I need to do an API call from a Dialog. Do I need to go back to the fragment for doing so, or is there any way to refer to the fragment view model?
Yes, it is possible and I was able to do that because class DialogFragment extends Fragment. So I added a view model just like any other fragment.
like below where BaseDialog class extends DialogFragment
You can try with this:
Use interface, implement it in fragment so you have callback funtion.
Pass high ordered function, declare it like this in dialog:
var click: (() -> Unit)? = null;
Then you can set it from fragment when you instantiate your dialog.
Use shared view model, for example make view model in your activity and then you can access it from every fragment or dialog like this:
(requireActivity() as MainActivity).viewModel
Like this you can set value in view model variable (liveData often) inside your dialog and observe changes in fragment
I think you can pass a high ordered function to dialog and handle it in fragment using viewModel inside.
Related
I have a navigation as follows:
FragmentList -> FragmentDetailA -> FragmentDetailB -> FragmentDetailC
I use a viewModel for the detail FragmentDetailViewModel
private val detailViewModel: DetailViewModel by activityViewModels()
But if I go forward, and then back, the above fragmentDetails are changed. How to have a viewmodel assigned to the fragment without changing the others?
Solution:
First of all, change activityViewModels() for viewModels()
Then, the problem was with setFragmentResultListener. It was called before instantiating the new fragment, then the call was made on Fragment A and not on Fragment B. I decided to pass data between destinations with Bundle objects.
Thanks a lot
With this way that you initialized view model, view model depends on the parent activity you must use this way
private val detailViewModel: DetailViewModel by viewModels()
to your view model instance depends on your fragment instance.
It sounds like you want to link the viewmodel to the fragment.
ViewModelProvider(this,viewModelFactory).get(MyViewModel.class)
We have lots of dialog need to show in ActivityA, ActivityA has ViewModelA, which has the live data to control when need to show dialog. Can I create dialog in ViewModelA and pass the dialog as a parameter in the LiveData?
In ViewModelA have
MutableLiveData<SingleLiveEvent<DialogEvent> dialogEvent;
For DialogEvent:
class DialogEvent(DialogFragment dialog)
When need to display dialog, update dialogEvent.
SomeDialogFragment fragment = new SomeDialogFragment.newInstance();
dialogEvent.postValue(new SingleLiveEvent(fragment));
In ActivityA observe the dialogEvent
viewModelA.getDialogEvent().observe {event -> event.dialog.show()}
ViewModel shouldn't hold reference to Views. According to me, you can have your custom model for your dialog as LiveData and observe the data in your fragment/activity and take actions say show/hide/text on that basis from fragment/activity itself. Feel free to ask in doubt.
I have an activity like this:
There are 2 buttons A and B on toolbar and a frame for fragment to take over. Say I have a string variable named button_type in fragment.
I want to have a system so that when I click button A in activity, the button_type in fragment sets to A and when I click button B in activity, the button_type in fragment sets to B.
How to do this?
Please note that I may click the buttons (A,B) when the fragment is already active (its not like after I click one button, the fragment comes.)
Thanks in advance.
Edit:
Currently I am trying this:
In MainActivity I get similar string button_type and set it as A or B according as button click and use the method:
public String getData(){return button_type;}
And in fragment I use: button_type= activity.getData(); in onViewCreated.
But it only seems to have the initial set value of A and B (which is A) and does not change when another button is clicked.
I think the best way if you use an interface for managing text in the fragment. the fragment will implement the interface. When the button click call the function in the fragment which is implemented by fragment.
Another way you can create an object of the fragment using findFragmentByTag() or findFragmentById() and then call the function in the fragment which handles the text.
Create an interface with methods onClickA(String buttonType) and onClickB(String buttonType).
Then create an object that implements this interface (or make fragment implement this interface by itself). I'll call this object listener.
call setButtonType(String buttonType) in listener methods implementation.
Then pass your listener to activity (you can get an instance of parent activity in fragment with getActivity() and cast it to your activity class) and in onClickListener of button A (in activity) call listener.onClickA(yourString) and do the same thing for button B.
Hello i create class that implement BottomSheetDialogFragment with dynamic content. The content is a Fragment. So when initialize the BottomSheet i passing fragment object, and attach it to specific Container ID inside this BottomSheetDialogFragment. Looks like this :
private fun attachContentFragment() {
val transaction = childFragmentManager.beginTransaction()
transaction.apply {
replace(R.id.flContent, state.layoutContent)
commit()
}
}
state.layoutContent is my attached Fragment
I need to dismiss the BottomSheet if every action called in that fragment.
As far as i know, i need to get the object of BottomSheet that hold me(Fragment) and dismiss it.
But how i can get that BottomSheet object?
Thanks
So, technically it is a fragment inside fragment situation. I think there is several solutions here:
Call Activity from your child fragment. BottomSheetDialogFragment will subscribe to Activity for such events and react on them.
Get the instance of a BottomSheetDialogFragment by calling proper FragmentManager (which possible is an Activity one). You can get an instance of a fragment byTag for example.
Or you can call getParentFragment from a child Fragment.
I have a tabbed activity that shows a fragment by a viewpager, as usual.
This fragment have a list.
One of the actions of the user shows a dialogfragment to user insert a new item in this list.
I show the dialogfragment with edittexts to user create a new item.
The question is: how can I insert this item on the viewpagers' fragment list?
From any fragment I can call getActivity() to access the activity, but how access another fragment that is being shown behind the dialogfragment?
Thanks in advance.
Fragment with the List items - FragmentA
Dialog - NewItemDialogFragment
The method you're missing is setTargetFragment(). While building your NewItemDialogFragment, invoke this method passing the FragmentA as the target fragment for your dialog.
Later, you can access the FragmentA instance by calling getTargetFragment() inside NewItemDialogFragment and cast it to the FragmentA and add newly created item.
Alternatively, you can create the contract interface between the FragmentA and the NewItemDialogFragment
It sounds like you want to get the results from the dialogfragment (what the user has inserted on the dialogfragment edit-texts) and use this in the fragment that called the dialogfragment (to add as new item to the list) - in that case, the selected answer here solves this problem - also I think this Gist is a good resource to reference.
In your case, I also think implementing some sort of a custom listener/callback as they did in this Gist is a good idea. Hope this helps.
You can use event bus for this.
http://square.github.io/otto/
This is an example of usage:
Bus bus = new Bus();
bus.post(new AnswerAvailableEvent(42));
#Subscribe public void answerAvailable(AnswerAvailableEvent event) {
// TODO: React to the event somehow!
}
bus.register(this); // In order to receive events, a class instance needs to register with the bus.