Android programming imei getDeviceID(telephonymanager)

Android programming imei getDeviceID(telephonymanager) - android

How can I get IMEI number up to API level 19 (kitkat) in Android programming?
I have used getDeviceID(telephonyManager) but it is working only up to API 22 not below for API level 19.
Is there any other function that can be used?

You may try this:
TelephonyManager telephonyManager = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (ActivityCompat.checkSelfPermission(context,
Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return;
}
String IMEI_Number = telephonyManager.getDeviceId();
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
String Imei0Id = telephonyManager.getDeviceId(0); // hear 0 is slot number
if (null != Imei0Id && !Imei0Id.equals("000000000000000")) {
IMEI_Number = Imei0Id;
}
}
also check this link for good concept
https://developer.android.com/reference/android/telephony/TelephonyManager
on left side you found API Level Option that I mentioned in below picture by red mark.
It will shows which are used by or not.

Related

How to Get IMEI or Serial Number for Android 10+ [duplicate]

I am getting the IMEI ID null from the telephonymanager. What to do?
is there any workaround for that?

Android Q has restricted to access for both IMEI and serial no. It is available only for platform and apps with special carrier permission. Also the permission READ_PRIVILEGED_PHONE_STATE is not available for non platform apps.
If you try to access it throws below exception
java.lang.SecurityException: getImeiForSlot: The user 10180 does not meet the requirements to access device identifiers.
Please refer documentation:
https://developer.android.com/preview/privacy/data-identifiers#device-ids
Also refer Issue

I am late to post answer. I still believe my answer will help someone.
Android 10 Restricted developer to Access IMEI number.
You can have a alternate solution by get Software ID. You can use software id as a unique id. Please find below code as i use in Application.
public static String getDeviceId(Context context) {
String deviceId;
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null) {
deviceId = mTelephony.getDeviceId();
} else {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
}
}
return deviceId;
}

This just would not work as of Android Q. Third party apps can not use IMEI nor the serial number of a phone and other non-resettable device identifiers.
The only permissions that are able to use those is READ_PRIVILEGED_PHONE_STATE and that cannot be used by any third party apps - Manufacture and Software Applications. If you use that method you will get an error Security exception or get null .
You can still try to get a unique id by using:
import android.provider.Settings.Secure;
private String android_id = Secure.getString(getContext().getContentResolver(),Secure.ANDROID_ID);

The best way to get the IMEI number is as follows:
public static String getIMEIDeviceId(Context context) {
String deviceId;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q)
{
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (context.checkSelfPermission(Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return "";
}
}
assert mTelephony != null;
if (mTelephony.getDeviceId() != null)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)
{
deviceId = mTelephony.getImei();
}else {
deviceId = mTelephony.getDeviceId();
}
} else {
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
Log.d("deviceId", deviceId);
return deviceId;
}
Just copy the method and use it. It will definitely. However, you might know you can't get IMEI in android Q (version 10). In this code, you can get a unique identifier (alternative id) through any device or any API level.
It works 100%
Thank You!!
And Enjoy Coding :)

As the best practices suggest. " you can avoid using hardware identifiers, such as SSAID (Android ID) and IMEI, without limiting required functionality."
Rather go for an instance ID such as String uniqueID = UUID.randomUUID().toString(); or FirebaseInstanceId.getInstance().getId();

Not sure about IMEI number, but you can get the simSerialNumber and other carrier info this way.
getSimSerialNumber() needs privileged permissions from Android 10 onwards, and third party apps can't register this permission.
See : https://developer.android.com/about/versions/10/privacy/changes#non-resettable-device-ids
A possible solution is to use the TELEPHONY_SUBSCRIPTION_SERVICE from Android 5.1, to retrieve the sim serial number. Steps below:
Check for READ_PHONE_STATE permission.
Get Active subscription list.( Returns the list of all active sim cards)
Retrieve the sim details from Subscription Object.
if ( isPermissionGranted(READ_PHONE_STATE) ) {
String simSerialNo="";
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) {
SubscriptionManager subsManager = (SubscriptionManager) context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE);
List<SubscriptionInfo> subsList = subsManager.getActiveSubscriptionInfoList();
if (subsList!=null) {
for (SubscriptionInfo subsInfo : subsList) {
if (subsInfo != null) {
simSerialNo = subsInfo.getIccId();
}
}
}
} else {
TelephonyManager tMgr = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
simSerialNo = tMgr.getSimSerialNumber();
}
}
Check if this helps

you can change other way, i use uuid to replace devices id.
String uniquePseudoID = "35" +
Build.BOARD.length() % 10 +
Build.BRAND.length() % 10 +
Build.DEVICE.length() % 10 +
Build.DISPLAY.length() % 10 +
Build.HOST.length() % 10 +
Build.ID.length() % 10 +
Build.MANUFACTURER.length() % 10 +
Build.MODEL.length() % 10 +
Build.PRODUCT.length() % 10 +
Build.TAGS.length() % 10 +
Build.TYPE.length() % 10 +
Build.USER.length() % 10;
String serial = Build.getRadioVersion();
String uuid = new UUID(uniquePseudoID.hashCode(), serial.hashCode()).toString();
AppLog.d("Device ID",uuid);

If your app targets Android 10 or higher, a SecurityException occurs.
Following modules are affected...
Build
getSerial()
TelephonyManager
getImei()
getDeviceId()
getMeid()
getSimSerialNumber()
getSubscriberId()
So you cant get IMEI no for android 10 , You have to used another unique identifier for this like Android ID
It unique 64 bit hex no for device
private String android_id = Secure.getString(getContext().getContentResolver(),
Secure.ANDROID_ID);

According to google docs.
Restriction on non-resettable device identifiers
Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
Caution: Third-party apps installed from the Google Play Store cannot
declare privileged permissions.
So, Instead of imei you can get Android unique ID.
String imei = "";
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (checkSelfPermission(Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
try {
imei = telephonyManager.getImei();
} catch (Exception e) {
e.printStackTrace();
imei = Settings.Secure.getString(this.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
} else {
if (ActivityCompat.checkSelfPermission(MainActivity.this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
imei = telephonyManager.getDeviceId();
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
}

Targeting Android Q, third party apps can't access IMEI at all. Android Q doc is misleading while stating
Starting in Android Q, apps must have the READ_PRIVILEGED_PHONE_STATE
privileged permission in order to access the device's non-resettable
identifiers, which include both IMEI and serial number.
https://developer.android.com/preview/privacy/data-identifiers#device-ids
But when I actually tried to implement it, I am receiving this exception:
java.lang.SecurityException: getDeviceId: The user 10132 does not meet the requirements to access device identifiers.
Someone had reported this on google's issue tracker where a Googler said that this is intended behaviour and IMEI on Q+ is only available for system level apps.
Status: Won't Fix (Intended Behavior) This is Working As Intended.
IMEI is a personal identifier and this is not given out to apps as a
matter of policy. There is no workaround.
https://issuetracker.google.com/issues/129583175#comment10

They mentioned:
If your app is the device or profile owner app, you need only the READ_PHONE_STATE permission to access non-resettable device identifiers, even if your app targets Android 10 or higher.
I tried deploying via EMM as device owner app but not success.

If you needed, you can try to install a work profile in to the mobile phone and include your app in the same package or vice versa.
I tried and it works, it's simple if yo follow this repo: https://github.com/googlesamples/android-testdpc
When you install the Work Profile your app is installed in this profile and you will have acces to the IMEI.
And now there is another example fixed yesterday to Android 10:
https://github.com/android/enterprise-samples/pull/29

Android API 29 Permission Error READ_PRIVILEGED_PHONE_STATE [duplicate]

I am getting the IMEI ID null from the telephonymanager. What to do?
is there any workaround for that?

Android Q has restricted to access for both IMEI and serial no. It is available only for platform and apps with special carrier permission. Also the permission READ_PRIVILEGED_PHONE_STATE is not available for non platform apps.
If you try to access it throws below exception
java.lang.SecurityException: getImeiForSlot: The user 10180 does not meet the requirements to access device identifiers.
Please refer documentation:
https://developer.android.com/preview/privacy/data-identifiers#device-ids
Also refer Issue

I am late to post answer. I still believe my answer will help someone.
Android 10 Restricted developer to Access IMEI number.
You can have a alternate solution by get Software ID. You can use software id as a unique id. Please find below code as i use in Application.
public static String getDeviceId(Context context) {
String deviceId;
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null) {
deviceId = mTelephony.getDeviceId();
} else {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
}
}
return deviceId;
}

This just would not work as of Android Q. Third party apps can not use IMEI nor the serial number of a phone and other non-resettable device identifiers.
The only permissions that are able to use those is READ_PRIVILEGED_PHONE_STATE and that cannot be used by any third party apps - Manufacture and Software Applications. If you use that method you will get an error Security exception or get null .
You can still try to get a unique id by using:
import android.provider.Settings.Secure;
private String android_id = Secure.getString(getContext().getContentResolver(),Secure.ANDROID_ID);

The best way to get the IMEI number is as follows:
public static String getIMEIDeviceId(Context context) {
String deviceId;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q)
{
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (context.checkSelfPermission(Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return "";
}
}
assert mTelephony != null;
if (mTelephony.getDeviceId() != null)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)
{
deviceId = mTelephony.getImei();
}else {
deviceId = mTelephony.getDeviceId();
}
} else {
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
Log.d("deviceId", deviceId);
return deviceId;
}
Just copy the method and use it. It will definitely. However, you might know you can't get IMEI in android Q (version 10). In this code, you can get a unique identifier (alternative id) through any device or any API level.
It works 100%
Thank You!!
And Enjoy Coding :)

As the best practices suggest. " you can avoid using hardware identifiers, such as SSAID (Android ID) and IMEI, without limiting required functionality."
Rather go for an instance ID such as String uniqueID = UUID.randomUUID().toString(); or FirebaseInstanceId.getInstance().getId();

Not sure about IMEI number, but you can get the simSerialNumber and other carrier info this way.
getSimSerialNumber() needs privileged permissions from Android 10 onwards, and third party apps can't register this permission.
See : https://developer.android.com/about/versions/10/privacy/changes#non-resettable-device-ids
A possible solution is to use the TELEPHONY_SUBSCRIPTION_SERVICE from Android 5.1, to retrieve the sim serial number. Steps below:
Check for READ_PHONE_STATE permission.
Get Active subscription list.( Returns the list of all active sim cards)
Retrieve the sim details from Subscription Object.
if ( isPermissionGranted(READ_PHONE_STATE) ) {
String simSerialNo="";
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) {
SubscriptionManager subsManager = (SubscriptionManager) context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE);
List<SubscriptionInfo> subsList = subsManager.getActiveSubscriptionInfoList();
if (subsList!=null) {
for (SubscriptionInfo subsInfo : subsList) {
if (subsInfo != null) {
simSerialNo = subsInfo.getIccId();
}
}
}
} else {
TelephonyManager tMgr = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
simSerialNo = tMgr.getSimSerialNumber();
}
}
Check if this helps

you can change other way, i use uuid to replace devices id.
String uniquePseudoID = "35" +
Build.BOARD.length() % 10 +
Build.BRAND.length() % 10 +
Build.DEVICE.length() % 10 +
Build.DISPLAY.length() % 10 +
Build.HOST.length() % 10 +
Build.ID.length() % 10 +
Build.MANUFACTURER.length() % 10 +
Build.MODEL.length() % 10 +
Build.PRODUCT.length() % 10 +
Build.TAGS.length() % 10 +
Build.TYPE.length() % 10 +
Build.USER.length() % 10;
String serial = Build.getRadioVersion();
String uuid = new UUID(uniquePseudoID.hashCode(), serial.hashCode()).toString();
AppLog.d("Device ID",uuid);

If your app targets Android 10 or higher, a SecurityException occurs.
Following modules are affected...
Build
getSerial()
TelephonyManager
getImei()
getDeviceId()
getMeid()
getSimSerialNumber()
getSubscriberId()
So you cant get IMEI no for android 10 , You have to used another unique identifier for this like Android ID
It unique 64 bit hex no for device
private String android_id = Secure.getString(getContext().getContentResolver(),
Secure.ANDROID_ID);

According to google docs.
Restriction on non-resettable device identifiers
Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
Caution: Third-party apps installed from the Google Play Store cannot
declare privileged permissions.
So, Instead of imei you can get Android unique ID.
String imei = "";
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (checkSelfPermission(Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
try {
imei = telephonyManager.getImei();
} catch (Exception e) {
e.printStackTrace();
imei = Settings.Secure.getString(this.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
} else {
if (ActivityCompat.checkSelfPermission(MainActivity.this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
imei = telephonyManager.getDeviceId();
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
}

Targeting Android Q, third party apps can't access IMEI at all. Android Q doc is misleading while stating
Starting in Android Q, apps must have the READ_PRIVILEGED_PHONE_STATE
privileged permission in order to access the device's non-resettable
identifiers, which include both IMEI and serial number.
https://developer.android.com/preview/privacy/data-identifiers#device-ids
But when I actually tried to implement it, I am receiving this exception:
java.lang.SecurityException: getDeviceId: The user 10132 does not meet the requirements to access device identifiers.
Someone had reported this on google's issue tracker where a Googler said that this is intended behaviour and IMEI on Q+ is only available for system level apps.
Status: Won't Fix (Intended Behavior) This is Working As Intended.
IMEI is a personal identifier and this is not given out to apps as a
matter of policy. There is no workaround.
https://issuetracker.google.com/issues/129583175#comment10

They mentioned:
If your app is the device or profile owner app, you need only the READ_PHONE_STATE permission to access non-resettable device identifiers, even if your app targets Android 10 or higher.
I tried deploying via EMM as device owner app but not success.

If you needed, you can try to install a work profile in to the mobile phone and include your app in the same package or vice versa.
I tried and it works, it's simple if yo follow this repo: https://github.com/googlesamples/android-testdpc
When you install the Work Profile your app is installed in this profile and you will have acces to the IMEI.
And now there is another example fixed yesterday to Android 10:
https://github.com/android/enterprise-samples/pull/29

I am getting IMEI null in Android Q?

I am getting the IMEI ID null from the telephonymanager. What to do?
is there any workaround for that?

Android Q has restricted to access for both IMEI and serial no. It is available only for platform and apps with special carrier permission. Also the permission READ_PRIVILEGED_PHONE_STATE is not available for non platform apps.
If you try to access it throws below exception
java.lang.SecurityException: getImeiForSlot: The user 10180 does not meet the requirements to access device identifiers.
Please refer documentation:
https://developer.android.com/preview/privacy/data-identifiers#device-ids
Also refer Issue

I am late to post answer. I still believe my answer will help someone.
Android 10 Restricted developer to Access IMEI number.
You can have a alternate solution by get Software ID. You can use software id as a unique id. Please find below code as i use in Application.
public static String getDeviceId(Context context) {
String deviceId;
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null) {
deviceId = mTelephony.getDeviceId();
} else {
deviceId = Settings.Secure.getString(
context.getContentResolver(),
Settings.Secure.ANDROID_ID);
}
}
return deviceId;
}

This just would not work as of Android Q. Third party apps can not use IMEI nor the serial number of a phone and other non-resettable device identifiers.
The only permissions that are able to use those is READ_PRIVILEGED_PHONE_STATE and that cannot be used by any third party apps - Manufacture and Software Applications. If you use that method you will get an error Security exception or get null .
You can still try to get a unique id by using:
import android.provider.Settings.Secure;
private String android_id = Secure.getString(getContext().getContentResolver(),Secure.ANDROID_ID);

The best way to get the IMEI number is as follows:
public static String getIMEIDeviceId(Context context) {
String deviceId;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q)
{
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
} else {
final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (context.checkSelfPermission(Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return "";
}
}
assert mTelephony != null;
if (mTelephony.getDeviceId() != null)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O)
{
deviceId = mTelephony.getImei();
}else {
deviceId = mTelephony.getDeviceId();
}
} else {
deviceId = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
Log.d("deviceId", deviceId);
return deviceId;
}
Just copy the method and use it. It will definitely. However, you might know you can't get IMEI in android Q (version 10). In this code, you can get a unique identifier (alternative id) through any device or any API level.
It works 100%
Thank You!!
And Enjoy Coding :)

As the best practices suggest. " you can avoid using hardware identifiers, such as SSAID (Android ID) and IMEI, without limiting required functionality."
Rather go for an instance ID such as String uniqueID = UUID.randomUUID().toString(); or FirebaseInstanceId.getInstance().getId();

Not sure about IMEI number, but you can get the simSerialNumber and other carrier info this way.
getSimSerialNumber() needs privileged permissions from Android 10 onwards, and third party apps can't register this permission.
See : https://developer.android.com/about/versions/10/privacy/changes#non-resettable-device-ids
A possible solution is to use the TELEPHONY_SUBSCRIPTION_SERVICE from Android 5.1, to retrieve the sim serial number. Steps below:
Check for READ_PHONE_STATE permission.
Get Active subscription list.( Returns the list of all active sim cards)
Retrieve the sim details from Subscription Object.
if ( isPermissionGranted(READ_PHONE_STATE) ) {
String simSerialNo="";
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP_MR1) {
SubscriptionManager subsManager = (SubscriptionManager) context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE);
List<SubscriptionInfo> subsList = subsManager.getActiveSubscriptionInfoList();
if (subsList!=null) {
for (SubscriptionInfo subsInfo : subsList) {
if (subsInfo != null) {
simSerialNo = subsInfo.getIccId();
}
}
}
} else {
TelephonyManager tMgr = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
simSerialNo = tMgr.getSimSerialNumber();
}
}
Check if this helps

you can change other way, i use uuid to replace devices id.
String uniquePseudoID = "35" +
Build.BOARD.length() % 10 +
Build.BRAND.length() % 10 +
Build.DEVICE.length() % 10 +
Build.DISPLAY.length() % 10 +
Build.HOST.length() % 10 +
Build.ID.length() % 10 +
Build.MANUFACTURER.length() % 10 +
Build.MODEL.length() % 10 +
Build.PRODUCT.length() % 10 +
Build.TAGS.length() % 10 +
Build.TYPE.length() % 10 +
Build.USER.length() % 10;
String serial = Build.getRadioVersion();
String uuid = new UUID(uniquePseudoID.hashCode(), serial.hashCode()).toString();
AppLog.d("Device ID",uuid);

If your app targets Android 10 or higher, a SecurityException occurs.
Following modules are affected...
Build
getSerial()
TelephonyManager
getImei()
getDeviceId()
getMeid()
getSimSerialNumber()
getSubscriberId()
So you cant get IMEI no for android 10 , You have to used another unique identifier for this like Android ID
It unique 64 bit hex no for device
private String android_id = Secure.getString(getContext().getContentResolver(),
Secure.ANDROID_ID);

According to google docs.
Restriction on non-resettable device identifiers
Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
Caution: Third-party apps installed from the Google Play Store cannot
declare privileged permissions.
So, Instead of imei you can get Android unique ID.
String imei = "";
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (checkSelfPermission(Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
try {
imei = telephonyManager.getImei();
} catch (Exception e) {
e.printStackTrace();
imei = Settings.Secure.getString(this.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
} else {
if (ActivityCompat.checkSelfPermission(MainActivity.this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
if (telephonyManager != null) {
imei = telephonyManager.getDeviceId();
}
} else {
ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.READ_PHONE_STATE}, 1010);
}
}

Targeting Android Q, third party apps can't access IMEI at all. Android Q doc is misleading while stating
Starting in Android Q, apps must have the READ_PRIVILEGED_PHONE_STATE
privileged permission in order to access the device's non-resettable
identifiers, which include both IMEI and serial number.
https://developer.android.com/preview/privacy/data-identifiers#device-ids
But when I actually tried to implement it, I am receiving this exception:
java.lang.SecurityException: getDeviceId: The user 10132 does not meet the requirements to access device identifiers.
Someone had reported this on google's issue tracker where a Googler said that this is intended behaviour and IMEI on Q+ is only available for system level apps.
Status: Won't Fix (Intended Behavior) This is Working As Intended.
IMEI is a personal identifier and this is not given out to apps as a
matter of policy. There is no workaround.
https://issuetracker.google.com/issues/129583175#comment10

They mentioned:
If your app is the device or profile owner app, you need only the READ_PHONE_STATE permission to access non-resettable device identifiers, even if your app targets Android 10 or higher.
I tried deploying via EMM as device owner app but not success.

If you needed, you can try to install a work profile in to the mobile phone and include your app in the same package or vice versa.
I tried and it works, it's simple if yo follow this repo: https://github.com/googlesamples/android-testdpc
When you install the Work Profile your app is installed in this profile and you will have acces to the IMEI.
And now there is another example fixed yesterday to Android 10:
https://github.com/android/enterprise-samples/pull/29

Check telephonyManager.getDeviceId() returns a Real value or not

Requirement
One android device one account. To restrict user creating multiple accounts in a single device.
What I had done
During Log in, With the help of telephonyManager.getDeviceId() I am getting the IMEI number of an android device. Then I am checking this with all IMEI number stored in my server Database.
But after impementing
TelephonyManager telephonyManager = (TelephonyManager) this.getSystemService(Context.TELEPHONY_SERVICE);
String IMEINo = telephonyManager.getDeviceId();
I got many IMEI numbers that's fake.
For example I checked in https://www.imei24.com for "272052651704884".
The result was "Given IMEI 272052651704884 is not correct. Control amount is false. The last digit of the IMEI number is generated based on Luhna formula."
After doing many research I came to know that if you are cloaning the App using Parallel Space or any othrt such, telephonyManager.getDeviceId() returns a fake value.
After 7 long months I found a solution to this problem. That is Lunh Algorithm, which perform some calculation and tells weather it is a valid IMEI or not.
What I Need: A suggestion for weather I should blindly rely on The Lunh Algorithm or not.

I think you should try this it will works. I found real IMEI number with getDeviceId()
TelephonyManager telephonyManager = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
if (ActivityCompat.checkSelfPermission(context,
Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return;
}
String IMEI_Number = null;
if (telephonyManager != null) {
IMEI_Number = telephonyManager.getDeviceId();
}
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
String Imei0Id = null;
if (telephonyManager != null) {
Imei0Id = telephonyManager.getDeviceId(0);
}
if (null != Imei0Id && !Imei0Id.equals("000000000000000")) {
IMEI_Number = Imei0Id;
}
}

Use an immutable universally unique identifier (UUID). A UUID represents a 128-bit value.
UUID.randomUUID().toString()

Will TelephonyManger.getDeviceId() return device id for Tablets like Galaxy Tab...?

I want to get the device id that will be unique for each Android device. I am presently developing for a Tablet device. Want to get unique device id and store the corresponding values...
So, i want to know whether Tablet devices will return a value if i use TelephonyManager.getDeviceId()...???Or is there any other value that is unique for each device???

TelephonyManger.getDeviceId() Returns the unique device ID, for example, the IMEI for GSM and the MEID or ESN for CDMA phones.
final TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
String myAndroidDeviceId = mTelephony.getDeviceId();
But i recommend to use:
Settings.Secure.ANDROID_ID that returns the Android ID as an unique 64-bit hex string.
String myAndroidDeviceId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID);
Sometimes TelephonyManger.getDeviceId() will return null, so to assure an unique id you will use this method:
public String getUniqueID(){
String myAndroidDeviceId = "";
TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (mTelephony.getDeviceId() != null){
myAndroidDeviceId = mTelephony.getDeviceId();
}else{
myAndroidDeviceId = Secure.getString(getApplicationContext().getContentResolver(), Secure.ANDROID_ID);
}
return myAndroidDeviceId;
}

This is not a duplicate question. As it turns out, Google's CTS require that getPhoneType of TelephonyManager needs to be none and getDeviceId of TelephonyManager needs to be null for non-phone devices.
So to get IMEI, please try to use:
String imei = SystemProperties.get("ro.gsm.imei")
Unfortunately, SystemProperties is a non-public class in the Android OS, which means it isn't publicly available to regular applications. Try looking at this post for help accessing it: Where is android.os.SystemProperties

Since Android 8 everything's changed. You should use Build.getSerial(), to get the serial number of the device and add the permission READ_PHONE_STATE.
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
serial = Build.getSerial(); // Requires permission READ_PHONE_STATE
} else {
serial = Build.SERIAL; // Will return 'unknown' for device >= Build.VERSION_CODES.O
}
And get the IMEI or MEID this way:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
String imei = tm.getImei(); // Requires permission READ_PHONE_STATE
serial = imei == null ? tm.getMeid() : imei; // Requires permission READ_PHONE_STATE
} else {
serial = tm.getDeviceId(); // Requires permission READ_PHONE_STATE
}

Develop Reference

The Android operating system is a mobile operating system that was developed by Google (GOOGL?) to be primarily used for touchscreen devices, cell phones, and tablets.

Android programming imei getDeviceID(telephonymanager) - android

How can I get IMEI number up to API level 19 (kitkat) in Android programming? I have used getDeviceID(telephonyManager) but it is working only up to API 22 not below for API level 19. Is there any other function that can be used?

Related

How to Get IMEI or Serial Number for Android 10+ [duplicate]

Android API 29 Permission Error READ_PRIVILEGED_PHONE_STATE [duplicate]

I am getting IMEI null in Android Q?

Check telephonyManager.getDeviceId() returns a Real value or not

Will TelephonyManger.getDeviceId() return device id for Tablets like Galaxy Tab...?

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