Develop Reference

Deeplink does not open the app from Gmail

We are trying to implement deepLink from a Gmail in our app. I add following code to my Manifest file :
<activity
android:name="io.fetchcar.archapp.MainActivity"
android:exported="true">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter android:label="#string/filter_view_fetch">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="fetch" />
</intent-filter>
</activity>
In the Gmail we have following button with html code :
Fetch A Car Now
But when we click on the button from Gmail, it does not open the app.
The thing is if we open it as a web page in the browser and click on Fetch A Car Now button, it opens our app as expected.
Is it any limitation to open our app with Deeplink from Gmail ?

How to launch app on click of url in android

Launch app when click on url if app installed on device. if app not installed on device, open playstore.
<activity android:name=".ui.NewsCardActivity">
<intent-filter>
<data android:scheme="app" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
</activity>

You have to deep link your app, add following lines in activity (Manifiest.xml) which you want to launch
<intent-filter >
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE"/>
<data android:host="screen" android:scheme="appname"/>
</intent-filter>
in browser when ever you click appname://screen your app activity will be launched,
replace appname and screen as per your requirement
Note if you type this url in browser it will search in google ,for this to work you have to write link in html page
Some text
If not working the add android:exported="true" in activity
<activity
android:name=".activity.MainActivity"
android:exported="true">

Redirect to Mobile app from facebook and twitter app

My Android app can share links via Twitter or Facebook.
If someone clicks on a link that was shared and they already have the app installed, how can I make the app launch directly?
Updated -
Simple Issue Fixed from here -
Make a link in the Android browser start up my app?

You need to add <Intent-filter> under <activity> tag in manifest.xml file like
<activity android:name=".ui.MyActivity" >
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="image/*" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.SEND_MULTIPLE" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="image/*" />
</intent-filter>
</activity>
When another application tries to share any of these things by constructing an intent and passing it to startActivity(), your application will be listed as an option in the intent chooser.
If the user selects your application, the corresponding activity (.ui.MyActivity in the example above) will be started. It is then up to you to handle the content appropriately within your code and UI.
And go to this for better understanding: http://developer.android.com/training/sharing/receive.html

Facebbok/twitter
facebook
After facebbok login OnComplete() is called. So, fire your intent in this method.
public void onComplete(Bundle values)
{
# fire desired intent
}
twitter
put this code into your manifest file with activity name and on which activity
want to redirect put the below line so link is created and you will redirect
<activity
android:name="com.example.mainactivity"
android:screenOrientation="portrait" >
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data
android:host="home"
android:scheme="oauth" />
</intent-filter>
</activity>
*********************************************************************
<h6>put this into your mainactivty</h6>
static final String TWITTER_CALLBACK_URL = "oauth://home";
static final String TWITTER_CALLBACK_URL = "oauth://home";

How to avoid multiple open in particular application in android?

I have already opened my android application. I used url scheme, so that my app can be opened from the users email. But if i try to open my application from clicking email link from the web browser, it will open that application in separate window. (Please see my attached screen short picture) .
How to avoid my application to open twice separately?
<activity
android:name="com.mYs3.MainActivity.flash_screen"
android:label="#string/app_name"
android:screenOrientation="portrait"
android:theme="#android:style/Theme.NoTitleBar.Fullscreen" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<data android:scheme="mYs3" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.BROWSABLE" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>

try this line in your activity block in manifest
android:launchMode="singleTask"

Could not launch application by calling a URL from Android Browser

There are many answers in stackoverflow showing how to lauch app from a web browser ,but I am not sure what went wrong with my code, that never seems to be doing the intended.
I am trying to launch my app by a URL from any other app like web browser,initially
my manifest file looks like this
<activity android:name=".Main">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<data android:scheme="http" android:host="ebay.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
And When I typed http://ebay.com in the browser that never started my app.Obviously,how does the browser know about my app?,then i tried the other way around and added another Activity called MyActivity and altered the manifest file as
<activity android:name=".Main">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".MyActivity">
<intent-filter>
<data android:scheme="http" android:host="ebay.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
</activity>
and tried in my Main Activity
startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://mycityway.com")));
Thus producing the intended result.I can also start another application Activity using this method.
But most of the answers here says that the later is possible.What is the mistake i am doing,I couldn't launch my app from browser.Please guide me.

And When I typed http://ebay.com in the browser that never started my
app.
It gets started when a matching link is clicked not when you type the url in the browser.
Try it by sending yourself an email containing http://ebay.com and click the link in the email application.