This question already has answers here:
How to use selector to tint ImageView?
(6 answers)
Closed 4 years ago.
I have 2 images (normal,pressed), I want to set in selector of button
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true"
android:drawable="#drawable/recent_pressed" />
<item
android:drawable="#drawable/recent" />
</selector>
now I want to apply tint color in #drawable/recent_pressed image.
can have any solution for this.
I don't want to create custom class for imageview, because this selector is use as a menu.
I searched about that but this link not working for me
Create a selector tint_tem.xml :
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:color="#color/white" android:state_pressed="true" />
<item android:color="#color/white" android:state_activated="true" />
<item android:color="#color/green" />
Then in your xml, you can add tint attribute to ImageView:
<ImageView
android:layout_width="30dp"
android:layout_height="30dp"
android:tint="#color/tint_item"
android:src="#drawable/ic_menu_home" />
ou can also use this selector on a TextView using textColor attibute:
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textColor="#color/tint_item" />
You can create a bitmap and apply tint on it .
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true">
<bitmap android:src="#drawable/your_pressed_drawable" android:tint="#color/colorPrimary"/>
</item>
<item android:drawable="#drawable/your_second_drawable" />
</selector>
Related
I have a simple Button, which has a drawable set as icon:
<Button
android:id="#+id/bOk"
android:drawableStart="#drawable/icon_ok"
android:text="#string/ok"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
when I disable the button, either in XML layout file: android:enabled="false"
or programmaticaly: bOk.setEnabled(false);
The button gets disabled, it is 'grayed out', but the icon remains as it was ine the enabled state.
How can I get a look, that the icon is also 'grayed out'?
Create a new grayed icon and add both inside a selector.xml:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="#drawable/icon_ok" android:state_enabled="true" />
<item android:drawable="#drawable/icon_ok_disabled" android:state_enabled="false" />
</selector>
Use inside button like: android:drawableStart="#drawable/selector"
For TextColor,
Create another selector inside res/color/mycustomtextcolor.xml:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:color="#666" android:state_enabled="false" />
<item android:color="#000" android:state_enabled="true"/>
</selector>
Inside your widget call using: android:textColor="#color/mycustomtextcolor"
Or
inside your style add another item using: <item name="android:textColor">#color/mycustomtextcolor</item>
Like a regular Button, a Button that has an image background is not grayed when disabled.
You have to use another image it appears grayed.
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_enabled="false"
android:drawable="#drawable/button_gray" /> ***button_gray is a Drawable image***
<item android:state_pressed="true"
android:drawable="#drawable/button_gray" />
<item android:drawable="#drawable/button_red" /> ***button_red is a Drawable image***
</selector>
You can tint your drawable on enabled and disabled state using a selector with bitmaps:
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_enabled="false">
<bitmap android:src="#drawable/icon_ok" android:tint="#color/disableColorWithAlpha" />
</item>
<item android:state_enabled="true">
<bitmap android:src="#drawable/icon_ok" android:tint="#color/colorAccent" />
</item>
</selector>
Is it possible change a color of drawable from selector?
My selector:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:drawable="#drawable/ic_plus_circle_grey600_48dp" android:state_pressed="true"/>
<item android:drawable="#drawable/ic_plus_circle_black_48dp"/>
</selector>
I try use that way, (in this case I'm using a selector on tint) but I'm getting some error:
<ImageView
android:id="#+id/btAdd"
android:layout_width="wrap_content"
android:src="#drawable/ic_plus_circle_black_48dp"
android:tint="#color/blue_android_focused"
android:layout_height="wrap_content"/>
This is the selector of tint:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:color="#color/blue_android_pressed" android:state_pressed="true" />
<item android:color="#color/green" />
</selector>
Using tint on bitmap (** API 21+**):
Selector: drawable/selector_add
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true">
<bitmap android:src="#drawable/ic_plus_circle_grey600_48dp"
android:tint="#color/blue_android_pressed" />
</item>
<item>
<bitmap android:src="#drawable/ic_plus_circle_grey600_48dp"
android:tint="#color/colorAccent" />
</item>
</selector>
In the ImageView
<ImageView
android:id="#+id/btAdd"
android:layout_width="wrap_content"
android:src="#drawable/selector_add"
android:layout_height="wrap_content"
/>
You can have the same drawables with different colors, that´s work for me
Your should use tint like this :
<ImageView
android:id="#+id/activity_register_et_fullname"
android:layout_width="100dp"
android:layout_height="100dp"
android:background="#drawable/bg_page"
app:backgroundTint="#color/blue_android_focused"/>
Use ImageView in AppCompatActivity, it will be inflated with AppCompatImageView (see also android.support.v7.app.AppCompatViewInflater). You should look at the code in it.
I want to create effects for ImageButton. For example, it will change color when clicked...How I do it? I want to do this in .xml file. Can you help me! Thank you!
I tried to create the state.xml file as follwing:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:state_pressed="true"
android:state_enabled="true"
android:drawable="#drawable/btn_0" />
<item
android:state_focused="true"
android:state_enabled="true"
android:drawable="#drawable/btn_ac" />
</selector>
However, I can't set background for ImageButton. The error like this:
All you have to do it to add the "android:background" attribut to your ImageButton and set a drawable.
Your layout
<ImageButton
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:src="#drawable/my_btn"
android:background="#drawable/btn_drawable"/>
btn_drawable.xml
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_pressed="true"
android:drawable="#drawable/blue"
/>
<item android:state_focused="true"
android:drawable="#drawable/white"
/>
<item android:drawable="#drawable/green" />
</selector>
In that code above you set a different drawable when your ImageButton is pressed (state_pressed), focused (state_focus) or when is normal (not pressed and not focused).
Here you can find with more detail.
Create a drawable like below and name it as btn_drawable.
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:state_enabled="false"
android:drawable="#drawable/btn_disable" />
<item
android:state_pressed="true"
android:state_enabled="true"
android:drawable="#drawable/btn_click" />
</selector>
This is for an example,Like this you can add the <item/> according to your needs and state of the image button.
Then set the drawable as image button background.
<ImageButton
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="#drawable/btn_drawable"/>
This question already has answers here:
android button selector
(6 answers)
Closed 8 years ago.
How can I create a button that changes its background image to represent the default, pressed or focused states?
Quite easy to do using a selector.
Create a new xml file inside the drawable folder containing the following:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="#drawable/drawable_selected" android:state_selected="true"></item>
<item android:drawable="#drawable/drawable_pressed" android:state_pressed="true"></item>
<item android:drawable="#drawable/drawable_default"></item>
</selector>
Then refer to this selector in your Button:
<Button
android:id="#+id/button"
android:background="#drawable/selector_you_just_made"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:text="Button" />
More documentation and other possible states can be found here.
XML drawable:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="#drawable/button_pressed"
android:state_pressed="true" />
<item android:drawable="#drawable/button_focused"
android:state_focused="true" />
<item android:drawable="#drawable/button_default" />
</selector>
Button:
<Button
android:id="#+id/button_send"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="#string/button_send"
android:onClick="sendMessage"
android:background="#drawable/button_custom" />
Here in section Custom background is more info
I customized the Toggle button by using a drawable defined by using a selector. I use this drawable as background for the Toggle button.
<ToggleButton
android:id="#+id/mailbox:toggle_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_gravity="bottom"
android:layout_weight="1"
android:background="#drawable/toggle_background"
android:gravity="center_horizontal|center_vertical" />
The toggle_background is defined here:
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:drawable="#drawable/img1"
android:state_checked="true" />
<item
android:drawable="#drawable/img2"
android:state_checked="false" />
</selector>
The problem is that the image is always stretched. Is there a way to define an image for the two states that is not stretched?
What I need is a background that will be stretched and in the center of the button an icon that must not be stretched.
Is it possible?
This is my final solution.
In the layout:
<ToggleButton
android:id="#+id/mailbox:toggle"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:background="#drawable/toggle_drawable_layers"/>
in the toggle_drawable_layers.xml
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:drawable="#drawable/toggle_drawable_bkg"></item>
<item android:left="10dp" android:drawable="#drawable/toggle_drawable_left"
android:gravity="center_vertical|center_horizontal" />
</layer-list>
in the toggle_drawable_left.xml
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_checked="true">
<bitmap android:src="#drawable/bitmap_checked"
android:gravity="center_vertical|center_horizontal" />
</item>
<item android:state_checked="false">
<bitmap android:src="#drawable/bitmap_unchecked"
android:gravity="center_vertical|center_horizontal" />
</item>
</selector>
I did the same task this way, the button:
<ToggleButton android:id="#+id/mlAbout"
android:textOn="#string/about"
android:textOff="#string/about"
android:background="#drawable/ml_about" />
#drawable/ml_about:
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:drawable="#drawable/list_bg_top"></item>
<item android:left="10dp">
<bitmap android:src="#drawable/waiting_status_btn"
android:gravity="center_vertical|left" />
</item>
</layer-list>
#drawable/list_bg_top background image that will be stretched and #drawable/waiting_status_btn is the icon the will not be stretched with the widget
Just use bitmaps instead of drawables in your selector like so (no need to use layers):
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:drawable="#drawable/img1"
android:state_checked="true" />
<item
android:drawable="#drawable/img2"
android:state_checked="false" />
</selector>
Also, don't forget to declare
android:textOff=""
android:textOn=""
in your ToggleButton declaration
There is another way to overcome the issue of stretching:
Just convert the image into a Nine-Patch image, where the stretchable areas are just on all sides of the image.
Then Android will stretch the image only in invisible areas, and keep the visible image unchanged.