I am getting an OffsetDateTime from our backend in a String format like this:
"2017-07-15T10:52:59Z"
I am trying to parse this String to a Android Date:
private SimpleDateFormat mSimpleDateFormat;
private static final String DATE_FORMAT_PATTERN = "yyyy-MM-dd'T'HH:mm:ss";
mSimpleDateFormat = new SimpleDateFormat(DATE_FORMAT_PATTERN, Locale.getDefault());
Date newDate = null;
String dateString = notice.getCreated();
try {
newDate = mSimpleDateFormat.parse(dateString);
} catch (ParseException e) {
LogHelper.showExceptionLog(MyClass.class, e);
}
It always throws:
Unparseable date: "2017-07-15T10:52:59Z"
To parse the Z (which is the UTC designator) you must use the X pattern (as explained in javadoc):
SimpleDateFormat mSimpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssX");
String dateString = "2017-07-15T10:52:59Z";
Date newDate = mSimpleDateFormat.parse(dateString);
If you use just yyyy-MM-dd'T'HH:mm:ss as a pattern, SimpleDateFormat will use the system's default timezone and ignore the Z, giving incorrect results: it'll parse the date/time as 10:52 in the default timezone, which can be different to 10:52 in UTC. By using the X pattern, you get the correct result.
I also removed the Locale because this formatter is not dealing with any locale-sensitive information (like month and day of week names), so it doesn't affect the parsing in this case (and SimpleDateFormat already uses the default locale if you don't specify one).
PS: the X pattern was introduced in JDK 7. If you're using and older version, it won't be available. In this case, you can set the UTC as a timezone of the formatter:
SimpleDateFormat mSimpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
mSimpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
Obviously this code is assuming that the input is always in UTC (with Z in the end).
Java new Date/Time API
The old classes (Date, Calendar and SimpleDateFormat) have lots of problems and design issues, and they're being replaced by the new APIs.
For Android, you can use the ThreeTen Backport, a great backport for Java 8's new date/time classes. To make it work, you'll also need ThreeTenABP (more on how to use it here).
As the input string is in ISO 8601 format, you can easily parse it to a org.threeten.bp.OffsetDateTime:
String dateString = "2017-07-15T10:52:59Z";
OffsetDateTime odt = OffsetDateTime.parse(dateString);
You can then convert this to a java.util.Date easily, using the org.threeten.bp.DateTimeUtils class:
Date date = DateTimeUtils.toDate(odt.toInstant());
If the input is always in UTC (always with the Z in the end), you can also use a org.threeten.bp.Instant:
String dateString = "2017-07-15T10:52:59Z";
Instant instant = Instant.parse(dateString);
Date date = DateTimeUtils.toDate(instant);
The only difference is that Instant only parses UTC inputs (ending with Z) and OffsetDateTime accepts any valid UTC offset (like -03:00 or +05:30).
Related
I am trying to convert "2021-05-14T13:42:48.000Z" string to Date Object.
I have tried this:
DateFormat dateFormat = new SimpleDateFormat("YYYY-MM-DDHH:MM:SS");
And also this, which i saw on stackoverflow only:-
DateFormat dateFormat = new SimpleDateFormat("YYYY-MM-DD'T'HH:MM:SS'A'");
But none of it worked.
How can i convert this string to my date object?
Assuming your date string always represents a UTC time (with the 'Z'), you can use format string:
yyyy-MM-dd'T'HH:mm:ss.SSSZ
but you'll first need to replace the Z in your date string with the fixed timezone "+0000", as in "2021-05-14T13:42:48.000+0000".
Try this:
String myDateString = "2021-05-14T13:42:48.000Z"
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US);
Date myDate = dateFormat.parse (myDateString.replace("Z","+0000"));
This will return a date correctly adjusted for your current timezone, in my case 9:42:48am EDT.
There is a more detailed discussion at Converting ISO 8601-compliant String to java.util.Date which you may find useful.
You have used the date-time format incorrectly. It's important to note that the date-time formats have different meanings between capitalized and small letters.
For example: Capital MM means months, whereas small mm means minutes.
To know more about the date formats, you can refer this:
https://cheatography.com/pezmat/cheat-sheets/date-time-formats/pdf/
or this:
https://devhints.io/datetime
And the answer for your case is:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
Please do not use SimpleDateFormat or even java.date. All these classes are deprecated.
Instead, rely on the Android available java.time package.
In short:
val source = "2021-05-14T13:42:48.000Z"
val parsed = ZonedDateTime.parse(source)
This will correctly parse the timezone (Z for Zulu/UTC/GMT).
You can verify this, by simply converting the parsed Zoned date time into, for example, Europe/Amsterdam time (which is +2).
val source = "2021-05-14T13:42:48.000Z"
val parsed = ZonedDateTime.parse(source)
parsed.toString() // prints: 2021-05-14T13:42:48Z
parsed.zone // prints: "Z"
ZoneId.of(parsed.zone.id) // returns the ZoneOffset "Z" (correct)
// Convert to Amsterdam Time
val amsterdamDateTime = parsed.withZoneSameInstant(ZoneId.of("Europe/Amsterdam"))
amsterdamDateTime.toString() // prints: 2021-05-14T15:42:48+02:00[Europe/Amsterdam] (2 hours ahead of the Zulu time, also correct).
parsed.format(DateTimeFormatter.ISO_DATE_TIME).toString() // Prints: 2021-05-14T13:42:48Z (correct)
So as you can see, these classes do the right thing (most of the time).
I suggest you use them.
I have a date-time string with time zone like "2019-05-21 04:49:39.000Z" this. How do i split the date from this string without split method.I have to use the time zone formatter. Anyone please help me in it.
public static String getDateTime(String created_on) {
SimpleDateFormat inFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
SimpleDateFormat outFormat = new SimpleDateFormat("dd MMM yyyy hh:mm aa");
try {
inFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
Date value = inFormat.parse(created_on);
outFormat.setTimeZone(TimeZone.getDefault());
created_on = outFormat.format(value);
} catch (ParseException e) {
e.printStackTrace();
}
return created_on;
}
Use this Function.It will help you to get Date and Time
Use some library for parsing String to e.g. OffsetDateTime,
after from parsedDateTime variable get any part of the time (hour, min...)
In kotlin (min API 26) :
val parsedDateTime = OffsetDateTime
.parse("2019-05-21 04:49:39.000Z", DateTimeFormatter.ISO_DATE_TIME)
val time = "${parsedDateTime.hour} : ${parsedDateTime.minute}"
check this link for more examples : examples
https://grokonez.com/kotlin/kotlin-convert-string-datetime
Update :
As Ole V.V. mentioned in comment - if you’re not yet on API level 26, you may add ThreeTenABP to your Android project and import OffsetDateTime from there (and than the same code works for lower API).
I am trying to convert ISO 8601 time into something human readable and in the local timezone of the Android device.
String date = "2016-09-24T06:24:01Z";
LocalDate test = LocalDate.parse(date, ISO_INSTANT);
But it returns:
method threw 'org.threeten.bp.format.DateTimeParseException' exception
From reading http://www.threeten.org/threetenbp/apidocs/org/threeten/bp/format/DateTimeFormatter.html#ISO_INSTANT it seems like what I'm doing should be possible.
What am I doing wrong?
Edit
Expanded exception error:
Unable to obtain LocalDate from TemporalAccessor: DateTimeBuilder[fields={MilliOfSecond=0, NanoOfSecond=0, InstantSeconds=1474698241, MicroOfSecond=0}, ISO, null, null, null], type org.threeten.bp.format.DateTimeBuilder
Edit 2
The solution is in the answer below. For anyone that stumbles across this, if you want to specify a custom output format you can use:
String format = "MMMM dd, yyyy \'at\' HH:mm a";
String dateString = DateTimeFormatter.ofPattern(format).withZone(ZoneId.systemDefault()).format(instant);
#alex answer is correct. Here is a working example.
Instant represents a point in time. To convert to any other local types you will need timezone.
String date = "2016-09-24T06:24:01Z";
This date string is parsed using the DateTimeFormatter#ISO_INSTANT internally.
Instant instant = Instant.parse(date);
From here you can convert to other local types just using timezone ( defaulting to system time zone )
LocalDateTime localDateTime = instant.atZone(ZoneId.systemDefault()).toLocalDateTime();
LocalDate localDate = instant.atZone(ZoneId.systemDefault()).toLocalDate();
LocalTime localTime = instant.atZone(ZoneId.systemDefault()).toLocalTime();
Alternatively, you can use static method to get to local date time and then to local date and time.
LocalDateTime localDateTime = LocalDateTime.ofInstant(instant, ZoneId.systemDefault());
LocalDate localDate = localDateTime.toLocalDate();
LocalTime localTime = localDateTime.toLocalTime();
You need to use Instant.parse().
This will give you an Instant that you can combine with a time zone to create a LocalDate.
In Kotlin:
Converts to LocalDateTime directly based on your local time zone::
val instant: Instant = Instant.parse("2020-04-21T02:22:04Z")
val localDateTime = instant.atZone(ZoneId.systemDefault()).toLocalDateTime()
Converts to Date and time separately based on your local time zone:
val localDate: LocalDate = instant.atZone(ZoneId.systemDefault()).toLocalDate()
val localTime: LocalTime = instant.atZone(ZoneId.systemDefault()).toLocalTime()
This question already has answers here:
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I am getting date value from DB as a long value. I am converting this to string to use parse function. Given below is my code
Date date1 = new SimpleDateFormat("MM/dd/yyyy").parse(strDate1);
But the app is crashing when this code is executing.it will successfully execute if the
strDate1="12/30/2012".
But i am having this value as "12302012235"(pzudo value).
How can i do this?
edit:
i am saving date value to DB as INTEGER. from DB i am getting this value and converting to string.this is the actual strDate1 value
strDate1="1346524199000"
Try the following code segment:
Calendar c = Calendar.getInstance();
c.setTimeInMillis(Long.parseLong(val));
Date d = (Date) c.getTime();
SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy");
String time = format.format(d);//this variable time contains the time in the format of "day/month/year".
Try this,
SimpleDateFormat dateFormat=new SimpleDateFormat("yyyy-MM-dd");
Date dateD=new Date();
dateD.setTime(LongTime);
date=dateFormat.format(dateD);
Java 8, Convert milliseconds long to Date as String by given date format pattern. If you have a long milliseconds and want to convert them into date string at specifies time zone and pattern, then you can use it:-
dateInMs is a long value of DateTime.
DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss")
.format(Instant.ofEpochMilli(dateInMs).atZone(ZoneId.of("Europe/London")))
java.time
The java.util date-time API and their formatting API, SimpleDateFormat are outdated and error-prone. It is recommended to stop using them completely and switch to the modern date-time API* .
Using modern date-time API:
import java.time.Instant;
import java.time.ZoneId;
import java.time.ZonedDateTime;
import java.time.format.DateTimeFormatter;
import java.util.Date;
import java.util.Locale;
public class Main {
public static void main(String[] args) {
long input = 12302012235L;
// Get Instant from input
Instant instant = Instant.ofEpochMilli(input);
System.out.println(instant);
// Convert Instant to ZonedDateTime by applying time-zone
// Change ZoneId as applicable e.g. ZoneId.of("Asia/Dubai")
ZonedDateTime zdt = instant.atZone(ZoneId.systemDefault());
System.out.println(zdt);
// Format ZonedDateTime as desired
// Check https://stackoverflow.com/a/65928023/10819573 to learn more about 'u'
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("MM/dd/uuuu", Locale.ENGLISH);
String formatted = dtf.format(zdt);
System.out.println(formatted);
// If at all, you need java.util.Date
Date date = Date.from(instant);
}
}
Output:
1970-05-23T09:13:32.235Z
1970-05-23T10:13:32.235+01:00[Europe/London]
05/23/1970
Learn more about the modern date-time API from Trail: Date Time.
* For any reason, if you have to stick to Java 6 or Java 7, you can use ThreeTen-Backport which backports most of the java.time functionality to Java 6 & 7. If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring and How to use ThreeTenABP in Android Project.
You can try following code:
private Date getGMTDate(long date) {
SimpleDateFormat dateFormatGmt = new SimpleDateFormat(
"yyyy-MMM-dd HH:mm:ss");
dateFormatGmt.setTimeZone(TimeZone.getTimeZone("GMT"));
SimpleDateFormat dateFormatLocal = new SimpleDateFormat(
"yyyy-MMM-dd HH:mm:ss");
Date temp = new Date(date);
try {
return dateFormatLocal.parse(dateFormatGmt.format(temp));
} catch (ParseException e) {
e.printStackTrace();
}
return temp;
}
I hope this will help you.
Try this
Date date1 = new SimpleDateFormat("MMddyyyySSS").parse(strDate1);
Hope it will works for 12302012235 , but i assume 235 is millisec.
i got the answer.actually i wanted to convert the string to date only for comparing the values.since i am getting the value as long i directly used the compareTo function to do this.avoided the conversion of long to string and string to date conversion.thank you all for support.
I want to display a date of birth based on the user locale. In my application, one of my fields is the date of birth, which is currently in the format dd/mm/yyyy. So if the user changes his locale, the date format should also change accordingly. Any pointers or code samples would really help me to overcome the problem.
You can use the DateFormat class that formats a date according to the user locale.
Example:
String dateOfBirth = "26/02/1974";
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
Date date = null;
try {
date = sdf.parse(dateOfBirth);
} catch (ParseException e) {
// handle exception here !
}
java.text.DateFormat dateFormat = android.text.format.DateFormat.getDateFormat(context);
String s = dateFormat.format(date);
You can use the different methods getLongDateFormat, getMediumDateFormat depending on the level of verbosity you would like to have.
While the accepted answer was correct when the question was asked, it has later become outdated. I am contributing the modern answer.
java.time and ThreeTenABP
DateTimeFormatter dateFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.SHORT);
LocalDate dateOfBirth = LocalDate.of(1991, Month.OCTOBER, 13);
String formattedDob = dateOfBirth.format(dateFormatter);
System.out.println("Born: " + formattedDob);
It gives different output depending on the locale setting of the JVM (usually taking from the device). For example:
Canadian French: Born: 91-10-13
Chinese: Born: 1991/10/13
German: Born: 13.10.91
Italian: Born: 13/10/91
If you want a longer format, you may specify a different format style. Example outputs in US English locale:
FormatStyle.SHORT: Born: 10/13/91
FormatStyle.MEDIUM: Born: Oct 13, 1991
FormatStyle.LONG: Born: October 13, 1991
FormatStyle.FULL: Born: Thursday, October 13, 1991
Question: Can I use java.time on Android?
DateTimeFormatter.ofLocalizedDate requires Api O minimum.
Yes, java.time works nicely on older and newer Android devices. No, it does not require API level 26 or Oreo even though a message in your Android Studio might have you think that. It just requires at least Java 6.
In Java 8 and later and on newer Android devices (from API level 26) the modern API comes built-in.
In Java 6 and 7 get the ThreeTen Backport, the backport of the modern classes (ThreeTen for JSR 310; see the links at the bottom).
On older Android either use desugaring or the Android edition of ThreeTen Backport. It’s called ThreeTenABP. In the latter case make sure you import the date and time classes from org.threeten.bp with subpackages.
Question: Can I also accept user input in the user’s local format?
Yes, you can. The formatter can also be used for parsing a string from the user into a LocalDate:
LocalDate date = LocalDate.parse(userInputString, dateFormatter);
I suggest that you first format an example date and show it to the user so that s/he can see which format your program expects for his/her locale. As example date take a date with day of month greater than 12 and year greater than 31 so that the order of day, month and year can be seen from the example (for longer formats the year doesn’t matter since it will be four digits).
Parsing will throw a DateTimeParseException if the user entered the date in an incorrect format or a non-valid date. Catch it and allow the user to try again.
Question: Can I do likewise with a time of day? A date and time?
Yes. For formatting a time of day according to a user’s locale, get a formatter from DateTimeFormatter.ofLocalizedTime. For both date and time together use one of the overloaded versions of DateTimeFormatter.ofLocalizedDateTime.
Avoid the DateFormat, SImpleDateFormat and Date classes
I recommend you don’t use DateFormat, SimpleDateFormat and Date. Those classes are poorly designed and long outdated, the first two in particular notoriously troublesome. Instead use LocalDate, DateTimeFormatter and other classes from java.time, the modern Java date and time API.
Links
Oracle tutorial: Date Time explaining how to use java.time.
Java Specification Request (JSR) 310, where java.time was first described.
ThreeTen Backport project, the backport of java.time to Java 6 and 7 (ThreeTen for JSR-310).
Java 8+ APIs available through desugaring
ThreeTenABP, Android edition of ThreeTen Backport
Question: How to use ThreeTenABP in Android Project, with a very thorough explanation.
As simple as
For date + time:
DateFormat format = DateFormat.getDateTimeInstance(DateFormat.DEFAULT, DateFormat.SHORT, Locale.getDefault());
For just date:
DateFormat format = DateFormat.getDateInstance(DateFormat.SHORT, Locale.getDefault());
Android api provide easy way to display localized date format.
The following code works.
public class FileDateUtil {
public static String getModifiedDate(long modified) {
return getModifiedDate(Locale.getDefault(), modified);
}
public static String getModifiedDate(Locale locale, long modified) {
SimpleDateFormat dateFormat = null;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.JELLY_BEAN_MR2) {
dateFormat = new SimpleDateFormat(getDateFormat(locale));
} else {
dateFormat = new SimpleDateFormat("MMM/dd/yyyy hh:mm:ss aa");
}
return dateFormat.format(new Date(modified));
}
#TargetApi(Build.VERSION_CODES.JELLY_BEAN_MR2)
public static String getDateFormat(Locale locale) {
return DateFormat.getBestDateTimePattern(locale, "MM/dd/yyyy hh:mm:ss aa");
}
}
You can check following code.
String koreaData = FileDateUtil.getModifiedDate(Locale.KOREA, System.currentTimeMillis());
String franceData = FileDateUtil.getModifiedDate(Locale.FRENCH, System.currentTimeMillis());
String defaultData = FileDateUtil.getModifiedDate(Locale.getDefault(), System.currentTimeMillis());
String result = "Korea : " + koreaData + System.getProperty("line.separator");
result += "France : " + franceData + System.getProperty("line.separator");
result += "Default : " + defaultData + System.getProperty("line.separator");
tv.setText(result);
To change the date format according to the locale, the following code worked to me:
String dateOfBirth = "26/02/1974";
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
Date date = null;
try {
date = sdf.parse(dateOfBirth);
} catch (ParseException e) {
// handle exception here !
}
String myString = DateFormat.getDateInstance(DateFormat.SHORT).format(date);
Then when you change the locale, the date format will change based on it.
For more information about the dates patterns:
http://docs.oracle.com/javase/tutorial/i18n/format/dateFormat.html
To get the date format pattern you can do :
Format dateFormat = android.text.format.DateFormat.getDateFormat(getApplicationContext());
String pattern = ((SimpleDateFormat) dateFormat).toLocalizedPattern();
After that, you can format your input as per the pattern.
The simple way to do it:
String AR_Format = "dd-mm-yyyy";
String EN_Format = "mm-dd-yyyy";
String getFomattedDateByLocale(Date date, String locale) {
return new SimpleDateFormat(strDateFormat, new Locale(locale)).format(date);
}
And then call it like this:
txtArabicDate.setText(getFomattedDateByLocale(new Date(), AR_Format));
txtEnglishDate.setText(getFomattedDateByLocale(new Date(), EN_Format));
Don't forget to replace new Date() by your own date variable.
Good luck.
My way, with example: UTC iso format String to android User.
//string UTC instant to localDateTime
String example = "2022-01-27T13:04:23.891374801Z"
Instant instant = Instant.parse(example);
TimeZone timeZone = TimeZone.getDefault();
LocalDateTime localDateTime = LocalDateTime.ofInstant(instant, timeZone.toZoneId());
//localDateTime to device culture string output
DateTimeFormatter dateFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.LONG);
String strDate = localDateTime.toLocalDate().format(dateFormatter);
DateTimeFormatter timeFormatter = DateTimeFormatter.ofLocalizedTime(FormatStyle.MEDIUM);
String strTime = localDateTime.toLocalTime().format(timeFormatter);
//strings to views
txtDate.setText(strDate);
txtTime.setText(strTime);