Develop Reference

How to make a synchronous volley StringRequest?

How to make Volley StringRequest should wait for the one response to complete and after completing the first response it should start another request.

you have to do if your first response successfully then call these second method your answers is into your question

Inside onResponse of your StringRquest make the second request you want.
StringRequest stringRequest = new StringRequest(Request.Method.POST, recieveMessageUrl, new Response.Listener<String>() {
#Override
public void onResponse(String response) {
//create second request here
//and add it to queue
}
}, new Response.ErrorListener() {
#Override
public void onErrorResponse(VolleyError error) {
}
});
Note: you will have to make sure that your response is valid otherwise the onErrorResponse will be called.

Android Volley duplicates request

Volley request is done inside a while. It duplicates for no reason ( seemingly ) For example when I suppose to make two requests, volley does it 4 times. Below is my code, some of you could hint the problem in my code ?
while(i<chnumTxt.length()){
final RequestQueue queue;
queue = Volley.newRequestQueue(this);
char letter=chnumTxt.charAt(i);
Log.i("check","counter="+i+" "+"digit="+letter);
String URL = "http://192.168.4.20:80/chnumber?key="+letter;
Log.i("web",URL);
StringRequest request = new StringRequest(Request.Method.GET, URL, new Response.Listener<String>() {
#Override
public void onResponse(String response) {
//Log.i("html",response.toString());
}
}, new Response.ErrorListener() {
#Override
public void onErrorResponse(VolleyError error) {
}
});
queue.add(request);
new CountDownTimer(500, 500) {
public void onFinish() {
// When timer is finished
// Execute your code here
}
public void onTick(long millisUntilFinished) {
}
}.start();
i++;
}

Eventually i found the answer somewhere. Volley will retry links if the link seems slow. So after blocking it, got it right. It is like :
First declare a variable :
static final float DEFAULT_BACKOFF_MULT = 1f;
and after defining the request, do below code :
request.setRetryPolicy(new DefaultRetryPolicy(20 * 1000, 0,
DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));

Nested Volley Requests in Android Studio in single session connection

I want to extract data from an HTTPS site. but It's generating an access code for every new opening of the website. so I used volley for getting access code once and getting the result of https once but when I am making 2nd request to get the result, a new session is a creation that leads to a change of access code. Can I do this in a single request ? or is there any alternate way to do this?
RequestQueue queue = Volley.newRequestQueue(this);
String url ="https://jntukresults.edu.in/view-results-56736070.html";
StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
new Response.Listener<String>() {
#Override
public void onResponse(String response) {
access_code=StringUtils.substringBetween(response, "&accessToken=\"+", ",true);");
Toast.makeText(getApplicationContext(),raju,Toast.LENGTH_LONG).show();
}
}, new Response.ErrorListener() {
#Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(),"Error",Toast.LENGTH_SHORT).show();
}
});
Volley.newRequestQueue(getApplicationContext()).add(stringRequest);
String resultUrl="https://jntukresults.edu.in/results/res.php?ht=16FE1A0593&id=56736070&accessToken="+access_code;
StringRequest stringRequest1=new StringRequest(Request.Method.GET, resultUrl, new Response.Listener<String>() {
#Override
public void onResponse(String response2) {
textView.setText(response2);
Toast.makeText(getApplicationContext(),response2,Toast.LENGTH_SHORT).show();
}
}, new Response.ErrorListener() {
#Override
public void onErrorResponse(VolleyError error) {
}
});
Volley.newRequestQueue(getApplicationContext()).add(stringRequest1);

Appending string at the end of url in GET method :Volley

I am working with volley library in my android app development.
I have a base url and I need to append some value at the end of the url,click here,
So, this value "ZGxb87HuJK" keeps changing dynamically in my program and need to append this value at the end of url. How to add this in params?

Use this way.
StringRequest strreq = new StringRequest(Request.Method.GET,
"https://sample.com/testing/" + Hear Your dynamic value,
new Response.Listener<String>() {
#Override
public void onResponse(String Response) {
// get response
}
}, new Response.ErrorListener() {
#Override
public void onErrorResponse(VolleyError e) {
e.printStackTrace();
}
});
Volley.getInstance(this).addToRequestQueue(strreq);

String URL = "https://sample.com/testing/" + "dynamic value e.g ZGxb87HuJK";
JsonObjectRequest jsonObjReq = new JsonObjectRequest(Request.Method.GET,
URL, null,
new Response.Listener() {
#Override
public void onResponse(JSONObject response) {
//Success Callback
}
},
new Response.ErrorListener() {
#Override
public void onErrorResponse(VolleyError error) {
//Failure Callback
}
});
// Adding the request to the queue along with a unique string tag
MyApplication.getInstance().addToRequestQueue(jsonObjectReq, "getRequest");
Change your code like this

Volley pass a response outside of the class

I want to pass a response outside of my classes (many classes)
public static void userLocation()
{
RequestQueue queue = Volley.newRequestQueue(context);
String url = "http://www.jobdiagnosis.com/iphone/userlocation.php";
StringRequest dr = new StringRequest(Request.Method.GET, url,
new Response.Listener<String>()
{
#Override
public void onResponse(String response) {
// response
//Toast.makeText(context, ""+response, Toast.LENGTH_LONG).show();
}
},
new Response.ErrorListener()
{
#Override
public void onErrorResponse(VolleyError error) {
// error.
// Toast.makeText(getApplicationContext(), "error"+error, Toast.LENGTH_LONG).show();
Log.d("error", ""+error);
}
}
);
queue.add(dr);
}
Please suggest how I can pass a response outside of the class

In volly its difficult to return response outside the class.because request on server run in background and if we return value followed by queue.add(url) then it will return null.So there is no solution till now.Thanks!!