) {
ByteBuf in = (ByteBuf) msg;
try {
while (in.isReadable()) {
System.out.print((char) in.readByte());
System.out.flush();
}
} finally {
ReferenceCountUtil.release(msg);
}
}
when I connect, Server was printing 'connected client ip address'
but after that, 'hello' message is not printed in my server.
what is wrong? server? client?
I think encode, decode is not problem, cuz nothing received
please let me know how to do for that?

If you want to write a String you need to put StringEncoder in the ChannelPipeline (on the client side). If you check the returned ChannelFuture of writeAndFlush(...) you will see it was failed.