How to retrieve child data under 2 random keys - android

How do I display the RequestsID on a recyclerview only when stallID = 1?
How should my DatabaseReference be?
update:

Your database structure would not support orderByChild() from top node. So you would have to set your database reference upto the node food and then you can use orderByChild() query to find the Childs with certain stallID.
This, in code would look something like this:
DatabaseReference ref = FirebaseDatabase.getInstance().getReference().child("Requests").child("1542..").child("foods");
ref.orderByChild("stallID").equalTo(stallIDYouWant).addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(#NonNull DataSnapshot dataSnapshot) {
for (DataSnapshot ds : dataSnapshot.getChildren()){
// do here what you wanted
}
}
#Override
public void onCancelled(#NonNull DatabaseError databaseError) {
// ToDo: don't ignore this, do something for errors
}
)};
This would in fact not help you much because you'd have to set this for every unique id in your database structure.
So the better thing to do here would be make your database structure different. To know more how to make your structure good for this operation, refer this answer.

Related

How to get values from different child in firebase realtime database?

Here is my Database architecture where Jobs is the main child and under that there will be users child, and an user can post multiple time. now i want to get all the posts done by all the users at once. is it possible to do that?
https://i.stack.imgur.com/DT3MO.jpg
setQuery(FirebaseDatabase.getInstance().getReference().child("Jobs")
Used that query to get all of the posts from all of the users but didnt work. any better solution for this problem?
setQuery(FirebaseDatabase.getInstance().getReference().child("Jobs").child("Uid");
this one works but cant use this one because i want to set free for all users to read data.
You can do the following:
DatabaseReference reference = FirebaseDatabase.getInstance().getReference("Jobs");
reference.addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot ds : dataSnapshot.getChildren()){
String key = ds.getKey();
for (DataSnapshot childSnapshot: ds.getChildren()) {
// get the child attribute under the random key
}
}
}
#Override
public void onCancelled(DatabaseError databaseError) {
throw databaseError.toException();
}
});
Since you have a reference to node Jobs then in the first iteration you can get the random keys (highlighted in your image), and in the second iteration you can get the attributes inside those keys.

Retrieve Firebase data who have specific child

Please check my database image. I want to select and display all users who have parent = chris
my database image
To retrieve the users that contain parent : chris, you can do the following:
DatabaseReference reference = FirebaseDatabase.getInstance().getReference("users");
reference.orderByChild("parent").equalTo("chris").addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
for(DataSnapshot datas: dataSnapshot.getChildren()){
String name = datas.child("name").getValue(String.class);
String key = datas.getKey();
}
}
#Override
public void onCancelled(DatabaseError databaseError) {
throw databaseError.toException();
}
});
orderByChild.equalTo is a query that will retrieve all the nodes that contain parent equal to chris.
Since you tagged this as a android studio question I assume you are using the Firebase SDK.
You should check out the documentation, where they explain how you can query in a lot of languages with very nice examples.

firebase get value from uid after unkown uid

CABARAN is an unknown Uid. it is not a text. Right now I have the uid, and I want to get value for the tajukPenuh.
This is the code and I still can't get the value.
FirebaseDatabase.getInstance().getReference().child("karangan").addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(#NonNull DataSnapshot dataSnapshot) {
if (dataSnapshot.exists()) {
for (DataSnapshot child : dataSnapshot.getChildren()) {
Karangan karangan = child.child(karanganID).getValue(Karangan.class);
if (karangan != null) {
String tajukPenuh = karangan.getTajukPenuh();
holder.getTextViewKaranganID().setText("Karangan Tajuk: " + tajukPenuh);
}
}
}
}
#Override
public void onCancelled(#NonNull DatabaseError databaseError) {
}
});
You could in theory do a query like this:
FirebaseDatabase.getInstance().getReference().child("karangan")
.orderByChild("-LYgFIl4Xiv_Ls51Slvh/uid").equalTo("-LYgFIl4Xiv_Ls51Slvh")
.addListenerForSingleValueEvent(new ValueEventListener() {
But the problem is that you'd need a lot of indexes in your rules, which may be technically possible, but is unfeasible for most real usage.
Your current data structure makes it easy to find all the child nodes for CABARAN, but it does not make it easy to find CABARAN for a given child node. To allow that use-case to run efficiently, you should expand your data structure with a so-called reverse index that maps back to CABARAN from the value that you know. So something like:
"myIndex": {
"-LYgFIl4Xiv_Ls51Slvh": "CABARAN",
"-LzfFIl4Xasas51Slads": "CABARAN",
"-Lasddas981398asdh1h": "CASITWO"
}
This is an additional data structure, that you will have to keep up to date when you're writing the rest of the data. But with this structure, it now becomes very easy to determine that -LYgFIl4Xiv_Ls51Slvh maps to CABARAN.
For more on this, see my answer here: Firebase query if child of child contains a value

I can't get the key of firebase database

In my solution I save data from Windows form application. There is no problem. I can list them in my android app. On this point I am trying to get key value to update the data, but always I get null.
FirebaseDatabase database = FirebaseDatabase.getInstance();
DatabaseReference myReference = database.getReference();
Query myTopPostsQuery = myReference.child("DURUSLAR").orderByChild("kayitid").equalTo("1298843637");
myTopPostsQuery.addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot postSnapshot: dataSnapshot.getChildren())
{
//Childadi =postSnapshot.getKey().toString();
String anahtar=postSnapshot.getKey().toString();
Toast.makeText(getApplicationContext(),anahtar,Toast.LENGTH_LONG);
}
}
#Override
public void onCancelled(DatabaseError databaseError) {
}
});
Can you please help me?
When you execute a query at a location in the Firebase Database, it will search for the property you order/filter on in each child under that location. Since you query in /DURUSLAR, Firebase looks for /DURUSLAR/{something}/kayitid. Such a property does not exist, since you only have /DURUSLAR/{something}/{pushid}/kayitid.
To fix this problem you have two options:
query at a lower level
query to the property at its (fixed) path
The first option is to create the query at a lower level in the tree:
Query myTopPostsQuery = myReference.child("DURUSLAR/K6").orderByChild("kayitid").equalTo("1298843637");
Now the query is looking for /DURUSLAR/{pushid}/kayitid and it will work.
The second option is to query for the known path of the property:
Query myTopPostsQuery = myReference.child("DURUSLAR").orderByChild("K6/-KknsAR4_KFAeZ1HVXPW/kayitid").equalTo("1298843637");
It seems unlikely you want this here, but the approach may be helpful in other situations. Often when you need this approach with push IDs in the path, you'll want to look at http://stackoverflow.com/questions/40656589/firebase-query-if-child-of-child-contains-a-value.
The reason you are getting null is because you are doing orderByChild on the wrong level of data . According to your data u need to have a child K4-> which has a unique_id_push_id -> kayitid.Therefore you need to traverse the K4 in order to get 1298843637 for key kayitid.You can follow this tutorial to understand the retrieving of data from firebase .
Query myTopPostsQuery = myReference.child("DURUSLAR").child("k6").orderByChild("kayitid").equalTo("1298843637");
myTopPostsQuery.addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot postSnapshot: dataSnapshot.getChildren())
{
//Childadi =postSnapshot.getKey().toString();
String anahtar=postSnapshot.getKey().toString();
Toast.makeText(getApplicationContext(),anahtar,Toast.LENGTH_LONG);
}
}
#Override
public void onCancelled(DatabaseError databaseError) {
}
});

Firebase DatabaseReference filter by specified values

Lets suppose I have this firebase JSON structure:
And I need to get all the questions which have the atribute "from" equal to "this".
I know that I can use Volley to make a StringRequest and GET all values from my questions.json. Then, in the client side I could iterate over the response and remove the ones which don't have the correct atribute, but this would only work if I have a few questions. If I have millions of questions I would need to iterate over those millions of questions.
Is there any way I could put a filter on my request to get only the question with an attribute of my choice? (Ex: search questions.json where from == this)
Try this if may be useful in your scenario
DatabaseReference reference = FirebaseDatabase.getInstance().getReference();
Query query = reference.child("questions").orderByChild("from").equalTo("this");
query.addListenerForSingleValueEvent(new ValueEventListener() {
#Override
public void onDataChange(DataSnapshot dataSnapshot) {
if (dataSnapshot.exists()) {
for (DataSnapshot issue : dataSnapshot.getChildren()) {
// do with your result
}
}
}
#Override
public void onCancelled(DatabaseError databaseError) {
}
});
You can use equalTo
Query query = reference.child("questions").orderByChild("from").equalTo("this");

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