Develop Reference

How to redefine the HOME key press in Android, but only when my application is in the foreground

I want my app to handle the HOME key press with a custom action, and also stay in the foreground. I put the following code in AndroidManidest.xml:
<activity
...
android:launchMode="singleTask">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
<category android:name="android.intent.category.HOME" />
<category android:name="android.intent.category.DEFAULT" />
....
</intent-filter>
</activity>
However, this has set my app as the new home screen, which I don't want. I only want to capture the key press while my app is in the foreground, just like you can capture other buttons. Is there any way to do that? Perhaps set the intent filter to only work while my app is in the foreground?

Receive data intent opens second app when app is opened

<activity
android:name=".activitys.SplashScreen"
android:theme="#style/AppTheme.NoActionBar">
<intent-filter>
<category android:name="android.intent.category.LAUNCHER" />
<action android:name="android.intent.action.MAIN" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.SEND" />
<category android:name="android.intent.category.DEFAULT" />
<data android:mimeType="text/plain" />
</intent-filter>
</activity>
When app is sterted, trying to share the text and app is launching but if open pervious app by android navigation button i see 2 my app exemplars. How to check if app is launched and reopen not open second at one time

Simple answer: you need to add
android:launchMode="singleInstance"
within your activity bracket (below android:name=".activitys.SplashScreen", for example)
Better answer: Go through this article to understand the different types of launch modes: https://medium.com/#iammert/android-launchmode-visualized-8843fc833dbe
Best answer: Read through the doc on tasks: https://developer.android.com/guide/components/activities/tasks-and-back-stack

Handling Home button android for developing lock screen

I am developing lock screen application for that i need to disable the home button.
some one told to me kept in the manifest as category as default, home but when ever device boot completed my activity launches but not finishing.because I my application is home How to handle the Home button.How Go locker application handled Home button
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
<category android:name="android.intent.category.HOME" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
please give me a proper suggestion i would very thankful to you.

You need to add:
<category android:name="android.intent.category.LAUNCHER" />
so your full intent-filter section looks like this:
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
<category android:name="android.intent.category.HOME" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
Not this still won't FORCE the app to run at boot. This will just add it to the list of launchers. It will only launch at boot if the user chooses it as their default launcher.
If you want to run an activity at launch, you can register a broadcast receiver to handle the ON_BOOT_COMPLETED action, but think very carefully before doing so; is this what all users of your app would want?

Android Intent-Filter for Multi Screen

I want to launch my application from web browser in Android using Intent-Filter based on scheme, host in the DATA tag like this.
<activity android:name=".activity.LogoActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".activity.phone.MainActivityPhone" android:configChanges="orientation|keyboard"
android:launchMode="singleTask">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="my" android:host="mystore" />
</intent-filter>
</activity>
<activity android:name=".activity.tablet.MainActivityTablet" android:configChanges="orientation|keyboard"
android:launchMode="singleTask">
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="my" android:host="mystore" />
</intent-filter>
</activity>
As you see, There are two Main Activities for phone and tablet, and in LogoActivity determine which Main Activity will be opened by screen size. But the problem is when user clicks my://mystore link in web browser, there are two choices to launch that MainActivtyPhone and MainActivityTablet.
What I want is there is only one proper intent-filter works for uri my://mystore .
Any help? Thanks.

On the first run of your application, use PackageManager to disable the activity you do not want to use.
Please do not invent custom schemes. Please use HTTP URLs instead:
<data android:scheme="http" android:host="yourdomain.com" android:path="/something/or/another" />
That way, you can actually put a real Web page at http://yourdomain.com/something/or/another, so if somebody gets your link but does not have your app installed, they will see your Web page, instead of getting an error.
Also, please remove android:configChanges, or handle all configuration changes.

Could not launch application by calling a URL from Android Browser

There are many answers in stackoverflow showing how to lauch app from a web browser ,but I am not sure what went wrong with my code, that never seems to be doing the intended.
I am trying to launch my app by a URL from any other app like web browser,initially
my manifest file looks like this
<activity android:name=".Main">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<data android:scheme="http" android:host="ebay.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
And When I typed http://ebay.com in the browser that never started my app.Obviously,how does the browser know about my app?,then i tried the other way around and added another Activity called MyActivity and altered the manifest file as
<activity android:name=".Main">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name=".MyActivity">
<intent-filter>
<data android:scheme="http" android:host="ebay.com" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
</intent-filter>
</activity>
and tried in my Main Activity
startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://mycityway.com")));
Thus producing the intended result.I can also start another application Activity using this method.
But most of the answers here says that the later is possible.What is the mistake i am doing,I couldn't launch my app from browser.Please guide me.

And When I typed http://ebay.com in the browser that never started my
app.
It gets started when a matching link is clicked not when you type the url in the browser.
Try it by sending yourself an email containing http://ebay.com and click the link in the email application.