I want to comapare two textbox values words by words and check if the words are same or not. If its not same then it should tell me the percentage of matching words.
For example : I am a good boy(text box1)
Am a god boy (text box 2)
Then the result should be (3/5)*100 as 2 words are not matching that is I and good.
Please tell me how to do this.
here is a code as you want
public class Test {
public static void main(String[] args) {
String str1 = "I am a good boy";
String [] s_str1 = str1.split(" ");
String str2 = "Am a god boy";
String [] s_str2 = str2.split(" ");
int match = 0;
for(int i=0;i<s_str1.length;i++){
for(int j=0;j<s_str2.length;j++){
if(s_str1[i].equalsIgnoreCase(s_str2[j])){
match++;
}
}
}
int result = match*100/s_str1.length; //use length of string which is
your main str
System.out.println(result);
}
}
Try this:
int getCommonWords(String s1, String s2) {
Set<String> set1 = new HashSet<>(Arrays.asList(s1.split(" ")));
Set<String> set2 = new HashSet<>(Arrays.asList(s2.split(" ")));
set1.retainAll(set2);
return set1.size();
}
returns the number of common words between 2 strings. It is case-sensitive.
Related
I want to get a text that it is a part of an string.For example: I have a string like "I am Vahid" and I want to get everything that it's after "am".
The result will be "Vahid"
How can I do it?
Try:
Example1
String[] separated = CurrentString.split("am");
separated[0]; // I am
separated[1]; // Vahid
Example2
StringTokenizer tokens = new StringTokenizer(CurrentString, "am");
String first = tokens.nextToken();// I am
String second = tokens.nextToken(); //Vahid
Try:
String text = "I am Vahid";
String after = "am";
int index = text.indexOf(after);
String result = "";
if(index != -1){
result = text.substring(index + after.length());
}
System.out.print(result);
Just use like this, call the method with your string.
public String trimString(String stringyouwanttoTrim)
{
if(stringyouwanttoTrim.contains("I am")
{
return stringyouwanttoTrim.split("I am")[1].trim();
}
else
{
return stringyouwanttoTrim;
}
}
If you prefer to split your sentence by blank space you could do like this :
String [] myStringElements = "I am Vahid".split(" ");
System.out.println("your name is " + myStringElements[myStringElements.length - 1]);
I am creating and android app that randomly generates any category, I would like to get the given random category word. This is the example string
String="The category Animals that starts with a letter J";
or
String="The category Colors that starts with a letter V";
I need to get the word Animals or Colors every random String is generated
A not so advanced solution, but easy to understand:
public void findCategory() {
String string = "The category Colors that starts with a letter V";
String[] split = string.split(" ");
int i;
for (i = 0; i < split.length; i++) {
if ("category".equals(split[i])) {
break;
}
}
System.out.println(split[i + 1]);
}
You may use regex.
Matcher m = Pattern.compile("\\bcategory\\s+(\\S+)").matcher(str);
while(m.find()) {
System.out.println(m.group(1));
}
OR
Matcher m = Pattern.compile("(?<=\\bcategory\\s)\\S+").matcher(str);
while(m.find()) {
System.out.println(m.group());
}
Please use Matcher and Pattern -
String input = "The category Animals that starts with a letter J";
Matcher m1 = Pattern.compile("^The category (.*) that starts with a letter (.*)$").matcher(input);
if(m1.find()) {
String _thirdWord = m1.group(1); // Animals
String _lastWord = m1.group(2); // J
System.out.println("Third word : "+_thirdWord);
System.out.println("Last Word : "+_lastWord);
}
Use this, it might fix your issue
String string = "The category Colors that starts with a letter V";
String[] ar = string.split(" ");
System.out.println(ar[2]);
I am trying to remove special character from arraylist.
Not getting click how to do this?
I have 3 editfield and filling text after certain conditions
means when 1 is filled then another can be filled. now when i click to save this. this returns an array like [hello,abc,zbz] for fields
private List<String> hashtagData;
hashtagData = new ArrayList<String>();
String status_message = status.getText().toString();
String status_message2 = status2.getText().toString();
String status_message3 = status3.getText().toString();
hashtagData.add(status_message);
hashtagData.add(status_message2);
hashtagData.add(status_message3);
But I am trying to remove "[]".
Thank you if anybody can help.
Here try this:
ArrayList<String> strCol = new ArrayList<String>();
strCol.add("[a,b,c,d,e]");
strCol.add(".a.a.b");
strCol.add("1,2,].3]");
for (String string : strCol) {
System.out.println(removeCharacter(string));
}
private String removeCharacter(String word) {
String[] specialCharacters = { "[", "}" ,"]",",","."};
StringBuilder sb = new StringBuilder(word);
for (int i = 0;i < sb.toString().length() - 1;i++){
for (String specialChar : specialCharacters) {
if (sb.toString().contains(specialChar)) {
int index = sb.indexOf(specialChar);
sb.deleteCharAt(index);
}
}
}
return sb.toString();
}
Create regex which matches with your criteria, then loop through your list.
String myRegex = "[^a-zA-Z0-9]";
int index = 0;
for (String your_string : list)
list.set(index++, s.replaceAll(myRegex, ""));
can use below function to remove special character from string using regular expressions.
using System.Text;
using System.Text.RegularExpressions;
public string RemoveSpecialCharacters(string str)
{
return Regex.Replace(str, "[^a-zA-Z0-9_.]+", "", RegexOptions.Compiled);
}
I have a String separated by commas as follows
1,2,4,6,8,11,14,15,16,17,18
This string is generated upon user input. Suppose the user wants to remove any of the numbers, I have to rebuild the string without the specified number.
If the current string is:
1,2,4,6,8,11,14,15,16,17,18
User intents to remove 1, the final string has to be:
2,4,6,8,11,14,15,16,17,18
I tried to achieve this using the following code:
//String num will be the number to be removed
old = tv.getText().toString(); //old string
newString = old.replace(num+",",""); //will be the new string
This might be working sometimes but it is sure that it won't work for the above example I have shown, if I try to remove the 1, it also removes the last part of 11, because there also exists 1.
well you can use this. Its the most simplest approach i can think of:
//String num will be the number to be removed
old=","+tv.getText().toString()+",";//old string commas added to remove trailing entries
newString=old.replace(","+num+",",",");// will be the new string
newString=newString.substring(1,newString.length()-1); // removing the extra commas added
This would work for what you want to do. I have added a comma at the start and end of your string so that you can also remove the first and last entries too.
You can split the string first and check for the number where you append those value that is not equivalent to the number that will get deleted;
sample:
String formated = "1,2,4,6,8,11,14,15,16,17,18";
String []s = formated.split(",");
StringBuilder newS = new StringBuilder();
for(String s2 : s)
{
if(!s2.equals("1"))
newS.append(s2 + ",");
}
if(newS.length() >= 1)
newS.deleteCharAt(newS.length() - 1);
System.out.println(newS);
result:
2,4,6,8,11,14,15,16,17,18
static public String removeItemFromCommaDelimitedString(String str, String item)
{
StringBuilder builder = new StringBuilder();
int count = 0;
String [] splits = str.split(",");
for (String s : splits)
{
if (item.equals(s) == false)
{
if (count != 0)
{
builder.append(',');
}
builder.append(s);
count++;
}
}
return builder.toString();
}
String old = "1,2,4,6,8,11,14,15,16,17,18";
int num = 11;
String toRemove = "," + num + "," ;
String oldString = "," + old + ",";
int index = oldString.indexOf(toRemove);
System.out.println(index);
String newString = null;
if(index > old.length() - toRemove.length() + 1){
newString = old.substring(0, index - 1);
}else{
newString = old.substring(0, index) + old.substring(index + toRemove.length() -1 , old.length());
}
System.out.println(newString);
In my project I need to store the values dynamically in a string and need to split that string with ",". How can I do that ? Please help me..
My Code:
static ArrayList<ArrayList<String>> listhere;
ArrayList<String> arropids;
String arropids1;
for(int q=0;q<listhere.size();q++)
{
arropids = listhere.get(q);
if(arropids.get(3).equals("1"))
{
arropids1 += arropids.get(0) + ",";
System.out.println("arropids1"+arropids1);
}
}
You must be getting NullPointerException as you havent initialized the String, initialize it as
String arropids1="";
It will resolve your issue, but I dont Recommend String for this task, as String is Immutable type, you can use StringBuffer for this purpose, so I recommend following code:
static ArrayList<ArrayList<String>> listhere;
ArrayList<String> arropids;
StringBuffer buffer=new StringBuffer();
for(int q=0;q<listhere.size();q++)
{
arropids = listhere.get(q);
if(arropids.get(3).equals("1"))
{
buffer.append(arropids.get(0));
buffer.append(",");
System.out.println("arropids1"+arropids1);
}
}
and finally get String from that buffer by:
String arropids1=buffer.toString();
In order to split the results after storing your parse in the for loop, you use the split method on your stored string and set that equal to a string array like this:
static ArrayList<ArrayList<String>> listhere;
ArrayList<String> arropids;
String arropids1 = "";
for(int q=0;q<listhere.size();q++) {
arropids = listhere.get(q);
if(arropids.get(3).equals("1"))
{
arropids1 += arropids.get(0) + ",";
System.out.println("arropids1"+arropids1);
}
}
String[] results = arropids1.split(",");
for (int i =0; i < results.length; i++) {
System.out.println(results[i]);
}
I hope that this is what you're looking for.