I have a NSFW class that scans texts like item names and descriptions against a list of known NSFW-words.
That would be the best approach to test a list of strings like
let nsfw = listof(
"badword",
"curseword",
"ass",
... 200+ more
)
against a string like:
This is the text that contains a badword // returns true
Please note that i need to check for full words. not parts of words.
so the sentence:
The grass is grean // returns false
Because grass is not a bad word.
Ive tried something like this but it doesnt check for full words.
val result = nsfw.filter { it in sentence.toLowerCase() }
You may build a regex like
\b(?:word1|word2|word3...)\b
See the regex demo. Then, use it with the Regex.containsMatchIn method:
val nsfw = listOf(
"badword",
"curseword",
"ass"
)
val s1 = "This is the text that contains a badword"
val s2 = "The grass is grean"
val rx = Regex("\\b(?:${nsfw.joinToString(separator="|")})\\b")
println(rx.containsMatchIn(s1)) // => true
println(rx.containsMatchIn(s2)) // => false
See this Kotlin demo.
Here, nsfw.joinToString(separator="|") joins the words with a pipe (the alternation operator) and the "\\b(?:${nsfw.joinToString(separator="|")})\\b" creates the correct regex.
If your words may contain special regex metacharacters, like +, ?, (, ), etc., you need to "preprocess" the nsfw values with the Regex.escape method:
val rx = Regex("\\b(?:${nsfw.map{Regex.escape(it)}.joinToString("|")})\\b")
^^^^^^^^^^^^^^^^^^^^^^
See the Kotlin demo.
AND one more thing: if the keywords may start/end with chars other than letters, digits and underscores, you cannot rely on \b word boundaries. You may
Use whitespace boundaries: val rx = Regex("(?<!\\S)(?:${nsfw.map{Regex.escape(it)}.joinToString("|")})(?!\\S)")
Use unambiguous word boundaries: val rx = Regex("(?<!\\w)(?:${nsfw.map{Regex.escape(it)}.joinToString("|")})(?!\\w)")
You can use split() on the string that you want to check, with space as a delimiter, so you create a list of its words, although this does not always guarantee that all words will be extracted successfully, since there could exist other word separators like dots or commas etc. If that suits you, do this:
val nsfw = listOf(
"badword",
"curseword",
"ass"
)
val str = "This is the text that contains a badword"
val words = str.toLowerCase().split("\\s+".toRegex())
val containsBadWords = words.firstOrNull { it in nsfw } != null
println(containsBadWords)
will print
true
If you want a list of the "bad words":
val badWords = words.filter { it in nsfw }
Related
Hello I need to compare 2 numbers and I used >, => but it doesn't compare whole number, it looks for the leftest(left) number and compare
for example the number is 92,236 and i want to compare it with 100,000, it says 92236 is bigger than 100,000 and it is because of the first number which is 9 and the first number of second number that is 1 so it says 100,000 is not bigger than 9236
here what I had done
class IncreaseMoneyFragment : Fragment() {
var decide = ""
val increaseEditText = mIncreaseMoneyBinding.increaseEdt.text.toString() (get value of edit text)
val currentPayment = it.payment (get loanPayment from database)
if (increaseEditText > currentPayment) {
Toast.makeText(activity, "more", Toast.LENGTH_SHORT).show()
val more = "بیشتر"
decide = more
} else {
Toast.makeText(activity, "less", Toast.LENGTH_SHORT).show()
val less = "کمتر"
decide = less
}
builder.setTitle(" مبلغ مورد نظر از مبلغ قسط وام $decide است. ادامه میدهید؟")
THANKS FOR HELPING ME :)
You are most likely comparing strings (text) and not numbers here. That's why it's using the alphabetical order instead of the integer order:
println("92236" > "100000") // true
println(92236 > 100000) // false
You probably want to convert your strings into integers instead:
if (increaseEditText.toInt() > currentPayment.toInt()) {
// ...
}
Note that toInt will crash if the strings are not actual numbers (for instance empty).
You can use toIntOrNull if you want more safety. It returns null if the string is not a number, so you can simply check for null and deal with this problem separately before comparing.
#SuppressLint("SetTextI18n")
private fun countName(x: String) {
val textView: TextView = findViewById(R.id.result)
for (i in 0 until x.length) {
textView.text = i.toString()
}
}
This is what I have so far. It works somewhat but for some reason it is lagging behind 1 number. For example, if I type James, the number it will output would be 4.
How to get the number of characters in a string (usually what you want):
str.length
How to get the number of Unicode code points in a string (because sometimes a code point is encoded as multiple characters):
str.codePointCount(0, str.length)
See this Java answer for more details on the difference between these two options.
There are many simple ways to get the number of characters in a string. but if you want to know the mistake in your code you should have started to count from 1 instead of 0.
for (i in 1 until x.length) {
textView.text = i.toString()
}
fun SubmitOrder(view: View) {
/* pricing of coffee */
val total = quantity * 5
val s: String = ("$$total.00")
money.text = ("Total : $s\nThank You!").toString()
//This is calling On click listener
Toast.makeText(this, "order_Submitted", Toast.LENGTH_SHORT).show()
}
In this code, I need a new line before Thank You! in money.text but I am not getting any new line I am new in android development so, am not able to point out the mistake.
Let's go thru your code line by line:
val s: String = ("$$total.00")
s is a bad variable name, as it's not descriptive at all
you don't need the (braces)
the :String here is optional. In such an obvious case i would emit it.
A $ is a sign to the kotlin compiler to include the following variable. Therefore, you can't use the $ when you mean "US-Dollar". See this post on how to escape it
While ".00" works, it's no good style. I suggest you use string formatting as described here.
can be written as val s = "\$ ${String.format("%.2f", total)}"
you should wherever possible use string resources, but thats out of the scope of this answer
money.text = ("Total : $s\nThank You!").toString()
this is correct, but unnecessary verbose:
"Total : $s\nThank You!" is already a string, so there's no need to .toString()
braces are not needed
can be written as money.text = "Total : $s\nThank You!"
I need help in matching the #mentions words which itself contains some ids which will be used to redirect users to particular userId.
Here is my string:
val string = "Hello #[%user%]Akash(ef54321). Is #[%user%]Shubham(45321gg) there with you?"
I need parsed response == "Hello #Akash. Is #Shubham there with you?"
Also onClick of #Akash And #Shubham I need ids which are there in format (xxxxx).And #mentions should appear in grey background.Any help would be highly appreciated.Thanks,
I am using
val string = "Hello #[%user%]Akash(54321).Is #[%user%]Shubham(543215) there with you "
val matcher = Pattern.compile("^[#]\\w+|(?<=\\s)[#]\\w+").matcher(string)
while (matcher.find()) {
println("TAG"+matcher.group())
}
You may use
val string = "Hello #[%user%]Akash(ef54321). Is #[%user%]Shubham(45321gg) there with you?"
val rx = Regex("""#\[%user%](\w+)\((\w+)\)""")
val res = string.replace(rx, "#$1")
println(res) // => Hello #Akash. Is #Shubham there with yo?
val users =rx.findAll(string).map{it.groups[1]!!.value}.toList()
val ids =rx.findAll(string).map{it.groups[2]!!.value}.toList()
println(users) // => [Akash, Shubham]
println(ids) // => [ef54321, 45321gg]
See the Kotlin demo.
The #\[%user%](\w+)\((\w+)\) regex contains two capturing groups for users and for IDs. In the replacement method, you may refer to those values using $1 and $2 placeholders.
Pattern details
#\[%user%] - a #[%user%] literal string
(\w+) - Capturing group 1 (user, $1): one or more letters, digits or underscores
\( - a ( char
(\w+) - Capturing group 2 (ID, $2): one or more letters, digits or underscores
\) - a ) char.
I am trying to concatenate 2 String but not sure how to go about it.
this is my code:
val word = R.string.word
and i'm trying to append it with "$currentPage/5" inside the setText("$currentPage/5")
i tried to make it in this way setText("$word $currentPage/5")
and this way setText("${R.string.value} $currentPage/5")
and it did not work , it only shows me numbers not the text
try to use this:
val word = getString(R.string.word)
text_view.text = "$word $currentPage/5"
If you want to edit your value (e.g. current page) wrap it with {}
E.g.
val word = getString(R.string.word)
text_view.text = "$word ${currentPage/5}"
Remember to use proper kotlin syntax
In Kotlin, the concatenation of string can be done by **interpolation/templates**.
val a = "Its"
val b = "Kotlin!"
val c = "$a $b"
The output will be Its Kotlin!
Or we can alson do concatenate using the **+ / plus() operator**:
val a = "String"
val b = "Concatenate"
val c = a + b
val d =a.plus(b)
print(c)
The output will be: StringConcatenate
print(d)
The output will be: StringConcatenate
Or you can concatenate using the StringBuilder which is a normal way to do that.
To concatenate two string, we could do
val concatenatedWord = "${resources.getString(R.string.value)}:
${number/3}."
If R.string.value was "The result" and number was 15, value of concatenatedWord will be "The result: 5."
Or we could also concatenate using the + operator or using StringBuilder.
But if you do
textView.text = "${resources.getString(R.string.value)}: ${number/3}."
AS will warn "Do not concatenate text displayed with setText." so, in the case of setting concatenated text in textview, consider using
String.format("%s: %d.", resources.getString(R.string.value):
number/3)
As a future resource and answer why the accepted answer works:-
String Templates:-
Strings may contain template expressions, i.e. pieces of code that are evaluated and whose results are concatenated into the string.
How to implement these?
A template expression should start with a dollar sign ($) and consists of either a simple name:
when the expression is a simple variable.
val i = 10
println("i = $i") // prints "i = 10"
or else arbitrary expression in curly braces:
val s = "abc"
println("$s.length is ${s.length}") // prints "abc.length is 3"
Note :- Templates are supported both inside raw strings and inside escaped strings.
val nameOfAnimal = "fish"
val speciesClass = "is an Aquatic Vertebrate"
println(nameOfAnimal.plus(speciesClass))
println(nameOfAnimal+speciesClass)
println("$nameOfAnimal $speciesClass")
Results:
fishis an Aquatic Vertebrate
fishis an Aquatic Vertebrate
fish is an Aquatic Vertebrate