Develop Reference

passing JSON object in URL of RESTFUL Web service in Android?

I am working with JSON Restful web serivces where I have to pass JSON object in the Service URL. I have created the JSON object successfully but getting exception when my URL created the HTTP connection with the SERVER.
Below I have mention my URL:
http://72.5.167.50:8084/UpdateProfileInfo?{"ProfileEditId":"917","ContactsEmail":[{"Email":"dsfs","ContactId":""}],"ContactsPhone":[{"CountryId":"+1","Type":"2","Phone":"345345"}],"ProfileId":"290","LastName":"demo","GroupId":"1212","Title":"sdf","City":"dsf","TemplateId":"1212","State":"dsf","AuthCode":"9bcc6f63-2050-4c5b-ba44-b8103fbc377a","Address":"sdf","FirstName":"demo","ContactId":"","Zip":"23","Company":"tv"}
Getting java.lang.IllegalArgumentException: Illegal character in query in code :
int TIMEOUT_MILLISEC = 100000; // 1000 milisec = 1 seconds
int SOCKET_TIMEOUT_MILISEC = 120000; // 2 minutes
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_MILLISEC);
HttpConnectionParams.setSoTimeout(httpParams, SOCKET_TIMEOUT_MILISEC);
HttpClient client = new DefaultHttpClient(httpParams);
HttpPost request = new HttpPost(url);
HttpResponse response = client.execute(request);
responseString = request(response);
Please suggest me If I am doing something wrong with my URL.
*EDITED:*Tried with a key still getting Exeception:
http://72.5.167.50:8084/UpdateProfileInfo?profileinof={"ProfileEditId":"917","ContactsEmail":[{"Email":"sdf","ContactId":""}],"ContactsPhone":[{"CountryId":"+1","Type":"2","Phone":"345345345"}],"ProfileId":"290","LastName":"demo","GroupId":"1212","Title":"dsf","City":"dsf","TemplateId":"1212","State":"dsf","AuthCode":"d968273a-0110-461b-8ecf-3f9c456d17ac","Address":"dsf","FirstName":"demo","ContactId":"","Zip":"23","Company":"tv"}

There is different format of HTTP request that we needed to make for this kind of REQUEST.
I have mention my code below for this.
public JSONObject getJSONObject(){
return jsonObj;
}
ABove method returns me a JSON String which is passed in the below method.
public static HttpResponse makeRequest(String url) throws Exception
{
//instantiates httpclient to make request
DefaultHttpClient httpclient = new DefaultHttpClient();
//url with the post data
HttpPost httpost = new HttpPost(url);
//convert parameters into JSON object
JSONObject holder = getJSONObject();
//passes the results to a string builder/entity
StringEntity se = new StringEntity(holder.toString());
//sets the post request as the resulting string
httpost.setEntity(se);
httpost.setHeader("Accept", "application/json");
httpost.setHeader("Content-type", "application/json");
//Handles what is returned from the page
ResponseHandler responseHandler = new BasicResponseHandler();
return httpclient.execute(httpost, responseHandler);
}
Stack post helped me for doing this task...!!!

The IP is not correct.
IP is formed with 4 bytes. Every byte is a value from 0 to 255, can't be 7 thousand.
http://7232.25.1617.50:1084
Edit: Okay, you edited your question. You're sending a JSON as parameter. But this parameter has no "key".
Should be:
/UpdateProfileInfo?info={"ProfileEditId":"917",[.......]
Edit: I think this should be like this:
/UpdateProfileInfo?info="{'ProfileEditId':'917',[.......]}"
Notice that the value is surrounded by ", and the inner " are replaced now by '

Probably the issue is that you are trying to POST a JSON object as an url param.
If it really has to be an url param, that it has to be urlencoded.
If it rather should be a normal POST request, I's suggest to use a high level helper:
new RESTClient2(ctx).post("http://72.5.167.50:8084", jsonObject);

I can see a need to work with POJOs , converting them to JSON strings and conveying that string info over HTTP. There are lots of good android/java/apache/volley type libs that permit that.
However, i do not understand, in fact i disagree with your requirement to use GET and the URL parms for transport of your JSON string?
Its really easy to do the following:
POJO -> to JSON -> toString -> to http.string.entity -> POST
Why not re-examine your architecture and consider using POST not GET.
Then its easy , 2 step:
see example "request.setEntity( ... "
your code will look like this:
httpPost.setEntity(new StringEntity(pojo.toJSON().toString()));

Trouble sending JSON Post Android

It has been a while since I programmed for Android and I have lost all my previous work which had the code in it I am having problems with. I am developing an app for both Android and iPhone which connect to the same server to download data. All is well in the iPhone version but on Android when I hit the server with the post data containing the method name I would like to to run on the server it seems that the data is not added to the request.
Why is the POST not working in this request for Android but does for the iPhone version of the app?
Here is the code I am using:
public static void makeRequest() throws Exception {
Thread t = new Thread() {
public void run() {
Looper.prepare(); //For Preparing Message Pool for the child Thread
HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000);
HttpResponse response;
HttpEntity entity;
JSONObject json = new JSONObject();
try {
HttpPost post = new HttpPost("http://divisi.co.uk/rest/requesthandler.php");
json.put("method", "getEventListData");
StringEntity se = new StringEntity(json.toString());
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
post.setEntity(se);
response = client.execute(post);
entity = response.getEntity();
String retSrc = EntityUtils.toString(entity);
JSONObject result = new JSONObject(retSrc); //Convert String to JSON Object
if(result.getString("SC") == "200"){
JSONArray data = result.getJSONArray("data");
}
else{
}
} catch(Exception e) {
e.printStackTrace();
}
Looper.loop(); //Loop in the message queue
}
};
t.start();
}
The response I get mack from the server is:
{"data":{"scalar":""},"SC":405,"timestamp":1363788265}
Meaning the method name was not found, i.e. not posted in my request to the server.

heres an example of how i do things like this:
HttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost("http://divisi.co.uk/rest/requesthandler.php");
MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
reqEntity.addPart(new FormBodyPart("method", new StringBody("getEventListData")));
reqEntity.addPart(new FormBodyPart("NEED_A_KEY_HERE", new StringBody("" + json.toString())));
postRequest.setEntity(reqEntity);
HttpResponse response = httpClient.execute(postRequest);
JSONObject responseDict = new JSONObject(EntityUtils.toString(response.getEntity()));

allow this is your "http://divisi.co.uk/rest/requesthandler.php" page code, then in android you can use this... you don't allow post in your URL,

use fiddler on your sever side. see if the http message is correct. it seems your sever side problem, can you show us your sever side code which receive and parse json.

If the server can't read your request try to remove:
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
It will use the mime type defaults HTTP.PLAIN_TEXT_TYPE i.e. "text/plain".
I don't see any other possibility, if your code is the one you posted and not a more complicated input JSON object.

Your code to set the POST body may be just fine. I think the problem may be with your web service. Try using something like Rested or curl to manually make the call to your server. I made exactly the same request you are making, including with and without the POST body, and I got the same response from your server:
{"data":{"scalar":""},"SC":405,"timestamp":1365704082}
Some things that may be tripping you up:
JSONObject result = new JSONObject(retSrc); //Convert String to JSON Object
if(result.getString("SC") == "200"){
JSONArray data = result.getJSONArray("data");
}
Here, you are comparing the string "405" to "200" using ==, when you should first do a null check and then use .equals("200") instead. Or, use result.getInt("SC") == 200 since this is an integer type in your response JSON.
Also, the "data" entity from your server response is not actually coming back as a JSON array. You should use getJSONObject("data") instead.
Additionally, it's always a good idea to externalize your strings.
Here's how the code should look:
public static final String JSON_KEY_SC = "SC";
public static final String JSON_KEY_DATA = "data";
...
JSONObject result = new JSONObject(retSrc); //Convert String to JSON Object
String sc = result.getString(JSON_KEY_SC);
if (sc != null && sc.equals("200")) {
JSONObject data = result.getJSONObject(JSON_KEY_DATA);
}
else {
...
}

Posting a url containing an underscore (_)

I am posting a url with params containg an underscore (_).
sample: http://sdsdsds_asasasahjhd.com/dsdsdsd/login.json?
I am posting it like this:
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://sdsdsds_asasasahjhd.com/dsdsdsd/login.json?");
try {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("key1", "value1"));
nameValuePairs.add(new BasicNameValuePair("key2", "value2"));
nameValuePairs
.add(new BasicNameValuePair("key3", "value3"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (Exception e) {
e.printStackTrace();
}
When I am inspecting httpclient.execute(httppost) I am getting IllegalArgumentException and in catch in exception details it is telling Host name cannot be null.
Please specify any solution.
I have gone through some other questions here:
java.lang.IllegalStateException: Target host must not be null, or set in parameters
Host name may not be null in HttpResponse execute for android
but no use as I am not encoding the whole url.

I have an open-source library with network implementation mechanism. It has just receiver an workaround implementation. All you need it to set the host by reflection in case of troubles:
final URI uriObj = new URI("https", host, path, null, null);
if (uriObj.getHost() == null) {
final Field hostField = URI.class.getDeclaredField("host");
hostField.setAccessible(true);
hostField.set(uriObj, host);
}
return uriObj;
The commit is here.

well it clearly states that the host name can not be null.. your url doesn't specify one..
a url is expected to be in the format
http://hostName.com/example..../example.json

HttpPost httppost = new HttpPost(String);
This contructor will attempt to form a URL instance from the provided String. If this fails, you'll be dealing with a null value.
Please post the actual URL you're using and not a sample if you want us to be able to help you further.

See this link. Apache doesnt support underscore. You should change the url
https://issues.apache.org/jira/browse/HTTPCLIENT-911

How to send a JSON object over HttpClient Request with Android?

I want to send the JSON text {} to a web service and read the response. How can I do this from android? What are the steps such as creating request object, setting content headers, etc.
My code is here
public void postData(String result,JSONObject obj) {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpParams myParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(myParams, 10000);
HttpConnectionParams.setSoTimeout(myParams, 10000);
String json=obj.toString();
try {
HttpPost httppost = new HttpPost(result.toString());
StringEntity se = new StringEntity(obj.toString());
se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
httppost.setEntity(se);
HttpResponse response = httpclient.execute(httppost);
String temp = EntityUtils.toString(response.getEntity());
Log.i("tag", temp);
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
}
what mistake i have done plz correct me because it shows me an bad request error
but when i do post in poster it shows me status as Successfull 200 ok

I do this with
httppost.setHeader("Content-type", "application/json");
Also, the new HttpPost() takes the web service URL as argument.

In the try catch loop, I did this:
HttpPost post = new HttpPost(
"https://www.placeyoururlhere.com");
post.setHeader(HTTP.CONTENT_TYPE,"application/json" );
List<NameValuePair> nameValuePairs = new
ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("json", json));
post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpClient client = new DefaultHttpClient();
HttpResponse resp = client.execute(post);
HttpEntity entity = resp.getEntity();
response = EntityUtils.toString(entity);
You can add your nameValurPairs according to how many fields you have.
Typically the JSON might become really huge, which I will then suggest gzipping it then sending, but if your JSON is fairly small and always the same size the above should work for you.

If it is a web service and not RestAPI call then, you can get the WSDL file from the server and use a SOAP Stub generator to do all the work of creating the Request objects and the networking code for you, for example WSClient++
If you wish to do it by yourself then things get a little tricky. Android doesn't come with SOAP library.
However, you can download 3rd party library here: http://code.google.com/p/ksoap2-android/
If you need help using it, you might find this thread helpful: How to call a .NET Webservice from Android using KSOAP2?
If its a REST-API Call like POST or GET to be more specific then its is very simple
Just pass a JSON Formatted String object in you function and use org.json package to parse the response string for you.
Hope this helps.

HTTP Post Encoding

What I try to do
Hello Guys,
I try to create a login for my server, that I can access the data on it over my app. For this i created a Methode called 'public void doLogin(final String username, final String password)' . In this Methode I start a Thread in which I post the username and password to my server. Now to problem starts. When I do the post my server can't handle my post which looks like this: '"username="+username+"&password="+password'.
To try if its a serverside problem (infact its not) I made a post over 'curl -d' with the same parameters and I get a response without any problems.
For your information the server runs on Ruby3
Question
How do I need to change my Post to the server that it can handle the data I send. By the way the string I post must look exactly like that: '"username="+username+"&password="+password //this means username=LEUSER&password=LEPASS'
Please tell me what I need to change, some code snippets or tutorials would be great. Down here you find the importrent codesnippets of the doLogin Methode
Code
public void doLogin(final String username, final String password) {
Thread t = new Thread() {
public void run() {
String URL = "http://192.168.110.126:3000/sessions.json"; //für momentane testzwecke
DefaultHttpClient client = new DefaultHttpClient();
HttpResponse response;
try {
HttpPost post = new HttpPost(URL);
StringEntity se = new StringEntity("username="+username+"&password="+password);
post.setEntity(se);
response = client.execute(post);
if (response != null) {
//response handling
handler.sendEmptyMessage(0);
}
} catch (Exception e) {
e.printStackTrace();
Log.e("DataHandler", "URLConnection-Error" + e);
}
}
};
t.start();
}
Please Guide me Regarding This.

Your code looks like you are sending a html form. In fact curl adds a content-type (with value application/x-www-form-urlencoded) to the http header if you use the -d option.
So try to add the header field like this:
HttpPost post = new HttpPost(URL);
post.addHeader("Content-Type","application/x-www-form-urlencoded");
...

What you need to change is the String entity part. You should change with the following;
ArrayList<NameValuePair> requestParameters = new ArrayList<NameValuePair>();
requestParameters.add(new BasicNameValuePair("username", username));
requestParameters.add(new BasicNameValuePair("password", password));
username & password are the variables that are input on the program.
Lastly, if you forget to set permission it also won't work. You need to set android.permission.INTERNET