Develop Reference

Android DateFormatter print Eastern Daylight Time instead of EDT

So Im trying to print the string "Eastern Daylight Time" instead of EDT . This should be dynamic and not hardcoded. Looking into DateFormatter class did not lead me to an answer that worked.
Here was an example that allows me to format but did not lead me to my specific answer.
I am getting the date back in the following format -
2013-06-08T00:00:00-04:00
Here are somethings that I have tried -
1)
String dateString = changeFormatDateStringWithDefaultTimeZone(paymentConfirmation.getTransactionDate(),
"yyyy-MM-dd'T'HH:mm:ssZ",
"M/d/yyyy hh:mm a zz");
public static String changeFormatDateStringWithDefaultTimeZone(String value, String ip_format, String op_format) {
if (value == null)
return null;
try {
SimpleDateFormat opSDF = new SimpleDateFormat(op_format, Locale.US);
opSDF.setTimeZone(TimeZone.getDefault());
SimpleDateFormat inSDF = new SimpleDateFormat(ip_format, Locale.US);
Date date = inSDF.parse(value);
return(opSDF.format(date));
} catch (Exception e) {
Log.e("Err", "Failed to convert time "+value);
e.printStackTrace();
}
return null;
}
2)
Date today = Calendar.getInstance().getTime();
String todayString = DateUtils.convertDateToStringWithTimeZone(today);
public static String convertDateToStringWithTimeZone(Date date){
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
String dateString = df.format(date);
dateString += " " + TimeZone.getDefault().getDisplayName(false, TimeZone.LONG);
return dateString;
}
These always print timezone as EDT and I want the string Eastern Daylight Time. Can anyone help me out with this?

Okay, based on your last edit of the question, the solution should be like this:
case 1)
The output pattern should be changed to "M/d/yyyy hh:mm a zzzz" (note the count of z-symbols to enforce the full zone name). Depending on the date and the underlying timezone, the formatter SimpleDateFormat will automatically determine if the daylight or the standard name is to be used.
case 2)
Use TimeZone.getDefault().getDisplayName(true, TimeZone.LONG) to enforce the long daylight name. If your default timezone is "America/New_York" then such an expression should print "Eastern Daylight Time". Note that the boolean parameter has been changed to true.

How to covert string data like 2016-4-10 00:00:00 to timestamp?

I want convert data like 2016-4-10 00:00:00 to timestamp.
I use this code (I send this date as argument to this method):
public static long parseUTimeAndGiveTimestamp(String time) {
if (time != null && !time.equals("")) {
long longTime = 0;
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd kk:mm:ss.SSS");
Date date;
try {
time += ".000";
date = sdf.parse(time);
} catch (Exception e) {
e.printStackTrace();
return longTime;
}
longTime = date.getTime();
return longTime / 1000;
}
return 0;
}
But I get 1460235600 value and if I convert it to date again I get:
Sat, 09 Apr 2016 21:00:00
(before 10.04 - after 09.04)
So you can help me?

There is no issue with your code. There is some issue with the timezones. Your SimpleDateFormat will be using your local timezone. You probable might be getting the timestamp for your locale and while converting it back to the date, you are checking in GMT timezone. To test this just add
sdf.setTimeZone(TimeZone.getTimeZone("GMT"));
before parsing the date.
So basically you are not using the same timezones to convert date to timestamp and while converting timestamp to zone.

try to use one M to parse single-digit month format. It also handles two-digits correctly...
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-M-dd kk:mm:ss.SSS");

standard time vs miltary time

Im trying to display the current time in a format like 7:45pm instead of 19:45 but i can't seem to find the right format option.
Time cTime= new Time(Time.getCurrentTimezone());
cTime.setToNow();
clock.setText(cTime.format("%H:%M"));
This seems to display military

You're using Time.format(), so you can refer to the C++ strftime documentation for formatting rules. Your format string should be %I:%M%P for 12-hour time.

Use SimpleDateFormat with a - meaning am/pm marker.
Example:
Calendar cal = Calendar.getInstance();
SimpleDateFormat dateFormat = new SimpleDateFormat("h:mmaa");
try {
String now = dateFormat.format(cal.getTime());
} catch (ParseException e) {
e.printStackTrace();
}

Convert DateTime object java to Json string

I want to convert date time object in java to json string in format as below:
{"date":"/Date(18000000+0000)/"}
I did like this but it didn't give me the format i desired:
JSONObject object = new JSONObject();
object.put("date",new Date());
and the result of object.toString()
{"date":"Fri May 04 11:22:32 GMT+07:00 2012"}
i want the string "Fri May 04 11:22:32 GMT+07:00 2012" transform to "/Date(18000000+0000)/" (18000000+0000 here is just a example).
Thanks for your help.

Here is my solution, although it is not a good way, but I finally find a workable solution.
SimpleDateFormat format = new SimpleDateFormat("Z");
Date date = new Date();
JSONObject object = new JSONObject();
object.put("date", "/Date(" + String.valueOf(date.getTime()) + format.format(date) + ")/");

public static String convertToJsonDateTime(String javaDate)
{
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd HH:mm:ss");
Date currentDate = null;
try {
currentDate = dateFormat.parse(javaDate);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
long time =currentDate.getTime();
return "\\/Date("+time+"+0000)\\/";
}

My solution : I think this is the simplest Way
DateFormat dateFormat=new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
yourJsonObject.accumulate("yourDateVarible",dateFormat.format(new Date()));

The date format that you want is /Date(<epoch time><Time Zone>)/.
You can get the epoch time in java using long epoch = System.currentTimeMillis()/1000;(found at this link) and the time zone you can get by using the date and time patteren as Z. Then combine all the strings into one and store it to the Json Object.
Other possibility is that the time you are getting from iOS device may be of the pattern yyMMddHHmmssZ as got from here. Check the output on the iOS device at different times and identify the correct pattern.

From json.org's description of JSONObject:
The values can be any of these types: Boolean, JSONArray, JSONObject, Number, and String, or the JSONObject.NULL object.
This library doesn't support the "complex" mapping of a Date to a JSON representation. You'll have to do it yourself. You may find something like SimpleDateFormat helpful.

If your format like this -> "DDmmYYYY+HHMM"
DD -> Day (2 Digit)
mm -> Month (2 Digit)
YYYY -> Year (4 Digit)
HH -> Hour
MM -> Minute
Than you can do like this:
SimpleDateFormat format = new SimpleDateFormat("DDmmYYYY+HHMM");
JSONObject object = new JSONObject();
object.put("date", "/Date(" + format.format(new Date()) + ")/");

I suppose that's a representation of ISO international date-time format.
YYYYMMDD+HHMM
I think now you will be able to create that string
may be like,
Date d=new Date();
String tmp="";
tmp="/Date("d.getYear()+""+d.getMonth()+""+d.getDate()+"+"+d.getHours()+""+d.getMinutes()+")/";

Upgrade one of the previous answer:
public static String convertToJsonDateTime(Date dateToConvert) {
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd HH:mm:ss");
long time = dateToConvert.getTime();
return "/Date(" + time + "+0000)/";
}

Formatting a string timestamp with Android

For some reason this has me tearing my hair out.
I have a UNIX timestamp as a string in Android. All I want to do is format this so that it returns the date/time in the user's droid time zone.
I can convert it to a timestamp just fine, but it uses GMT rather than their localised zone.
Thanks

Use the SimpleDateFormat constructor with the Locale you need:
http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html#SimpleDateFormat%28java.lang.String,%20java.util.Locale%29
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
Calendar c = Calendar.getInstance();
try {
Date dt = sdf.parse("2011-03-01 17:55:15");
c.setTime(dt);
System.out.println( c.getTimeInMillis());
System.out.println(dt.toString());
} catch (ParseException e) {
System.err.println("There's an error in the Date!");
}
outputs:
1299002115000
Tue Mar 01 12:55:15 EST 2011