My app crashes after I pressed a button.
My code:
<android.support.v7.widget.AppCompatButton
android:id="#+id/btn_print_trans"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="40dp"
android:onClick="OnClickPrintSimpleApiTest"
android:text="PRINT"
android:textColor="#FFFFFF" />
and:
public void OnClickPrintSimpleApiTest(View view) {
final Button BTN_print = (Button) findViewById(R.id.btn_print_trans);
BTN_print.setBackgroundColor(Color.GREEN);
BTN_print.setEnabled(false);
}
Because the OP defined the onClick method OnClickPrintSimpleApiTest as an attribute in their xml layout file as:
android:onClick="OnClickPrintSimpleApiTest"
They do not need to get a reference to the Button using findViewById().
The Button view is passed to the OnClickPrintSimpleApiTest() method as the parameter "view". Therefore, simply do this:
public void OnClickPrintSimpleApiTest(View view) {
Button BTN_print = (Button) view
BTN_print.setBackgroundColor(Color.GREEN);
BTN_print.setEnabled(false);
}
Related
Am trying to click on a button i just added to an AlertDialog but its not responding. The button is on a layout file in the resources folder and then i added this layout to the AlertDialog via the Builder method setView()
I accessed the same Button via my mainactivity after inflating a random view with the layout and set an OnClickListener but its still not working
Here is detail code of what i have tried so far
Layout containing the button
<LinearLayout
android:orientation="vertical"
xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent"
android:layout_height="match_parent">
<Button android:layout_gravity="center_horizontal"
android:layout_height="wrap_content"
android:layout_width="wrap_content"
android:textColor="#FFF"
android:background="#drawable/round2"
android:textSize="20sp"
android:textAlignment="center"
android:padding="5dp"
android:text="Submit"
android:textAllCaps="false"
android:drawablePadding="10sp"
android:id="#+id/submit"
/>
</Linearlayout>
Then in my MainActivity.class, i access the button this way
class MainActivity extends AppCompatActivity implements View.OnClickListener{
Button submit;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//inflate layout containing button
datView=getLayoutInflater().inflate(R.layout.data_entry,null);
//access button
submit=datView.findViewById(R.id.submit);
//set event listener
submit.setOnClickListener(this);
}
//the interface
#Override
public void onClick(View v) {
check();
}
//custom method check
private void check(){
Toast.makeText(this,"Registering data into database",Toast.LENGTH_LONG).show();
}
}
Despite all that the toast does not show on clicking the button, please help
Please try using android:onClick = "check" in the button in your xml, and also create a method in your MainActivity called public void check(View view){...} with the toast inside of it
I want to navigate two buttons to the same class. In one XML, I have two buttons, both should work the same way. How can I achieve this?
Define two button with different id and point to same function in onClick event
<Button
android:id="#+id/button1"
android:onClick="executeSameBehavior"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button1" />
<Button
android:id="#+id/button2"
android:onClick="executeSameBehavior"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button2" />
And then implement your logic here:
public void executeSameBehavior(View view) {
// Your logic
}
You can simply assign one clickListener interface to both setOnClickListeners
Button a = findViewById(R.id.a);
Button b = findViewById(R.id.b);
View.OnClickListener listener = new View.OnClickListener() {
#Override
public void onClick(View view) {
// Something for both
}
};
a.setOnClickListener(listener);
b.setOnClickListener(listener);
I have set the onClick property of an EditText which is located in a fragment:
<EditText android:id="#+id/edittext1" android:layout_width="wrap_content"
android:layout_height="wrap_content" android:inputType="none" android:maxLines="1"
android:singleLine="true" android:layout_marginTop="16dp"
android:focusable="false"
android:longClickable="false"
android:clickable="true"
android:onClick="doSomething"
android:cursorVisible="false"
android:editable="false">
Then in the fragment class I have:
public void doSomething(View view) {
//show dialogfragment...
}
But the method doSomething is grayed out and I get the warning 'Method doSomething is never used'.
Note: This code was originally in an activity and was working fine.
Is there another way to handle onClick in fragments?
first initialize an EditText instance in the top of your fragment
EditText et;
then
in your onCreateView()
add:
etEmployee=(EditText)rootView.findViewById(R.id.edittext1);
then implement your onClickListener()
et.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
//what ever you need to do goes here
}
});
Note: in fragments you have to refer to the inflatedView to be able to access your editText in this case rootView.
also the code you are using doesn't work becouse here you are using fragments and using onClick attribute in your xml would only make you able to use it in the MainActivity that contain your fragment.
hope this will help.
If you add android:onClick="doSomething" to your fragment then method will be invoked in your activity but not in Activity. If you want the callback in your fragment add through pragmatically.
edittext.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
// Your code.
}
});
You can always try to add a OnClickListener to the EditText if it does not matter to you in which way the function gets called.
edittext1 = (EditText) view.findViewById(R.id.edittext1);
edittext1.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
doSomething();
}
});
In your layout XML try specifying a tools:context="com.mypackage.path.MyFragment". Don't know if it'll fix it for 'onClick', but it has fixed similar issues for me in the past.
This goes in the top most 'ViewGroup' in your layout file, example:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
tools:context="com.mypackage.path.MyFragment" />
I have an application with an input text where the users have to insert an information and a button "+" beside to input text.
I would like to make my form dynamic in a way that when a user pushes on "+" button appears dynamically another text input and another "+" button beside this one, the process is repeated in the same way.
I created and xml file, sample_content:
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignLeft="#+id/attempt"
android:layout_alignParentBottom="true"
android:text="TextView" />
<Button
style="?android:attr/buttonStyleSmall"
android:layout_width="36dp"
android:layout_height="32dp"
android:layout_alignParentRight="true"
android:layout_alignParentTop="true"
android:layout_marginRight="22dp"
android:text="+" />
<EditText
android:layout_width="229dp"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_marginRight="14dp"
android:layout_toLeftOf="#+id/addKey"
android:background="#drawable/inputtext_corner"
android:ems="10"
android:textSize="18sp" >
<requestFocus />
</EditText>
</RelativeLayout>
and in my Activity, AddDeviceActivity I put:
inflater = LayoutInflater.from(AddDeviceActivity.this);
Button addKey = (Button) findViewById(R.id.addKey);
addKey.setOnClickListener(new Button.OnClickListener() {
public void onClick(View v) {
final RelativeLayout canvas = (RelativeLayout) AddDeviceActivity.this.findViewById(R.id.my_canvas);
final View childView = inflater.inflate(R.layout.sample_component, canvas, false);
// TODO: Look up the 5 different signatures of the addView method,
// and pick that best fits your needs
canvas.addView(childView);
}
});
But this solution doesn't work because when I add the first input text and the first button, I don't know how to make the second button work in my AddDeviceActivity dynamicly
Just wondering whether you can do this:
Have your activity implement OnClickListener and add this method to your activity:
public void onClick(View v) {
final RelativeLayout canvas = (RelativeLayout) AddDeviceActivity.this.findViewById(R.id.my_canvas);
final View childView = inflater.inflate(R.layout.sample_component, canvas, false);
canvas.addView(childView);
((Button)childView.findViewById(R.id.addKey)).setOnClickListener(AddDeviceActivity.this);
}
And then change your initial code to use
addKey.setOnClickListener(this);
instead of an anonymous inner class.
I haven't tested this, but don't see why it wouldn't work.
check out this, pass null instead of canvas object in inflate() method
addKey.setOnClickListener(new Button.OnClickListener() {
public void onClick(View v) {
final RelativeLayout canvas = (RelativeLayout) AddDeviceActivity.this.findViewById(R.id.my_canvas);
final View childView = inflater.inflate(R.layout.sample_component, null, false);
// TODO: Look up the 5 different signatures of the addView method,
// and pick that best fits your needs
canvas.addView(childView);
}
});
I have set linearlayer to become clickable and want it to act like a button and start a new activity. However i got error. Here are part of the .xml
<LinearLayout
android:id="#+id/llproduct1"
android:layout_width="fill_parent" android:layout_height="wrap_content"
android:orientation="vertical" android:clickable="true">
<ImageView .... />
<TextView .... />
</LinearLayout>
This is the .java
Button bProduct1 = (Button) findViewById(R.id.llproduct1);
bProduct1.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
// TODO Auto-generated method stub
startActivity(new Intent("com.testing.PRODUCTDESCRIPTION"));
}
What went wrong?
Button bProduct1 = (Button) findViewById(R.id.llproduct1);
you cannot cast your LinearLayout to a button. But you can do:
LinearLayout bProduct1 = (LinearLayout) findViewById(R.id.llproduct1);
bProduct1.setOnClickListener(...)
see this for reference
It is wrong class casting in "bProduct1 = (Button) findViewById(R.id.llproduct1); "
'llproduct1' is LinearLayout!! not a Button.
therefore the java code cause ClassCastException.
onClick method is declared in View class.
and both of LinearLayout and Button are inheriting View class.
so why don't you fix the code below.
View bProduct1 = findViewById(R.id.llproduct1);
bProduct1.setOnClickListener(......);