Suppose i have a String, below
String myText="I'm a android developer and i'm developing an android app";
so i want to split the above string with(" ' "), and want to put it on a textView so how it is possible. i have used this code
split(Pattern.quote("'"));
so my complete code is :
textUser.setText(User);
String[] newDesc=Description1.split(Pattern.quote("'"));
for(String w:newDesc){
textDesc.setText(w);
}
but this is not working. Please resolve my issue
I believe Pattern.quote() wrapps your RegExp so that it only works if the matching string in inside quotes.
In other words, I do not believe in this case it would work.
A simple String[] newDesc=Description1.split("'"); should work.
Use this please
String[] newDesc=Description1.split("'");
Use the below code to understand the split string you need:
Example : String myText = "I'm a android developer and i'm developing an android app";
String[] strParts = myText.split("'");
Then
String strFirstString = strParts[0]; // I
String strSecondString = strParts[1]; // m a android developer and i
String strThirdString = strParts[2]; // m developing an android
Now display whichever String you want, in your textView.
Related
I am writing an app with Android Studio and I want to split a text into different values.
I have following text in result
*"Name: Peter;Age: 25; City: Chicago"*
I want to get:
*Name = Peter;
Age = 25;
City = Chicago;*
I used the search function and found these solutions: Android Split string but for my problem it seems to be too complicated.
The easiest way is to use split() method.
String s1="Name: Peter;Age: 25; City: Chicago";
String[] words=s1.split(";");
//using java foreach loop to print elements of string array
for(String w:words)
{
Log.i("Words: ", w);
}
So I have the following string:
String text = "\t\t\torder #168\n\t\t\tpaid\n\t\t\tview 4 items\n\t\t\tpicked up\n\t\t\tcomplete pickup\n\t\t\t2 stops";
How do I parse this string so that I always get the 2 in front of stops? I have tried the following, but it always returns 2 stops.
String substr = "complete pickup";
String numberOfStops = text.substring(text.indexOf(substr) + substr.length());
numberOfStops = numberOfStops.replaceAll("^\\s+","").replaceAll("\\s+$","");
The short way:
numberOfStops = numberOfStops.replaceAll("^\\s+","").replaceAll("\\s+$","").replace("stops","");
The flexible way is using Regex, and Pattern and Match classes. Let me know if you need it
I'm trying to remove all text tagged like this (including the tags)
<tag>TEXT</tag>
from a String.
I have tried
.replaceAll("<tag>.+/(tag)*>", "")
or
.replaceAll("<tag>.*(tag)*>", "")
but neither works correctly and I can't replace the tagged text with ""
I don't know exactly what you want, so here are a few options:
String text = "ab<tag>xyz</tag>cd";
// Between
text.replaceAll("<tag>.+?<\/tag>", "<tag></tag>"); // ab<tag></tag>cd
// Everything
text.replaceAll("<tag>.+?<\/tag>", ""); // abcd
// Only tags
text.replaceAll("<\/?tag>", ""); // abxyzcd
EDIT:
The problem was the missing ? after the .+. The question mark only matches the first occurence, so it works when multiple tags are present which was the case.
Change to this ,
String nn1="<tag>TEXT</tag>";
nn1=nn1.replace("<tag>","");
nn1=nn1.replace("</tag>","");
OR
String nn1="<tag>TEXT</tag>";
nn1=nn1.replaceAll("<tag>","");
nn1=nn1.replaceAll("</tag>","");
Output : TEXT
I hope this helps you.
public static void removeTAG()
{
String str = "<tag>Your Long String</tag>";
for(int i=0;i<str.length();i++)
{
str = str.replace("<tag>", "");
str = str.replace("</tag>", "");
}
System.out.println(str);
}
Here what i did and output was as expected
Output Your Long String
You can use the below regular expression.
.replaceAll("<tag>.+?<\/tag>", "<tag></tag>");
This removes all the tags whether it's an HTML or an XML tag.
For the input text:
<p>Arbit string <b>of</b><br><br>text. <em>What</em> to <strong>do</strong> with it?
I run the following code:
Whitelist list = Whitelist.simpleText().addTags("br");
// Some other code...
// plaintext is the string shown above
retVal = Jsoup.clean(plaintext, StringUtils.EMPTY, list,
new Document.OutputSettings().prettyPrint(false));
I get the output:
Arbit string <b>of</b>
text. <em>What</em> to <strong>do</strong> with it?
I don't want Jsoup to convert the <br> tags to line breaks, I want to keep them as-is. How can I do that?
Try this:
Document doc2deal = Jsoup.parse(inputText);
doc2deal.select("br").append("br"); //or append("<br>")
This is not reproducible for me. Using Jsoup 1.8.3 and this code:
String html = "<p>Arbit string <b>of</b><br><br>text. <em>What</em> to <strong>do</strong> with it?";
String cleaned = Jsoup.clean(html,
"",
Whitelist.simpleText().addTags("br"),
new Document.OutputSettings().prettyPrint(false));
System.out.println(cleaned);
I get the following output:
Arbit string <b>of</b><br><br>text. <em>What</em> to <strong>do</strong> with it?
Your problem must be somewhere else I guess.
In my android app, I am getting the String from an Edit Text and using it as a parameter to call a web service and fetch JSON data.
Now, the method I use for getting the String value from Edit Text is like this :
final EditText edittext = (EditText) findViewById(R.id.search);
String k = edittext.getText().toString();
Now normally it works fine, but if we the text in Edit Text contains space then my app crashes.
for eg. - if someone types "food" in the Edit Text Box, then it's OK
but if somebody types "Indian food" it crashes.
How to remove spaces and get just the String ?
Isn't that just Java?
String k = edittext.getText().toString().replace(" ", "");
try this...
final EditText edittext = (EditText) findViewById(R.id.search);
String k = edittext.getText().toString();
String newData = k.replaceAll(" ", "%20");
and use "newData"
String email=recEmail.getText().toString().trim();
String password=recPassword.getText().toString().trim();
In the future, I highly recommend checking the Java String methods in the API. It's a lifeline to getting the most out of your Java environment.
You can easily remove all white spaces using something like this. But you'll face another serious problem if you just do that. For example if you have input
String input1 = "aa bb cc"; // output aabbcc
String input2 = "a abbcc"; // output aabbcc
String input3 = "aabb cc"; // output aabbcc
One solution will be to fix your application to accept white spaces in input string or use some other literal to replace the white spaces. If you are using only alphanumeric values you do something like this
String input1 = "aa bb cc"; // aa_bb_cc
String input2 = "a abbcc"; //a_abbcc
String input3 = "aabb cc"; //aabb_cc
And after all if you are don' caring about the loose of information you can use any approach you want.