I need to develop an Android Mobile application using Android Studio. My main purpose is to create an app interface that has an empty space(line) where the user can enter a URL that needs to be verified using the Virustotal API key after clicking the "Verify" button.
What I have currently done:
I have already developed the app to enter a URL and then open it using a Mobile browser after clicking that button.
I have uploaded my exported code of mine.
[Exported Android Studio Code. (https://drive.google.com/drive/folders/14V7aCo5hjyirU9wWDlrnJkNzu4etlSLj?usp=share_link).
Please find the below snaps for your reference.
Initial App Interface
Entering URL
Output what I get
Please note that I don't have much understanding about developments, therefore kindly appreciate all of your support to do this.
Thank you in advance.
I have uploaded my exported code mine and some screenshots of the outputs to the below link.
https://drive.google.com/drive/folders/14V7aCo5hjyirU9wWDlrnJkNzu4etlSLj?usp=share_link
Related
App not installed. Clicking to firebase dynamic link lead to browser and open web content.
I am using this dynamic link: https://market.page.link/?link=https://market.kz/cabinet
I followed this doc: https://firebase.google.com/docs/dynamic-links/create-manually
I tried specify afl and apn but it didnt help.
The reason seems not be under developpers control. I had this problem too because i was always testing with the same app when opening the firebase dynamic link (Skype mobile).
I could not tell you exactly which app are causing this problem, but i can tell you that if you open a firebase dynamic link using skype in your Android device (strangely, it works fine with iOs), it will redirect to your browser at the Google play page.
You should try using another mobile app and open the link and see if it works. I tried facebook messenger and telegram and it works fine.
See more here : https://github.com/firebase/flutterfire/issues/2828
I tried almost all the methods that displayed regarding the query and deeplinking, but none of them worked for me.
This is the type of the link which is to be opened from an android browser
"http://www.udmy.com/view?jb_id=J091107"
How can I start specific activity of my application passing "jb_id=J091107" if this URL is accessed from mobile browser?
Is it possible to get "jb_id=J091107" ?
I also want to open playstore link if app is not installed in phone.
Thanks in advance
Let me start by saying StackOverflow has been a great tool for me as I learn Android development.
What I am trying to figure out is how to click on the ‘OK’ button when I am using the default Android web browser and the following message appears: (Sorry, I can’t post pics yet)
“You are using an unsupported version of Mozilla.
Please upgrade your browser to the latest version before logging in.”
I can’t use Chrome Debug because the “unsupported version” message doesn’t appear when I use the new version of Chrome. I don’t want the users of my app to have to download Chrome to be able to use my app.
I know I can use “document.getElementsByTagName('OK Button Element Tag Name').click();” but how would I find the Element Tag Name without the use of Chrome Debug?
Thanks in advance,
Ken
Have enabled a function in my app which checks up to 12 serial numbers programatically from an android app built in app inventor.
Recently there has been a change in the website code, which has broken the function.
I am trying to analyse the actions that occur when the 'send' button is clicked on the web site.
Am using wireshark. Have managed to 'see' what occurs when button is pressed.
It appears the _VIEWSTATE variable has changed.
Does anyone know if that would break the app?
web site I am querying http://vppneuapps.volvo.com/ww/PIE/PIE.aspx?lang=en-GB
app I have built http://goo.gl/xZCPO (free download)
Any advice/ help greatly appreciated.
Question answered by myself.
Zip file for app inventor here
I am building an android application and I am stuck at one place. I have integrated Twitter in my app using twitter4j, signpost apis. I am successful in writing code for putting text in user profile but I also want the user to follow my app when they click 'follow us on twitter' button.
Can anybody give me reference or guidance of writing such code?
What you are probably looking for is createFriendship()
You can see how it is used here
2016 Edit: Google code svn is broken and twitter 4j has moved
http://twitter4j.org/en/api-support.html