Develop Reference

How to get path of any file from my my application data folder

My application files are bellow, I want to get sharethis.png file in java code , What is syntax ?
I used this ...
Bitmap bMap = BitmapFactory.decodeFile("file:///android_asset/www/sharethis.png");
but not working

Try:
Bitmap shareThis = BitmapFactory.decodeResource(context.getResources(),
R.drawable.shareThis);

If you want to reference it from a JavaScript or html file in your assets folder, use file:///android_asset/www/sharethis.jpg.
Otherwise, according to this answer, this will list all the files in the assets folder:
AssetManager assetManager = getAssets();
String[] files = assetManager.list("");
This to open a certain file:
InputStream input = assetManager.open(assetName);

Try this:
try {
// get input stream
InputStream ims = getAssets().open("sharethis.png");
// load image as Drawable
Drawable d = Drawable.createFromStream(ims, null);
// set image to ImageView
mImage.setImageDrawable(d);
}
catch(IOException ex) {
Log.e("I/O ERROR","Failed")
}

Instead of using the assets dir, put the file into /res/raw , and you can then access it using the following URI: android.resource://com.your.packagename/" + R.raw.sharethis

The most efficient way to show the local image in android

I am currently work on a magazine like apps. Since there is an option to zoom in(150%, 200%, 250% of original source) , I would prefer not to scale down the image. However , the app will force restart when I try to decode the image because of the out of memory. Are there any suggestion to fix that?
The image are local (SD card) , can be retrieve in any approach, but eventually need to be a bitmap as I use something like cavans.drawbitmap to display it. I tried, input stream-> bytes , input stream->bitmap etc... but are there any most efficient way or at least
I can sure the app does not force restart / close? Thanks
try {
InputStream is = (InputStream) new URL(url).getContent();
try {
return BitmapFactory.decodeStream(is);
} finally {
is.close();
}
} catch (Exception e) {
return BitmapFactory.decodeResource(context.getResources(), defaultDrawable);
}

You should consider using nostra's image loader, it deals with memory quite efficiently, you can specify lots of config stuffs, im using it and its working pretty well for large images aswell

This is what smartImageView(by loopj - you can find him on http://loopj.com/) uses to retrieve files from the drive/sd.
private Bitmap getBitmapFromDisk(String imgID) {
Bitmap bitmap = null;
if(diskCacheEnabled){
String filePath = getFilePath(imgID);
File file = new File(filePath);
if(file.exists()) {
bitmap = BitmapFactory.decodeFile(filePath);
}
}
return bitmap;
}

Get R.drawable ID's dynamically in android

I have a folder with a few images, these images are added by user dynamically. So i need to get the R.drawable ID's of these images in android.... ???

Where are you saving these images too? When images are being added dynamically at runtime usually you need to store them on the phones storage. If you want the images to be stored in the external storage (SDCard) then you can use the following code to retrieve them and add them to your view (Which I assume your doing). This code assumes the images are being stored to your devices SDCard, which is where they will be pulled from.
//Get root directory of storage directory, pass in the name of the Folder if they are being stored farther down, i.e getExternalFilesDir("FolderName/FolderName2")
String state = Environment.getExternalStorageState();
if (Environment.MEDIA_MOUNTED.equals(state)) {
// We can read and write the media
File dir = getExternalFilesDir(null);
Bitmap bmap = null;
try {
InputStream is = new FileInputStream(new File(dir,"image.jpg"));
bmap = BitmapFactory.decodeStream(is);
} catch (FileNotFoundException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
if (bmap!=null) {
ImageView view = new ImageView(this);
view.setImageBitmap(bmap);
}
}

Android Show image by path

i want to show image in imageview without using id.
i will place all images in raw folder and open
try {
String ss = "res/raw/images/inrax/3150-MCM.jpg";
in = new FileInputStream(ss);
buf = new BufferedInputStream(in);
Bitmap bMap = BitmapFactory.decodeStream(buf);
image.setImageBitmap(bMap);
if (in != null) {
in.close();
}
if (buf != null) {
buf.close();
}
} catch (Exception e) {
Log.e("Error reading file", e.toString());
}
but this is not working i want to access image using its path not by name

read a stream of bytes using openRawResource()
some thing like this should work
InputStream is = context.getResources().openRawResource(R.raw.urfilename);
Check this link
http://developer.android.com/guide/topics/resources/accessing-resources.html#ResourcesFromCode
It clearly says the following
While uncommon, you might need access your original files and directories. If you do, then saving your files in res/ won't work for you, because the only way to read a resource from res/ is with the resource ID
If you want to give a file name like the one mentioned in ur code probably you need to save it on assets folder.

You might be able to use Resources.getIdentifier(name, type, package) with raw files. This'll get the id for you and then you can just continue with setImageResource(id) or whatever.
int id = getResources().getIdentifier("3150-MCM", "raw", getPackageName());
if (id != 0) //if it's zero then its not valid
image.setImageResource(id);
is what you want? It might not like the multiple folders though, but worth a try.

try {
// Get reference to AssetManager
AssetManager mngr = getAssets();
// Create an input stream to read from the asset folder
InputStream ins = mngr.open(imdir);
// Convert the input stream into a bitmap
img = BitmapFactory.decodeStream(ins);
} catch (final IOException e) {
e.printStackTrace();
}
here image directory is path of assets
like
assest -> image -> somefolder -> some.jpg
then path will be
image/somefolder/some.jpg
now no need of resource id for image , you can populate image on runtime using this

How to get access to raw resources that I put in res folder?

In J2ME, I've do this like that:
getClass().getResourceAsStream("/raw_resources.dat");
But in android, I always get null on this, why?

For raw files, you should consider creating a raw folder inside res directory and then call getResources().openRawResource(resourceName) from your activity.

InputStream raw = context.getAssets().open("filename.ext");
Reader is = new BufferedReader(new InputStreamReader(raw, "UTF8"));

In some situations we have to get image from drawable or raw folder using image name instead if generated id
// Image View Object
mIv = (ImageView) findViewById(R.id.xidIma);
// create context Object for to Fetch image from resourse
Context mContext=getApplicationContext();
// getResources().getIdentifier("image_name","res_folder_name", package_name);
// find out below example
int i = mContext.getResources().getIdentifier("ic_launcher","raw", mContext.getPackageName());
// now we will get contsant id for that image
mIv.setBackgroundResource(i);

Android access to raw resources
An advance approach is using Kotlin Extension function
fun Context.getRawInput(#RawRes resourceId: Int): InputStream {
return resources.openRawResource(resourceId)
}
One more interesting thing is extension function use that is defined in Closeable scope
For example you can work with input stream in elegant way without handling Exceptions and memory managing
fun Context.readRaw(#RawRes resourceId: Int): String {
return resources.openRawResource(resourceId).bufferedReader(Charsets.UTF_8).use { it.readText() }
}

TextView txtvw = (TextView)findViewById(R.id.TextView01);
txtvw.setText(readTxt());
private String readTxt()
{
InputStream raw = getResources().openRawResource(R.raw.hello);
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
int i;
try
{
i = raw.read();
while (i != -1)
{
byteArrayOutputStream.write(i);
i = raw.read();
}
raw.close();
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
return byteArrayOutputStream.toString();
}
TextView01:: txtview in linearlayout
hello:: .txt file in res/raw folder (u can access ny othr folder as wel)
Ist 2 lines are 2 written in onCreate() method
rest is to be written in class extending Activity!!

getClass().getResourcesAsStream() works fine on Android. Just make sure the file you are trying to open is correctly embedded in your APK (open the APK as ZIP).
Normally on Android you put such files in the assets directory. So if you put the raw_resources.dat in the assets subdirectory of your project, it will end up in the assets directory in the APK and you can use:
getClass().getResourcesAsStream("/assets/raw_resources.dat");
It is also possible to customize the build process so that the file doesn't land in the assets directory in the APK.

InputStream in = getResources().openRawResource(resourceName);
This will work correctly. Before that you have to create the xml file / text file in raw resource. Then it will be accessible.
Edit Some times com.andriod.R will be imported if there is any error in layout file or image names. So You have to import package correctly, then only the raw file will be accessible.

This worked for for me: getResources().openRawResource(R.raw.certificate)