Develop Reference

Image not updating which is uploaded using volley and glide

I am using Volley library in my app to upload image and Glide for setting image to textview. I have button to update image which opens gallery and let user select the image. The file is then uploaded in the specific folder successfully, but the image remains same. I also tried logout and login user which erases the values in ShredPreferences, all data updates, but image remains same. The older image is replaced by new in server folder, but still shows in app. It only updates after clearing app data from Settings. Why is this happening? does glide stores the cache data? how to get rid of this?

Glide caches the image from server by default. So if your URL is not changing, it will show you the image from the cache. To work around this, you can use RequestOptions:
RequestOptions requestOptions = new RequestOptions()
.diskCacheStrategy(DiskCacheStrategy.NONE)
.skipMemoryCache(true);
Glide.with(this)
.load(YOUR_IMAGE_URL)
.apply(requestOptions)
.into(YOUR_IMAGEVIEW);
EDIT (Picasso)
If you are using Picasso, the same case applies. In this case you should use:
Picasso.with(this)
.load(YOUR_IMG_URL)
.memoryPolicy(MemoryPolicy.NO_CACHE, MemoryPolicy.NO_STORE)
.networkPolicy(NetworkPolicy.NO_CACHE)
.into(YOUR_IMAGEVIEW);

How to remove a particular image URL from disk cache in Glide?

I am loading an image from remote URL into an ImageView with Glide. When I update the image, the content within that URL changes, but the URL location remains same. (This is as expected).
for eg. https://www.the-android-app.com/userid/121.jpg
Now I am showing image into ImageView using this code.
Glide
.with(this)
.load(profilePicUrl) //this is in String format
.diskCacheStrategy(DiskCacheStrategy.RESULT)
.skipMemoryCache(true)
.error(R.drawable.default_profile_pic)
.into(imgProfilePic);
When I update my profile pic, Glide is loading the same old pic from Cache. I need to remove cache entry for this URL before fetching the new image.
Edit:
The url always remains same, only the content inside it changes.
I'm using Glide 3.8.0

You can try signature(new ObjectKey(System.currentTimeMillis()))
Look in Custom cache invalidation for more information.
Example
GlideApp.with(this)
.load(imageUrl)
.signature(new ObjectKey(System.currentTimeMillis()))
.into(imageView);

Display multiple image with Glide

I want to display one image into two different image views using glide.I know that i can simply use the code below to do it.
ImageView imageView = findViewById(R.id.header_image);
Glide.with(this).load(R.drawable.header_image).into(imageView);
ImageView imageView2 = findViewById(R.id.header_image);
Glide.with(this).load(R.drawable.header_image).into(imageView2);
But it requires to load the same image twice into memory and i don't want that due to memory issues.I want to load the image once and diaplay it into two image views.What can i do to achieve it?

You no need to worry about memory issue while using glide because glide has own caching system to optimize memory pls read this doc
Glide provides a number of options that allow you to choose how loads will interact with Glide’s caches on a per request basis.
Disk Cache Strategies
DiskCacheStrategy can be applied with the diskCacheStrategy method to an individual request. The available strategies allow you to prevent your load from using or writing to the disk cache or choose to cache only the unmodified original data backing your load, only the transformed thumbnail produced by your load, or both.
The default strategy, AUTOMATIC, tries to use the optimal strategy for local and remote images. AUTOMATIC will store only the unmodified data backing your load when you’re loading remote data (like from URLs) because downloading remote data is expensive compared to resizing data already on disk. For local data AUTOMATIC will store the transformed thumbnail only because retrieving the original data is cheap if you need to generate a second thumbnail size or type.
To apply a DiskCacheStrategy:
GlideApp.with(fragment)
.load(url)
.diskCacheStrategy(DiskCacheStrategy.ALL)
.into(imageView);
Loading only from cache
In some circumstances you may want a load to fail if an image is not already in cache. To do so, you can use the onlyRetrieveFromCache method on a per request basis:
GlideApp.with(fragment)
.load(url)
.onlyRetrieveFromCache(true)
.into(imageView);
If the image is found in the memory cache or in the disk cache, it will be loaded. Otherwise, if this option is set to true, the load will fail.

You can use following code to load an image once and display it in multiple imageviews.
Glide.with(this)
.asBitmap()
.load(R.drawable.header_image)
.into(new SimpleTarget<Bitmap>() {
#Override
public void onResourceReady(#NonNull Bitmap resource, #Nullable Transition<? super Bitmap> transition) {
imageview.setImageBitmap(resource);
imageview2.setImageBitmap(resource);
}
});

If you are using latest version of Glide then create RequestOptions like
private RequestOptions simpleOptions = new RequestOptions()
.centerCrop()
.placeholder(R.color.color_gray)
.error(R.color.color_gray)
.diskCacheStrategy(DiskCacheStrategy.RESOURCE);
Use RequestOptions to load image with set properties
Glide.with(context)
.load(url)
.apply(simpleOptions)
.into(imageView);

Or maybe this way…
RequestBuilder<Drawable> builder = Glide.with(this).load(drawableResId);
builder.into(imageView0)
builder.into(imageView1)

try this way ...
setImage(R.drawable.header_image,imageView ,imageView2 );
void setImage(int image, ImageView... imageView) {
for (ImageView imageView : imageView) {
if (imageView != null) {
Glide.with(this).load(image).into(imageView);
}
}
}

cache image without showing glide

Is it possible to cache image using glide without showing it in the imageView?. If it is then how?.
Right now I'm doing this code:
Glide
.with(getApplicationContext())
.load("imageUrl")
.override(windowWidth(),(int)windowWidth()*0.5))
.diskCacheStrategy(DiskCacheStrategy.ALL);
But this is not working , when app is open glide load image not from cache but from url.

Since glide 4.X:
//to save img
RequestManager rm = Glide.with(context);
rm.load(imgUrl).submit();
//to load img
Glide.with(context)
.applyDefaultRequestOptions(
new RequestOptions().diskCacheStrategy(DiskCacheStrategy.ALL))
.load(imgUrl)
.into(view);
Based on this GitHub topic

i've never used it, but referring the documentation: have you tried the downloadOnly?
Glide's downloadOnly() API allows you to download the bytes of an image into the disk cache so that it will be available to be retrieved later.
https://github.com/bumptech/glide/wiki/Loading-and-Caching-on-Background-Threads#downloadonly

To preload remote images and ensure that the image is only downloaded once:
Glide.with(context)
.load(yourUrl)
.diskCacheStrategy(DiskCacheStrategy.SOURCE)
.preload();

how to cache image with a new one which have the same url?

i have listview to load images for alot of users and this listview item has an imageview for profile picture of user, the problem here if the user changed his the new image will not be shown as last profile picture is cached and the old one will be displayed because the new and old image have the same url:
URL EX:
"https://xyz.s3.amazonaws.com/users/" + friend_id + "/photos/profile.jpg"
i used Glide but i have the same problem

This issue is because of the cache of images, Glide checks if image is available in cache, if it does glide loads it else it would load the new image.
To solve this issue you need to change its cache strategy like this
Glide.with(mContext)
.load((Integer) mDataset.get(position))
.fitCenter()
.diskCacheStrategy(DiskCacheStrategy.NONE) // this will prevent image to be cached and each time glide will load it from server
.into(imageView);