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How do I convert full String 10 + 20 - 25; like text, got from a EditText, to double? [duplicate]

This question already has answers here:
Convert String to operator(+*/-) in java
(5 answers)
Closed 4 years ago.
How I convert String containing Mathematic arithmetic operation's like "10 + 20 - 25", I am getting String from EditText,I want to convert get the Result of operation.

Here is my code to resolve your problem:
public class ExecuteHandler {
private static Character[] OPERATORS = { '/', '*', '+', '-' };
private static final String REGEXOPERATORS = "[/+,-,/*,//,-]";
private static final String REGEXDIGITS = "(\\d+)";
private ArrayList<Character> operators = new ArrayList<>();
private ArrayList<Integer> digits = new ArrayList<>();
public String execute(String math) {
StringBuilder result = new StringBuilder();
try {
getDigits(math);
getOperators(math);
getNextOperator(operators);
for (Integer digit : digits) {
result.append(String.valueOf(digit));
}
} catch (ArithmeticException | IndexOutOfBoundsException e) {
return "ERROR";
}
return result.toString().isEmpty() ? "ERROR" : result.toString();
}
public void clear() {
operators.clear();
digits.clear();
}
private void getNextOperator(ArrayList<Character> operators) {
for (Character op : OPERATORS) {
for (int i = 0; i < operators.size(); i++) {
if (operators.get(i) == '/') {
operators.remove(i);
digits.set(i, (digits.get(i) / digits.get(i + 1)));
digits.remove(i + 1);
i -= 1;
}
}
for (int i = 0; i < operators.size(); i++) {
if (operators.get(i) == '*') {
operators.remove(i);
digits.set(i, (digits.get(i) * digits.get(i + 1)));
digits.remove(i + 1);
i -= 1;
}
}
for (int i = 0; i < operators.size(); i++) {
if (operators.get(i) == '+') {
operators.remove(i);
digits.set(i, (digits.get(i) + digits.get(i + 1)));
digits.remove(i + 1);
i -= 1;
}
}
for (int i = 0; i < operators.size(); i++) {
if (operators.get(i) == '-') {
operators.remove(i);
digits.set(i, (digits.get(i) - digits.get(i + 1)));
digits.remove(i + 1);
i -= 1;
}
}
}
}
private void getDigits(String math) {
Pattern r = Pattern.compile(REGEXDIGITS);
Matcher m = r.matcher(math);
while (m.find()) {
int t = Integer.parseInt(math.substring(m.start(), m.end()));
digits.add(t);
}
}
private void getOperators(String math) {
Pattern r = Pattern.compile(REGEXOPERATORS);
Matcher m = r.matcher(math);
while (m.find()) {
operators.add(math.charAt(m.start()));
}
}
}
Call method execute with input is string like "10 + 20 - 25:", the result will be a string of value (if success) or ERROR (if any syntax error).

Filter number from Array of string and get the index of last two greater number in android

I have a ArrayList that has value like [Value,Sum3,121,data8input,in:21::7,7.00,9.01] and I want to extract only number as the output should be like this [3,121,8,21,7,7.00,9.01] and then have to rearrange ascending and then get the index of last two number as result will be [21,121].
My tried code below,
for (int i = 0; i < arrayString.size(); i++) {
Pattern p = Pattern.compile("-?\\d+(,\\d+)*?\\.?\\d+?");
List<String> numbers = new ArrayList<String>();
Matcher m = p.matcher(arrayString.get(i).getvalue);
numbers.addAll(m);
for (int j = 0; j < numbers.size(); j++) {
Log.d("REMEMBERFILTER", allCollection.get(i).getTextValue());
}
}
}

do something like this, though it is not exactly memory efficient as I am using another list.
ArrayList<String> tempList = new ArrayList<>();
for (int i = 0; i < yourArrayList.size(); i++) {
tempList.add(yourArrayList.get(i).replaceAll("[^0-9]", ""));
}
//Arrange in ascending order
Collections.sort(tempList);
//Also try to remove those indexes which has only letters with
tempList.removeAll(Arrays.asList("", null));
for (int i = 0; i < tempList.size(); i++) {
Log.d("+++++++++", "" + tempList.get(i));
}
//You can get the last two or any element by get method of list by //list.size()-1 and list.size()-2 so on

This is a way to do it, finalArray has the 2 numbers you want:
String[] str = new String[] {"Value", "Sum3", "121", "data8input", "in:21::7", "7.00,9.01"};
StringBuilder longStringBuilder = new StringBuilder();
for (String s : str) {
longStringBuilder.append(s).append(" ");
}
String longString = longStringBuilder.toString();
String onlyNumbers = " " + longString.replaceAll("[^0-9.]", " ") + " ";
onlyNumbers = onlyNumbers.replaceAll(" \\. ", "").trim();
while (onlyNumbers.indexOf(" ") > 0) {
onlyNumbers = onlyNumbers.replaceAll(" ", " ");
}
String[] array = onlyNumbers.split(" ");
Double[] doubleArray = new Double[array.length];
for (int i = 0; i < array.length; i++) {
try {
doubleArray[i] = Double.parseDouble(array[i]);
} catch (NumberFormatException e) {
e.printStackTrace();
doubleArray[i] = 0.0;
}
}
Arrays.sort(doubleArray);
int numbersCount = doubleArray.length;
Double[] finalArray;
if (numbersCount >= 2) {
finalArray = new Double[]{doubleArray[numbersCount - 2], doubleArray[numbersCount - 1]};
} else if (numbersCount == 1) {
finalArray = new Double[]{ doubleArray[0]};
} else {
finalArray = new Double[]{};
}
for (Double number : finalArray) {
System.out.println(number);
}

Comparison of app version

How to compare app version in android
I got latest version code and current version code , but the problem is
current version is 1.0
and latest version is 1.0.0
so how to compare that float value in android

I have written a small Android library for comparing version numbers: https://github.com/G00fY2/version-compare
What it basically does is this:
public int compareVersions(String versionA, String versionB) {
String[] versionTokensA = versionA.split("\\.");
String[] versionTokensB = versionB.split("\\.");
List<Integer> versionNumbersA = new ArrayList<>();
List<Integer> versionNumbersB = new ArrayList<>();
for (String versionToken : versionTokensA) {
versionNumbersA.add(Integer.parseInt(versionToken));
}
for (String versionToken : versionTokensB) {
versionNumbersB.add(Integer.parseInt(versionToken));
}
final int versionASize = versionNumbersA.size();
final int versionBSize = versionNumbersB.size();
int maxSize = Math.max(versionASize, versionBSize);
for (int i = 0; i < maxSize; i++) {
if ((i < versionASize ? versionNumbersA.get(i) : 0) > (i < versionBSize ? versionNumbersB.get(i) : 0)) {
return 1;
} else if ((i < versionASize ? versionNumbersA.get(i) : 0) < (i < versionBSize ? versionNumbersB.get(i) : 0)) {
return -1;
}
}
return 0;
}
This snippet doesn't offer any error checks or handling. Beside that my library also supports suffixes like "1.2-rc" > "1.2-beta".

I am a bit late to the party but I have a great solution for all of you!
1. Use this class:
public class VersionComparator implements Comparator {
public boolean equals(Object o1, Object o2) {
return compare(o1, o2) == 0;
}
public int compare(Object o1, Object o2) {
String version1 = (String) o1;
String version2 = (String) o2;
VersionTokenizer tokenizer1 = new VersionTokenizer(version1);
VersionTokenizer tokenizer2 = new VersionTokenizer(version2);
int number1, number2;
String suffix1, suffix2;
while (tokenizer1.MoveNext()) {
if (!tokenizer2.MoveNext()) {
do {
number1 = tokenizer1.getNumber();
suffix1 = tokenizer1.getSuffix();
if (number1 != 0 || suffix1.length() != 0) {
// Version one is longer than number two, and non-zero
return 1;
}
}
while (tokenizer1.MoveNext());
// Version one is longer than version two, but zero
return 0;
}
number1 = tokenizer1.getNumber();
suffix1 = tokenizer1.getSuffix();
number2 = tokenizer2.getNumber();
suffix2 = tokenizer2.getSuffix();
if (number1 < number2) {
// Number one is less than number two
return -1;
}
if (number1 > number2) {
// Number one is greater than number two
return 1;
}
boolean empty1 = suffix1.length() == 0;
boolean empty2 = suffix2.length() == 0;
if (empty1 && empty2) continue; // No suffixes
if (empty1) return 1; // First suffix is empty (1.2 > 1.2b)
if (empty2) return -1; // Second suffix is empty (1.2a < 1.2)
// Lexical comparison of suffixes
int result = suffix1.compareTo(suffix2);
if (result != 0) return result;
}
if (tokenizer2.MoveNext()) {
do {
number2 = tokenizer2.getNumber();
suffix2 = tokenizer2.getSuffix();
if (number2 != 0 || suffix2.length() != 0) {
// Version one is longer than version two, and non-zero
return -1;
}
}
while (tokenizer2.MoveNext());
// Version two is longer than version one, but zero
return 0;
}
return 0;
}
// VersionTokenizer.java
public static class VersionTokenizer {
private final String _versionString;
private final int _length;
private int _position;
private int _number;
private String _suffix;
private boolean _hasValue;
VersionTokenizer(String versionString) {
if (versionString == null)
throw new IllegalArgumentException("versionString is null");
_versionString = versionString;
_length = versionString.length();
}
public int getNumber() {
return _number;
}
String getSuffix() {
return _suffix;
}
public boolean hasValue() {
return _hasValue;
}
boolean MoveNext() {
_number = 0;
_suffix = "";
_hasValue = false;
// No more characters
if (_position >= _length)
return false;
_hasValue = true;
while (_position < _length) {
char c = _versionString.charAt(_position);
if (c < '0' || c > '9') break;
_number = _number * 10 + (c - '0');
_position++;
}
int suffixStart = _position;
while (_position < _length) {
char c = _versionString.charAt(_position);
if (c == '.') break;
_position++;
}
_suffix = _versionString.substring(suffixStart, _position);
if (_position < _length) _position++;
return true;
}
}
}
2. create this function
private fun isNewVersionAvailable(currentVersion: String, latestVersion: String): Boolean {
val versionComparator = VersionComparator()
val result: Int = versionComparator.compare(currentVersion, latestVersion)
var op = "=="
if (result < 0) op = "<"
if (result > 0) op = ">"
System.out.printf("%s %s %s\n", currentVersion, op, latestVersion)
return if (op == ">" || op == "==") {
false
} else op == "<"
}
3. and just call it by
e.g. isNewVersionAvailable("1.2.8","1.2.9") where 1.2.8 is your current version here and 1.2.9 is the latest version, which returns true!

Why overcomplicate this so much?
Just scale the major, minor, patch version and you have it covered:
fun getAppVersionFromString(version: String): Int { // "2.3.5"
val versions = version.split(".") // [2, 3, 5]
val major = versions[0].toIntOrDefault(0) * 10000 // 20000
val minor = versions[1].toIntOrDefault(0) * 1000 // 3000
val patch = versions[2].toIntOrDefault(0) * 100 // 500
return major + minor + patch // 2350
}
That way when you compare e.g 9.10.10 with 10.0.0 the second one is greater.

Use the following method to compare the versions number:
Convert float to String first.
public static int versionCompare(String str1, String str2) {
String[] vals1 = str1.split("\\.");
String[] vals2 = str2.split("\\.");
int i = 0;
// set index to first non-equal ordinal or length of shortest version string
while (i < vals1.length && i < vals2.length && vals1[i].equals(vals2[i])) {
i++;
}
// compare first non-equal ordinal number
if (i < vals1.length && i < vals2.length) {
int diff = Integer.valueOf(vals1[i]).compareTo(Integer.valueOf(vals2[i]));
return Integer.signum(diff);
}
// the strings are equal or one string is a substring of the other
// e.g. "1.2.3" = "1.2.3" or "1.2.3" < "1.2.3.4"
return Integer.signum(vals1.length - vals2.length);
}
Refer the following SO question : Efficient way to compare version strings in Java

for loop overextending index

I'm attempting to iterate through the EditText "name" and check the letters so see if they match any of the letters in the objects of the array uNamesList.
If they do I want to break out of the loop and return the placement of the object that had the matching letter. At the moment I am getting this error, anyone know what might be wrong?
java.lang.StringIndexOutOfBoundsException: length=9; index=9
uNamesList.add("bob");
uNamesList.add("mike");
uNamesList.add("sike");
uNamesList.add("othername");
uNamesList.add("name");
public int getName(EditText name) {
String text = name.getText().toString();
for (int i = 0; i < text.length(); i++) { //i = current letter in text
char cLetter = name.toString().charAt(i);
for (int o = 0; o < uNamesList.size(); o++) {
String uName = (String)uNamesList.get(o);
char uLetter = uName.charAt(i);
if (cLetter == uLetter) {
match = o;
break;
}
}
}
return match;
}

You get the text inside edit text in wrong way. it should :
public int getName(EditText name) {
String text = name.getText(); //get the text
int match = 10;
for (int i = 0; i < text.toString().length(); i++) { //get the length of the text
for (int o = 0; o < uNamesList.size(); o++) {
char cLetter = name.toString().charAt(i);
String uName = (String)uNamesList.get(o);
Okay, here's the edit for another problem. i dont know if this what you want.
public int getName(EditText name) {
int match = 9999;
String text = name.getText().toString();
boolean found = false;
for (int i = 0; i < text.length(); i++) { //i = current letter in text
char cLetter = name.toString().charAt(i);
for (int o = 0; o < uNamesList.size(); o++) {
String uName = (String)uNamesList.get(o);
char uLetter = uName.charAt(i);
if (cLetter == uLetter) {
match = o;
found = true;
break;
}
}
if(found) break;
}
return match;
}
The simplest way is just only call return when it found.
public int getName(EditText name) {
int match = 9999;
String text = name.getText().toString();
for (int i = 0; i < text.length(); i++) { //i = current letter in text
char cLetter = name.toString().charAt(i);
for (int o = 0; o < uNamesList.size(); o++) {
String uName = (String)uNamesList.get(o);
char uLetter = uName.charAt(i);
if (cLetter == uLetter) {
return o;
}
}
}
return match;
}

change your for loop to the following, you accessing name from the uNameList loop where the length might be different
for (int i = 0; i < name.toString().length(); i++) {
char cLetter = name.toString().charAt(i);
for (int o = 0; o < uNamesList.size(); o++) {

For EditText you need GetText()
name.toString() gives you the java desciption of the object EditText

You are getting a StringIndexOutOfBoundsException most likely due to this line:
char uLetter = uName.charAt(i);
i in this case can be greater than the length of uName

regular-expressions android

i have string like these for example
309\306\308\337_338
309\306\337_338
310
311\315_316\336_337
311\315_316\336_337
311\335_336
these strings means list of page number , for example string "309\306\308\337_339" means
pages 309,306,308,337,338,339
i want to pass one of these string to function which return it as string like this
309,306,308,337,338,339
this function do that but in c# , i want to impalement in android
private static string Get_PageNumbers(string str)
{
ArrayList arrAll = new ArrayList();
MatchCollection match;
string[] excar;
string strid, firstNumber, lastlNumber;
int fn, ln;
ArrayList arrID = new ArrayList();
//***In Case The Range Number Between "_"
if (str.Contains("_"))
{
// match_reg = new Regex("(w?[\\d]+)*(_[\\d]+)");
Regex matchReg = new Regex("(w?[\\69]+_[\\d]+)*(q?[\\d]+//)*(a?[\\d]+_[\\d]+)*(y?[\\d]+)*");
match = matchReg.Matches(str);
int count = match.Count;
excar = new string[0];
for (int i = 0; i < count; i++)
{
Array.Resize(ref excar, count);
excar[i] = match[i].Groups[0].Value;
if (excar[i] != string.Empty)
arrID.Add(excar[i]);
}
//******IF Array Contains Range Of Number Like"102_110"
if (str.Contains("_"))
{
for (int i = 0; i < arrID.Count; i++)
{
strid = arrID[i].ToString();
if (arrID[i].ToString().Contains("_"))
{
int idy = strid.LastIndexOf("_");
firstNumber = strid.Substring(0, idy);
if (idy != -1)
{
lastlNumber = strid.Substring(idy + 1);
fn = int.Parse(firstNumber);
arrAll.Add(fn);
ln = int.Parse(lastlNumber);
for (int c = fn; c < ln; c++)
{
fn++;
arrAll.Add(fn);
}
}
}
else
{
arrAll.Add(arrID[i].ToString());
}
}
//******If Array Contain More Than One Number
if (arrAll.Count > 0)
{
str = "";
for (int i = 0; i < arrAll.Count; i++)
{
if (str != string.Empty)
str = str + "," + arrAll[i];
else
str = arrAll[i].ToString();
}
}
}
}
//***If string Contains between "/" only without "_"
else if (str.Contains("/") && !str.Contains("_"))
{
str = str.Replace("/", ",");
}
else if (str.Contains("\\"))
{
str = str.Replace("\\", ",");
}
return str;
}

I think this is easier to do with split function:
public static String Get_PageNumbers(String str) {// Assume str = "309\\306\\308\\337_338"
String result = "";
String[] pages = str.split("\\\\"); // now we have pages = {"309","306","308","337_338"}
for (int i = 0; i < pages.length; i++) {
String page = pages[i];
int index = page.indexOf('_');
if (index != -1) { // special case i.e. "337_338", index = 3
int start = Integer.parseInt(page.substring(0, index)); // start = 337
int end = Integer.parseInt(page.substring(index + 1)); // end = 338
for (int j = start; j <= end; j++) {
result += String.valueOf(j);
if (j != end) { // don't add ',' after last one
result += ",";
}
}
} else { // regular case i.e. "309","306","308"
result += page;
}
if (i != (pages.length-1)) { // don't add ',' after last one
result += ",";
}
}
return result; // result = "309,306,308,337,338"
}
For example this function when called as follows:
String result1 = Get_PageNumbers("309\\306\\308\\337_338");
String result2 = Get_PageNumbers("311\\315_316\\336_337");
String result3 = Get_PageNumbers("310");
Returns:
309,306,308,337,338
311,315,316,336,337
310

if i can suggest different implementation....
first, split string with "\" str.split("\\");, here you receive an array string with single number or a pattern like "num_num"
for all string founded, if string NOT contains "" char, put string in another array (othArr named), than, you split again with "" str.split("_");, now you have a 2 position array
convert that 2 strings in integer
now create a loot to min val form max val or two strings converted (and put it into othArr)
tranform othArr in a string separated with ","