Develop Reference

what is use of getchildnodes in code given below in android?

Here is My xml document iam trying to prase it using DOMXmlParser..
< records>
<employee>
<name>Sachin Kumar</name>
<salary>50000</salary>
</employee>
<employee>
<name>Rahul Kumar</name>
<salary>60000</salary>
</employee>
<employee>
<name>John Mike</name>
<salary>70000</salary>
</employee>
< /records>
Following is Code in OnCreate.
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv1 = (TextView) findViewById(R.id.textView1);
try {
InputStream is = getAssets().open("file.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(is);
Element element = doc.getDocumentElement();
element.normalize();
NodeList nList = doc.getElementsByTagName("employee");
System.out.println("No Of Collected Objects" + nList.getLength() );
for (int i = 0; i < nList.getLength(); i++) {
Node node = nList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE) {
Element element2 = (Element) node;
tv1.setText(tv1.getText()+"\n\nFirstName : "
+ getValue("firstname",element2) + "\n");
tv1.setText(tv1.getText()+"\n\nMiddleName : "
+ getValue("middlename",element2) + "\n");
tv1.setText(tv1.getText()+"\n\nLastName : "
+ getValue("lastname",element2) + "\n");
tv1.setText(tv1.getText() + "Salary : "
+ getValue("salary",element2) + "\n");
tv1.setText(tv1.getText() + "-----------------------");
}
}
}
Can anyone tell what is the use of getChildNodes in following code and why the item index should always be 0 ??.
private static String getValue(String tag, Element element) {
NodeList nodeList = element.getElementsByTagName(tag).item(0)
.getChildNodes();
Node node = (Node) nodeList.item(0);
return node.getNodeValue();
}

getChildNotes retrieves a list of all child nodes of the first element with "tag".
Then node is assigned the first element in the returned list.

How to Parse XML special characters from service by utf-8 encoding

I want to parse "ALışVERIş" type of content from service.
SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();
myXMLHandler = new XMLHandler();
xr.setContentHandler(myXMLHandler);
URL _url = new URL(params[0]);
xr.parse(new InputSource(_url.openStream()));

What I tried DOM Parser instead of XaxParser. Check below function and call it inside background thread :
public String readXML(){
StringBuilder stringBuilder = new StringBuilder();
try {
URL _url = new URL("http://182.160.161.2/~siva/turkish/web_serv/category.php?order_by=desc&category_id=2");
File fXmlFile = new File(new InputSource(_url.openStream()).getByteStream().toString());
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(new InputSource(_url.openStream()).getByteStream());
//optional, but recommended
//read this - http://stackoverflow.com/questions/13786607/normalization-in-dom-parsing-with-java-how-does-it-work
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("document");
Node nResp = nList.item(0);
Element fstElmnt = (Element) nResp;
NodeList nameList1 = fstElmnt.getElementsByTagName("response");
Node mCat = nameList1.item(0);
Element catElmt = (Element) mCat;
NodeList catList = catElmt.getElementsByTagName("category");
System.out.println("----------------------------");
for (int temp = 0; temp < catList.getLength(); temp++) {
Node nNode = catList.item(temp);
System.out.println("\nCurrent Element :" + nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
stringBuilder.append("Category ID : " + eElement.getElementsByTagName("category_name").item(0).getTextContent()+"\n");
stringBuilder.append("Category Name : " + eElement.getElementsByTagName("category_id").item(0).getTextContent());
System.out.println("Category ID : " + eElement.getElementsByTagName("category_name").item(0).getTextContent());
System.out.println("Category Name : " + eElement.getElementsByTagName("category_id").item(0).getTextContent());
}
}
} catch (Exception e) {
e.printStackTrace();
}
return stringBuilder.toString();
}
Here is a screenshot of my device, Have a look :
You can see those turkish language too :)

how to use listView with parsed strings in Android?

Here is my code. I want to see these parsed strings into ListView in Android. How can I do this?
DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xmlRecords));
Document doc = db.parse(is);
NodeList nodes = doc.getElementsByTagName("employee");
for (int i = 0; i < nodes.getLength(); i++) {
Element element = (Element) nodes.item(i);
NodeList name = element.getElementsByTagName("name");
Element line = (Element) name.item(0);
System.out.println("Name: " + getCharacterDataFromElement(line));
NodeList title = element.getElementsByTagName("title");
line = (Element) title.item(0);
System.out.println("Title: " + getCharacterDataFromElement(line));
}
}
public static String getCharacterDataFromElement(Element e) {
Node child = e.getFirstChild();
if (child instanceof CharacterData) {
CharacterData cd = (CharacterData) child;
return cd.getData();
}
return "";
}
}

Doc xml Parser android local xml file reading

I have one local xml file. I am storing here : res/xml/myxml.xml
<?xml version="1.0" encoding="utf-8"?>
<list>
<lists>
<tag>College Website</tag>
<value>http://www.nitk.ac.in/</value>
<lastupdate>04-07-2012</lastupdate>
</lists>
<lists>
<tag>College Images</tag>
<value>http://studentsworld.nitk.ac.in/index.php?q=convocation.html</value>
<lastupdate>25-9-2011</lastupdate>
</lists>
</list>
I have doc for loop. but how to connect local xml file in doc parser. i don't want url model, i want to a local xml file.
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
tag[i] = new TextView(this);
value[i] = new TextView(this);
lastupdate[i] = new TextView(this);
Element fstElmnt = (Element) node;
NodeList nameList = fstElmnt.getElementsByTagName("tag");
Element nameElement = (Element) nameList.item(0);
nameList = nameElement.getChildNodes();
tag[i].setText("tag = " + ((Node) nameList.item(0)).getNodeValue());
NodeList websiteList = fstElmnt.getElementsByTagName("value");
Element websiteElement = (Element) websiteList.item(0);
websiteList = websiteElement.getChildNodes();
value[i].setText("value = " + ((Node) websiteList.item(0)).getNodeValue());
NodeList lastupdateList = fstElmnt.getElementsByTagName("tag");
Element lastupdateElement = (Element) lastupdateList.item(0);
lastupdateList = lastupdateElement.getChildNodes();
lastupdate[i].setText("lastupdate = " + ((Node) lastupdateList.item(0)).getNodeValue());
layout.addView(tag[i]);
layout.addView(value[i]);
layout.addView(lastupdate[i]);
}
} catch (Exception e) {
System.out.println("XML Pasing Excpetion = " + e);
}
I have main.xml file
please send me a code

put you XML file in assets folder and try this
InputStream raw = getApplicationContext().getAssets().open("simple.xml");
and try this
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder= dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(raw);
....
...

put you XML file in assets folder and Try this way
String xml;
Document doc;
try{
xml=getXML(getAssets().open("yourxmlfilename.xml"));
}catch(Exception e){
Log.d("Error",e.toString());
}
doc = XMLfromString(xml);
where getXML and XMLfromString method are as shown below
//getXML method
public static String getXML(InputStream is)throws IOException {
BufferedInputStream bis = new BufferedInputStream(is);
ByteArrayOutputStream buf = new ByteArrayOutputStream();
int result = bis.read();
while(result != -1) {
byte b = (byte)result;
buf.write(b);
result = bis.read();
}
return buf.toString();
}
//XMLfromString method
public final static Document XMLfromString(String xml){
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
System.out.println("XML parse error: " + e.getMessage());
return null;
} catch (SAXException e) {
System.out.println("Wrong XML file structure: " + e.getMessage());
return null;
} catch (IOException e) {
System.out.println("I/O exeption: " + e.getMessage());
return null;
}
return doc;
}

please use below code for parse local xml,
InputStream in = this.getResources().openRawResource(R.raw.xmlfile);
And then parse inputstream,
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance ();
DocumentBuilder db = dbf.newDocumentBuilder ();
Document document = db.parse(in, null);

Can't parse XML with DOM in android

I am having some trouble parsing XML in Android from an URL. I don't know if it's the XML parsing that's the problem or only when I am trying to show it on the screen because
setListAdapter(new ArrayAdapter<String>(ANDROIDXMLActivity.this, android.R.layout.simple_list_item_1, stopNumbers));
wont show anything. The code below works perfectly in a java program.
URL: http://maps.travelsouthyorkshire.com/iGNMSearchService.asmx/FindObjectsWithinExtent?xMin=435360&yMin=387260&xMax=435960&yMax=387860&zoomLevel=0
try {
ArrayList<Double> xCords = new ArrayList<Double>();
ArrayList<Double> yCords = new ArrayList<Double>();
ArrayList<String> stopNumbers = new ArrayList<String>();
ArrayList<String> bussLocations = new ArrayList<String>();
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document doc = docBuilder
.parse(new URL(
"http://maps.travelsouthyorkshire.com/iGNMSearchService.asmx/FindObjectsWithinExtent?xMin=435360&yMin=387260&xMax=435960&yMax=387860&zoomLevel=0")
.openStream());
// normalize text representation
doc.getDocumentElement().normalize();
NodeList listOfObjects = doc.getElementsByTagName("iGNMObject");
for (int s = 0; s < listOfObjects.getLength(); s++) {
Node firstPersonNode = listOfObjects.item(s);
if (firstPersonNode.getNodeType() == Node.ELEMENT_NODE) {
Element firstPersonElement = (Element) firstPersonNode;
NodeList stopNumList = firstPersonElement
.getElementsByTagName("StopNumber");
Element ageElement = (Element) stopNumList.item(0);
if (ageElement != null) {
NodeList textAgeList = ageElement.getChildNodes();
String stop = ((Node) textAgeList.item(0))
.getNodeValue().trim();
stopNumbers.add(stop);
// ------
// -------
NodeList xPosList = firstPersonElement
.getElementsByTagName("XPosition");
Element firstNameElement = (Element) xPosList.item(0);
NodeList textFNList = firstNameElement.getChildNodes();
String temp2 = ((Node) textFNList.item(0))
.getNodeValue().trim();
double x = Double.parseDouble(temp2);
xCords.add(x);
// -------
NodeList yPosList = firstPersonElement
.getElementsByTagName("YPosition");
Element lastNameElement = (Element) yPosList.item(0);
NodeList textLNList = lastNameElement.getChildNodes();
String temp3 = ((Node) textLNList.item(0))
.getNodeValue().trim();
double y = Double.parseDouble(temp3);
yCords.add(y);
// ----
NodeList stopAkaList = firstPersonElement
.getElementsByTagName("StopAka");
Element stopAka = (Element) stopAkaList.item(0);
NodeList textStopAKAList = stopAka.getChildNodes();
String plats = ((Node) textStopAKAList.item(0))
.getNodeValue().trim();
bussLocations.add(plats);
} else {
}
}// end of if clause
}// end of for loop with s var
setListAdapter(new ArrayAdapter<String>(ANDROIDXMLActivity.this,
android.R.layout.simple_list_item_1, stopNumbers));
} catch (Exception e) {
}
}
}
}

Solved it. I had forgot to add internet permission in the manifest.