I can find some very old file-picker samples, but think it might now be possible to do it with the more up to date Intent.
I want to load and save files. It will be a text file but with an extension .mfl (an extension I am using for my files).
I have seen someone's code for images (but just for loading):
Intent intent = new Intent();
// Show only images, no videos or anything else
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
// Always show the chooser (if there are multiple options available)
startActivityForResult(Intent.createChooser(intent, "Select Picture"), PICK_IMAGE_REQUEST);
What do I need in setType to only see my .mfl files?
I already have a onActivityResult doing other stuff, so need to create my own requestCode. I was thinking
int PICK_MYFILE_REQUEST = 1001;
So I think my onActivityResult needs to look like this:
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if(/* doing my other stuff */){
} else if (requestCode == PICK_MYFILE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
Uri uri = data.getData();
try {
/* load the file */
} catch (IOException e) {
e.printStackTrace();
}
}
}
As you can see I think I might be almost there, but not completely sure what I am meant to be doing. (I am new to Android - I think you can guess.)
Is this roughly right? What do I need to do to get this working?
Also, how do I modify this to get a file saver dialog?
Try this :
Intent intent = new Intent();
intent.setType("application/pdf");
intent.setAction(Intent.ACTION_GET_CONTENT);
intent.addCategory(Intent.CATEGORY_OPENABLE);
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION); // temp permission for receiving app to read this file
For custom type you can use application/mfl so your Intent should be:
//Use ACTION_OPEN_DOCUMENT to get read/write permission
Intent intent = new Intent(Intent.Intent.ACTION_OPEN_DOCUMENT);
//"application/mfl" to request only .mfl files
intent.setType("application/mfl");
//Request readable files
intent.addCategory(Intent.CATEGORY_OPENABLE)
startActivityForResult(Intent.createChooser(intent, "Select File"),PICK_MYFILE_REQUEST);
Related
I am trying to fetch a file this way:
final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
String[] mimetypes = {"application/pdf"};
chooseFileIntent.setType("*/*");
chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
if (chooseFileIntent.resolveActivity(activity
.getApplicationContext().getPackageManager()) != null) {
chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
}
Then in onActivityResult :
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
}
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :
/document/acc=1;doc=28
So what to do? Thanks for your help.
I am trying to fetch a file
Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()
That was never correct, though it tended to work on older versions of Android.
So what to do?
Well, that depends.
If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT. (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)
If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:
If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user
To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.
private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;
private void chooseFile() {
Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
fileChooser.setType("application/pdf");
startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}
#Override
protected void onActivityResult(int requestCode, int resultCode, #Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == FILEPICKER_RESULT_CODE) {
if (resultCode == RESULT_OK) {
fileUri = data != null ? data.getData() : null;
if (fileUri != null) {
DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
if (d != null) {
Log.d("TAG", "file name: " + d.getName());
Log.d("TAG", "file path: " + d.getUri().getPath());
sendEmail(fileUri);
}
}
}
}
}
private void sendEmail(Uri path) {
String email = "example#gmail.com";
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("application/octet-stream");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
String[] to = { email };
intent.putExtra(Intent.EXTRA_EMAIL, to);
intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
intent.putExtra(Intent.EXTRA_STREAM, path);
startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}
hope it helps.
I am trying to fetch a file this way:
final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
String[] mimetypes = {"application/pdf"};
chooseFileIntent.setType("*/*");
chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
if (chooseFileIntent.resolveActivity(activity
.getApplicationContext().getPackageManager()) != null) {
chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
}
Then in onActivityResult :
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
}
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :
/document/acc=1;doc=28
So what to do? Thanks for your help.
I am trying to fetch a file
Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()
That was never correct, though it tended to work on older versions of Android.
So what to do?
Well, that depends.
If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT. (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)
If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:
If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user
To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.
private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;
private void chooseFile() {
Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
fileChooser.setType("application/pdf");
startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}
#Override
protected void onActivityResult(int requestCode, int resultCode, #Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == FILEPICKER_RESULT_CODE) {
if (resultCode == RESULT_OK) {
fileUri = data != null ? data.getData() : null;
if (fileUri != null) {
DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
if (d != null) {
Log.d("TAG", "file name: " + d.getName());
Log.d("TAG", "file path: " + d.getUri().getPath());
sendEmail(fileUri);
}
}
}
}
}
private void sendEmail(Uri path) {
String email = "example#gmail.com";
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("application/octet-stream");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
String[] to = { email };
intent.putExtra(Intent.EXTRA_EMAIL, to);
intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
intent.putExtra(Intent.EXTRA_STREAM, path);
startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}
hope it helps.
I am trying to fetch a file this way:
final Intent chooseFileIntent = new Intent(Intent.ACTION_GET_CONTENT);
String[] mimetypes = {"application/pdf"};
chooseFileIntent.setType("*/*");
chooseFileIntent.addCategory(Intent.CATEGORY_OPENABLE);
if (chooseFileIntent.resolveActivity(activity
.getApplicationContext().getPackageManager()) != null) {
chooseFileIntent.putExtra(Intent.EXTRA_MIME_TYPES, mimetypes);
activity.startActivityForResult(chooseFileIntent, Uploader.PDF);
}
Then in onActivityResult :
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
}
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath(), the file name I'm expecting is my_file.pdf, but instead I'm getting this :
/document/acc=1;doc=28
So what to do? Thanks for your help.
I am trying to fetch a file
Not with that code. That code is asking the user to pick a piece of content. This may or may not be a file.
According to many threads I'm supposed to fetch the file name from the intent with data.getData().getPath()
That was never correct, though it tended to work on older versions of Android.
So what to do?
Well, that depends.
If you wish to only accept files, integrate a file chooser library instead of using ACTION_GET_CONTENT. (UPDATE 2019-04-06: since Android Q is banning most filesystem access, this solution is no longer practical)
If you are willing to allow the user to pick a piece of content using ACTION_GET_CONTENT, please understand that it does not have to be a file and it does not have to have something that resembles a filename. The closest that you will get:
If getScheme() of the Uri returns file, your original algorithm will work
If getScheme() of the Uri returns content, use DocumentFile.fromSingleUri() to create a DocumentFile, then call getName() on that DocumentFile — this should return a "display name" which should be recognizable to the user
To get the real name and to avoid getting a name that looks like "image: 4431" or even just a number, you can write code as recommended by CommonsWare.
The following is an example of a code that selects a single pdf file, prints its name and path to the log, and then sends the file by email using its uri.
private static final int FILEPICKER_RESULT_CODE = 1;
private static final int SEND_EMAIL_RESULT_CODE = 2;
private Uri fileUri;
private void chooseFile() {
Intent fileChooser = new Intent(Intent.ACTION_GET_CONTENT);
fileChooser.setType("application/pdf");
startActivityForResult(Intent.createChooser(fileChooser, "Choose one pdf file"), FILEPICKER_RESULT_CODE);
}
#Override
protected void onActivityResult(int requestCode, int resultCode, #Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == FILEPICKER_RESULT_CODE) {
if (resultCode == RESULT_OK) {
fileUri = data != null ? data.getData() : null;
if (fileUri != null) {
DocumentFile d = DocumentFile.fromSingleUri(this, fileUri);
if (d != null) {
Log.d("TAG", "file name: " + d.getName());
Log.d("TAG", "file path: " + d.getUri().getPath());
sendEmail(fileUri);
}
}
}
}
}
private void sendEmail(Uri path) {
String email = "example#gmail.com";
Intent intent = new Intent(android.content.Intent.ACTION_SEND);
intent.setType("application/octet-stream");
intent.putExtra(android.content.Intent.EXTRA_SUBJECT, "PDF file");
String[] to = { email };
intent.putExtra(Intent.EXTRA_EMAIL, to);
intent.putExtra(Intent.EXTRA_TEXT, "This is the pdf file...");
intent.putExtra(Intent.EXTRA_STREAM, path);
startActivityForResult(Intent.createChooser(intent, "Send mail..."), SEND_EMAIL_RESULT_CODE);
}
hope it helps.
now file:// uri are not supported. people say to use FileProvider but i think i have to save image in app data location to use this. is there a way to get content:// URI Without Saving image in data directory.i want to open image in sd card from gallery. this below code works on old phones, after android 7 it is not working. FileUriExposedException example image file is in dcim folder my old code is this
File pic2toview = new File(imagepath);
Intent i = new Intent();
i.setAction(android.content.Intent.ACTION_VIEW);
i.setDataAndType(Uri.fromFile(pic2toview), "image/*");
startActivity(i);
Code to select an image from gallery by intent,
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Image"), PICK_IMAGE_REQUEST);
Then it handled in onActivityResult,
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == PICK_IMAGE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
imageUrl = data.getData();
}
}
Here imageUrl is Uri of image selected from gallery.
I am using this code to allow the user to select multiple .csv files from their storage:
Intent intent = new Intent(Intent.ACTION_OPEN_DOCUMENT);
intent.setType("text/comma-separated-values");
intent.addCategory(Intent.CATEGORY_OPENABLE);
intent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);
startActivityForResult(Intent.createChooser(intent, "Get CSV Files"), REQUEST_IMPORT_CSV);
After choosing the files it goes to onActivityResult() and so far I have done:
#Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case REQUEST_IMPORT_CSV:
if (data != null) {
ClipData clipData = data.getClipData();
ArrayList<Uri> csvUris = new ArrayList<>();
if (clipData != null) {
for (int i = 0; i < clipData.getItemCount(); i++) {
clipData.getItemAt(i).getText()
csvUris.add(clipData.getItemAt(i).getUri());
}
}
else {
csvUris.add(data.getData());
}
}
break;
}
}
Is this the right way to get all the relevant Uris from the result? If seems like if the user picks one file, I get the Uri from data.getData(), and if the user picked multiple files, then it goes straight to this clipData() thing instead.
Assuming (1) is correct, how do I get the filenames of the corresponding files that the user chose? For example "chosen_file.csv" (I am not asking for the path).
Is this the right way to get all the relevant Uris from the result?
AFAIK, yes. Leastways, it has worked for me.
how do I get the filenames of the corresponding files that the user chose?
Strictly speaking, you don't. There is no requirement for the Uri to point to a file, any more than the URL to this Web page has to point to a file.
What you can do is wrap the Uri in a DocumentFile, via fromSingleUri(). Then, call getName() on the DocumentFile to get a "display name" for the content. Depending on where the user got the content from, this may be a filename-like value. It is supposed to be something user-recognizable. However, do not assume that it is a filename, as it could be something else.