I have an Activity and its layout. Now I need to add a LinearLayout from another layout, menu_layout.xml.
LayoutInflater inflater;
inflater = (LayoutInflater) this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
LinearLayout layout = (LinearLayout) inflater.inflate(R.layout.menu_layout, null);
After this, findViewById() returns null. Is there is any solution for that?
Note: I can't put both XML in one place, and using <include> also is not working.
Explanation
When you inflate a layout, the layout is not in the UI yet, meaning the user will not be able to see it until it's been added. To do this, you must get a hold of a ViewGroup (LinearLayout,RelativeLayout,etc) and add the inflated View to it. Once they're added, you can work on them as you would with any other views including the findViewById method, adding listeners, changing properties, etc
Code
//Inside onCreate for example
setContentView(R.layout.main); //Sets the content of your activity
View otherLayout = LayoutInflater.from(this).inflate(R.layout.other,null);
//You can access them here, before adding `otherLayout` to your activity
TextView example = (TextView) otherLayout.findViewById(R.id.exampleTextView);
//This container needs to be inside main.xml
LinearLayout container = (LinearLayout)findViewById(R.id.container);
//Add the inflated view to the container
container.addView(otherLayout);
//Or access them once they're added
TextView example2 = (TextView) findViewById(R.id.exampleTextView);
//For example, adding a listener to the new layout
otherLayout.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View view) {
//Your thing
}
});
Assuming
main.xml contains a LinearLayout with the id container
other.xml is a layout file in your project
other.xml contains a TextView with the id exampleTextView
Try using
layoutObject.findViewById();
I have an activity in which I need to add LinearLayout dynamically, by code (because it depends on the user input).
So, here is what I have done:
LayoutInflater inflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
LinearLayout lyt = (LinearLayout) inflater.inflate(R.layout.row_edit, mLytRows);
TextView tvName = (TextView) lyt.findViewById(R.id.name_textview);
tvName.setText(user.getName());
where R.layout.row_edit is a LinearLayout in which there are some Views, including a TextView, whereas mLytRows is a referenced LinearLayout (defined in the XML of the UI), in which I want to add the row_edit layout.
Based on the user input, I repeat this code several times and here is the problem:
when I try to reference the TextView, I aways get the TextView of the first LinearLayout I have added.
Why? How can I solve it, please?
Take a closer look at the documentation.
If you specify the second argument in inflate(), the method returns the parent, not the inflated View.
Hence, lyt is always your parent and findViewById always returns the first element it finds with the R.id.name_textview ID.
You might want to do
LayoutInflater inflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
LinearLayout lyt = (LinearLayout) inflater.inflate(R.layout.row_edit, null);
TextView tvName = (TextView) lyt.findViewById(R.id.name_textview);
tvName.setText(user.getName());
mLytRows.addView(lyt);
And in ViewGroup you can see there are several addView methods to place the view where you want.
In your res/layout/my_image_layout.xml
<LinearLayout
android:id="#+id/buttons"
...>
<ImageView ...
</ImageView>
</LinearLayout>
To grab that Layout by its #+id value inside your app/src/java/MyClass.java code, do this:
String myLinearLayoutName = "buttons";
LinearLayout myLinearLayoutID2 = (LinearLayout) activity.findViewById(activity.getResources()
.getIdentifier(myLinearLayoutName, "id", activity.getPackageName()));
/*Bottom code changes that LinearLayout's background to a different image. "bomb" (R.mipmap.bomb) is the name of an image I have in my drawable folder. */
myLinearLayoutID2.setBackgroundResource(R.mipmap.bomb);
I have a ViewSwitcher and want to add views to it:
// initialize views
final ViewSwitcher switcher = new ViewSwitcher(this);
layMenu = (LinearLayout)findViewById(R.id.menu_main_view);
final LevelPicker levelPicker = new LevelPicker(getApplicationContext());
(//)switcher.addView(layMenu);
(//)switcher.addView(findViewById(R.layout.menu_switcher));
One is a custom view, the other one from XML. I commented one of them, but they both seem to throwIllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.
I tried doing several things like putting the views in a 'container' first (another layout), or tried removeView((View)getParent), like I believe the logcat tries to say..
Here's my xml file (in a nutshell):
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="#+id/menu_main_view">
<TextView>
</TextView>
<LinearLayout>
<Button></Button> //couple of buttons
</LinearLayout>
</LinearLayout> //this is the parent i guess
My first guess was that all childs had to be in 1 parent, which in my case is the LinearLayout. This didn't seem to work.
Thanks
yes any View instance should have only 1 parent according to the source file
{android}/frameworks/base/core/java/android/view/View.java
in order to remove a View instance from its container, you need to do following things:
// View view = ...
ViewParent parent = view.getParent();
if (parent instanceof ViewGroup) {
ViewGroup group = (ViewGroup) parent;
group.removeView(view);
}
else {
throw new UnsupportedOperationException();
}
I guess you invoked Activity.this.setContentView(R.layout....) on the xml layout file. in this case, the parent of the LinearLayout view was another LinearLayout instance provided by a "decorate window".
it's often not a good practice to remove the only child of the "decorate window". you'd better create the children of the ViewSwitcher explicitly:
// Activity.this.setContentView(viewSwitcher);
// final Context context = Activity.this;
final android.view.LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
final View layMenu = inflater.inflate(R.layout...., null /* container */);
final View menuSwitcher = inflater.inflate(R.layout...., null /* container */);
viewSwitcher.addView(layMenu);
viewSwitcher.addView(menuSwitcher);
I want to inflate a childView of ExpandableChildView component.
Code:
public View getChildView(int groupPosition, int childPosition, boolean isLastChild, View convertView, ViewGroup parent) {
View v = convertView;
LinearLayout linearOpt = themesOptions.get(childPosition);
if(v == null) {
v = mInflater.inflate(R.layout.itemrow, null);
}
LinearLayout ll = (LinearLayout) v.findViewById(R.id.root);
ll.addView(linearOpt);
return v;
}
Where linearOpt is a vector that contains a lot of LinearLayout objects that I have instantiated.
private void prepareThemes(){
View v = mInflater.inflate(R.layout.widget_configure, null);
LinearLayout theme = (LinearLayout) v.findViewById(R.id.themeLayout);
LinearLayout color = (LinearLayout) v.findViewById(R.id.colorLayout);
LinearLayout trans = (LinearLayout) v.findViewById(R.id.transpLayout);
themesOptions.add(theme);
themesOptions.add(color);
themesOptions.add(trans);
}
This is R.layout.itemrow xml:
But I received this error:
07-18 10:48:49.740:
ERROR/AndroidRuntime(2738):
java.lang.IllegalStateException: The
specified child already has a parent.
You must call removeView() on the
child's parent first.
How I can resolve this issue?
I think the problem is caused by the manner you prepare the layouts in prepareThemes().
You didn't mention, but I assume your 'layout/widget_configure.xml' defines a structure like this:?
<LinearLayout android:id="#+id/root">
<LinearLayout android:id="#+id/themeLayout> <!-- ... --> </LinearLayout>
<LinearLayout android:id="#+id/colorLayout> <!-- ... --> </LinearLayout>
<LinearLayout android:id="#+id/transpLayout> <!-- ... --> </LinearLayout>
</LinearLayout>
Then you inflate this in prepareThemes() to get the 3 sub layouts. But at this moment they are already registered as children of the surrounding layout (which I called "root"). As the error implies a view instance can be added to just one parent.
You could store each LinearLayout in its own xml file and then inflate 3 times. Those stored layouts then could be add exactly once to a child.
I'm not sure what you want to do, but I would guess, it would be better - instead of preparing - to just have 3 different layouts that include the part from layout.itemrow and then just make a switch case in getChildView() and inflate the needed layout on the fly. Because even when you store a not bind layout in prepareThemes: As soon as you have more then one group you would get the same error when adding a prestored layout to the child of the snd group.
I hope this helps.
I have a layout defined in XML. It contains also:
<RelativeLayout
android:id="#+id/item"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
/>
I would like to inflate this RelativeView with other XML layout file. I may use different layouts depending on a situation. How should I do it? I was trying different variations of
RelativeLayout item = (RelativeLayout) findViewById(R.id.item);
item.inflate(...)
But none of them worked fine.
I'm not sure I have followed your question- are you trying to attach a child view to the RelativeLayout? If so you want to do something along the lines of:
RelativeLayout item = (RelativeLayout)findViewById(R.id.item);
View child = getLayoutInflater().inflate(R.layout.child, null);
item.addView(child);
You inflate an XML resource. See the LayoutInflater doc .
If your layout is in a mylayout.xml, you would do something like:
View view;
LayoutInflater inflater = (LayoutInflater) getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
view = inflater.inflate(R.layout.mylayout, null);
RelativeLayout item = (RelativeLayout) view.findViewById(R.id.item);
Though late answer,
but would like to add that one way to get this
LayoutInflater layoutInflater = (LayoutInflater)this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View view = layoutInflater.inflate(R.layout.mylayout, item );
where item is the parent layout where you want to add a child layout.
It's helpful to add to this, even though it's an old post, that if the child view that is being inflated from xml is to be added to a viewgroup layout, you need to call inflate with a clue of what type of viewgroup it is going to be added to. Like:
View child = getLayoutInflater().inflate(R.layout.child, item, false);
The inflate method is quite overloaded and describes this part of the usage in the docs. I had a problem where a single view inflated from xml wasn't aligning in the parent properly until I made this type of change.
Even simpler way is to use
View child = View.inflate(context, R.layout.child, null)
item.addChild(child) //attach to your item
Try this code :
If you just want to inflate your layout :
View view = LayoutInflater.from(context).inflate(R.layout.your_xml_layout,null); // Code for inflating xml layout
RelativeLayout item = view.findViewById(R.id.item);
If you want to inflate your layout in container(parent layout) :
LinearLayout parent = findViewById(R.id.container); //parent layout.
View view = LayoutInflater.from(context).inflate(R.layout.your_xml_layout,parent,false);
RelativeLayout item = view.findViewById(R.id.item); //initialize layout & By this you can also perform any event.
parent.addView(view); //adding your inflated layout in parent layout.
layout inflation
View view = null;
LayoutInflater inflater = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE);
view = inflater.inflate(R.layout.mylayout, null);
main.addView(view);
If you're not in an activity you can use the static from() method from the LayoutInflater class to get a LayoutInflater, or request the service from the context method getSystemService() too :
LayoutInflater i;
Context x; //Assuming here that x is a valid context, not null
i = (LayoutInflater) x.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
//OR
i = LayoutInflater.from(x);
(I know it's almost 4 years ago but still worth mentioning)
AttachToRoot Set to True
Just think we specified a button in an XML layout file with its layout width and layout height set to match_parent.
<Button xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="#+id/custom_button">
</Button>
On This Buttons Click Event We Can Set Following Code to Inflate Layout on This Activity.
LayoutInflater inflater = LayoutInflater.from(getContext());
inflater.inflate(R.layout.yourlayoutname, this);
Hope this solution works for you.!
If you want to add a single view multiple time then you have to use
layoutInflaterForButton = getActivity().getLayoutInflater();
for (int noOfButton = 0; noOfButton < 5; noOfButton++) {
FrameLayout btnView = (FrameLayout) layoutInflaterForButton.inflate(R.layout.poll_button, null);
btnContainer.addView(btnView);
}
If you do like
layoutInflaterForButton = getActivity().getLayoutInflater();
FrameLayout btnView = (FrameLayout) layoutInflaterForButton.inflate(R.layout.poll_button, null);
and
for (int noOfButton = 0; noOfButton < 5; noOfButton++) {
btnContainer.addView(btnView);
}
then it will throw exception of all ready added view.
If you are you trying to attach a child view to the RelativeLayout? you can do by following
RelativeLayout item = (RelativeLayout)findViewById(R.id.item);
View child = getLayoutInflater().inflate(R.layout.child, item, true);
I had the hardest time with this error, because of my unique circumstances, but finally found a solution.
My situation: I am using a separate view (XML) which holds a WebView, then opens in an AlertDialog when I click a button in my main activity view. But somehow or another the WebView belonged to the main activity view (probably because I pull the resource from here), so right before I assigned it to my AlertDialog (as a view), I had to get the parent of my WebView, put it into a ViewGroup, then remove all the views on that ViewGroup. This worked, and my error went away.
// set up Alert Dialog box
AlertDialog.Builder alert = new AlertDialog.Builder(this);
// inflate other xml where WebView is
LayoutInflater layoutInflater = (LayoutInflater)this.getSystemService
(Context.LAYOUT_INFLATER_SERVICE);
View v = layoutInflater.inflate(R.layout.your_webview_layout, null);
final WebView webView = (WebView) v.findViewById(R.id.your_webview_id);
// more code...
.... later on after I loaded my WebView ....
// first, remove the parent of WebView from it's old parent so can be assigned a new one.
ViewGroup vg = (ViewGroup) webView.getParent();
vg.removeAllViews();
// put WebView in Dialog box
alert.setView(webView);
alert.show();
With Kotlin, you can use:
val content = LayoutInflater.from(context).inflate(R.layout.[custom_layout_name], null)
[your_main_layout].apply {
//..
addView(content)
}
When add a layout to an Activity in Kotlin, see these steps:
Add just in Activity - One layout as a parent
Xml file of new
Layout Give the value of R.
val parent: LinearLayout =findViewById(R.id.stars)
val view =
LayoutInflater.from(applicationContext).inflate(R.layout.another, parent,false)
Where parent is not necessary, can be null But warning message will be appear
view.findViewById<ImageView>(R.id.ivTimer).setImageResource(R.drawable.t2)
Any view must be set value in this way, finally add
parent.apply { addView(view)}
I had used below snippet of code for this and it worked for me.
LinearLayout linearLayout = (LinearLayout)findViewById(R.id.item);
View child = getLayoutInflater().inflate(R.layout.child, null);
linearLayout.addView(child);