In my project i want to fetch all records from table with sort by created_date descending order.
Also i want to add condition of fetch all item not created_by login user.
I have tried many ways but not able to achieve it.
Below is my table structure.
Here is my java code to fetch records from dynamoDB.
Map<String, Condition> filter = new HashMap<String, Condition>();
//filter.put(RealmConstant.Expo.created_by, new Condition().withComparisonOperator(ComparisonOperator.NE).withAttributeValueList(new AttributeValue().withS(userId)));
filter.put(RealmConstant.Expo.created_date, new Condition().withComparisonOperator(ComparisonOperator.LE.toString()).withAttributeValueList(new AttributeValue().withS(""+new Date())));
Expo expo =new Expo();
expo.setCreated_by(userId);
DynamoDBQueryExpression<Expo> queryExpression = new DynamoDBQueryExpression<Expo>();
queryExpression.setHashKeyValues(expo);
queryExpression.setIndexName(AppConstant.DynamoDBTableIndex.created_by_created_date_index);
queryExpression.setConsistentRead(false);
queryExpression.setRangeKeyConditions(filter);
queryExpression.setScanIndexForward(false);
return mapper.query(Expo.class, queryExpression);
As per above code i am getting all records created by me only. I want to fetch all records not created by me.
Also tried .withFilterExpression("created_by <> :val1").withExpressionAttributeValues(eav); but not working. As already question posted. Why is there no **not equal** comparison in DynamoDB queries?
and
DynamoDB: Filter Expression can only contain non-primary key attributes
The short answer is that you can’t fetch *all the items from a DynamoDB table in sorted order, by any attribute. DynamoDB just doesn’t work that way.
Think of DynamoDB as a distributed hash map of lists.
Just the same as you can’t expect to be able to get globally sorted results from such a map of lists, you can’t get them from DynamoDB either.
You can scan the whole table, and even filter, out some unwanted results as you go, but for sorting, you need to do it after you’ve fetched the records.
What you can do is retrieve items that have the same partition key, in order or the sort key.
And you can create an index where you pick an arbitrary attribute as the partition key and another as the sort key but even that approach has some limitations.
The best way to go is to really take some time and think about what you are going to do with the data. Why are trying to retrieve all items from the table in sorted order? Perhaps there is a better way to organize your data such the you din’t need to retrieve all of it.
Related
I am using firebase realtime database to track the inventory on a track. I am doing something simple. As you can see in the image above an item has been added twice to the database instead of adding the quantities. How can I check that an item with a certain SKU and location_name already exists in the database?
If you want to store the inventory per product, and products have unique keys already, consider using that existing key in the database, instead of using push() to generate a new unique ID.
So where you now do something like:
db.push().setValue(objectForSkuPVC005PBPSTA);
Instead do:
db.child("PVC005PBPSTA").setValue(objectForSkuPVC005PBPSTA);
That way you can always update the child at db.child("PVC005PBPSTA") when you need to change its quantity.
A second unrelated point: you're storing the quantity as a string. I recommend storing it as an actual number, so that you can use numerical operations (such as the new ServerValue.increment()) to manipulate it.
This question already has an answer here:
Firebase query if child of child contains a value
(1 answer)
Closed 3 years ago.
I need a firebase query to filter the list based on the value of an array.
if any of the index of GID(Array) contains the given key. e.g my key is YsGMyfLSGRNHxDWQmhpuPRqtxlq1 and one node's GID have that on 0th index and other have that on 1st index. So these two lists need to be returned.
Currently, I can only get the one at 0th index using the code
//userID = YsGMyfLSGRNHxDWQmhpuPRqtxlq1
firebaseDatabase.child("Groups").queryOrdered(byChild: "GID/0").queryEqual(toValue:userID)
When I try to combine the query I am getting errors.
I don't know about your database structure, But I can explain that There is a limitation in Firebase Realtime database that you can only order by 1 child.
So now if we require to order by 2 Childs we can combine 2 nodes and make it 1 node and can apply order by query on it. For example
If we have username & email fields we can make a new field username_email and can apply order by on it.
Like
user: {
username: "john",
email: "john#g.com"
username_email = "john_john#g.com"
}
Now we can write
firebaseDatabase.child("user").queryOrdered(byChild: "username_email").queryEqual(toValue: "john_john#g.com");
There is no way you can filter your groups based on a value that exist within an array. If you want to query your database to get all groups a particular user is apart of, then you should consider augmenting your data structure to allow a reverse lookup. This means that you should add under each user object the groups in which that user is present.
This means that you'll need to duplicate some data, but this is not a problem when it comes to Firebase. This is a quite common practice, which is named denormalization and for that, I recommend you see this video, Denormalization is normal with the Firebase Database.
When you are duplicating data, there is one thing that need to keep in mind. In the same way you are adding data, you need to maintain it. With other words, if you want to update/detele an item, you need to do it in every place that it exists.
However, what you need is actually allowed in Cloud Firestore. Its array-contains operator allow you to filter documents that have a certain value in an array. For more on this topic, please see the following post:
Better Arrays in Cloud Firestore.
If we query data from Firebase on a key for a child node, does it downloads the whole child node and filter data in the application or it downloads the query specific data? i.e. the filtered data
String myUserId = getUid();
Query myTopPostsQuery = databaseReference.child("user-posts").child(myUserId).orderByChild("starCount");
myTopPostsQuery.addChildEventListener(new ChildEventListener() {});
myTopPostsQuery will sort data according to starCount and I will receive data in the addChildEventListener() I want to know that whether this data is being filtered inside my app after receiving or my app downloads only the filtered data from the Firebase.
If you use a filter in your query you will download the query specific data without any operation executed on the client side.
Keep in mind that:
You can only use one order-by method at a time. Calling an order-by method multiple times in the same query throws an error.
You can combine multiple limit or range functions. For example, you can combine the startAt() and endAt() methods to limit the results to a specified range of values.
For any other info take a read here
You get the data already filtered. When you use a query, let say, limitToLast(10) you get only those 10 elements. This is happening also in your case with orderByChild("starCount"). In your SnanpShot will find only those filtered elements. Please visit official doc for more details.
Hope it helps.
Based on the code you pasted here, your query will just retrieve all the posts for the database path user-posts/<id> with an ordered manner which means that there is not filter. But still you will get back all the available posts under the path you are querying. It can be a "semi-filter" as it will find only the posts which include starCount field
The best thing is to filter during your query in order to retrieve back exactly what is needed and not everything as you are doing right now, imagine that this list of posts can be really big so you will have a big issue with performance later.
Read the following section here about sorting & filtering.
https://firebase.google.com/docs/database/admin/retrieve-data#orderbychild
Apart from that consider to add an index in userId field for speeding up your query.
Lets assume I have a List of String (ex: List<String>). I want to match all the Strings in the List to a particular attribute already present in the Firebase Database. How do I achieve this, as the equalTo() query only accepts a single String. I also don't want to generate as many queries as the List size. Any help would be much appreciated.
I put my data in 3 tables(Links, Images and PDF)
each table has columns(university, faculty, grade, and description,...)
I want to retrieve description column in the 3 tables.
where university, faculty, and grade equal to certain values.
and sort them with creation date.
how can I perform that query in parse?
I'm not familiar with Android, but I'm pretty sure Parse does not support "Join" in the way a SQL database does. You could nest the queries, performing the next one in the previous one's completion block.
However, if you regularly want to get data from those 3 tables, I'd suggest you make it 1 table instead, with a column "Content" instead of Link/Img/PDF. Images and PDFs would probably be stored as PFFiles anyway, and you can put link as either its own string column or putting it in a file. You could also add a column "type" if you want to be able to query a specific type, or just keep track of which columns contains which data.
Then you could query the "Content" class, on the keys you want.
I think this link might help you
https://parse.com/docs/js/guide#relations and it is quite simple and nicely explained . You can't do it directly in the database, though.