Android char java.lang.String.charAt(int)' on a null object reference - android

I'm trying to get the first char from a string in an Array-adapter. After I run the application, it will work but while scrolling, the listview is crashing the application and I am getting the error:
java.lang.NullPointerException: Attempt to invoke virtual method 'char java.lang.String.charAt(int)' on a null object reference at this line char first = typenameRGN.charAt(0);
Here is my code in ArrayAdapter:
String typenameRGN = all_Post.getStrShortName();
Log.e("typenameRGN ", " = " + typenameRGN);
char first = typenameRGN.charAt(0);
Log.e("first ", " " + first);
String strTypeRGN = Character.toString(first);
Log.e("strTypeRGN ", " " + strTypeRGN);
holder.txtInitialLetter.setText(strTypeRGN);
Thanks.

Let check arrayadapter all_Post .
Maybe this array altered(clear,..) when listview scroll and it return null

Related

ContentValues getAsLong NullPointerException

I have a ContentValues that I'm parsing for data. I just received a very strange crash report:
Fatal Exception: java.lang.NullPointerException: Attempt to invoke
virtual method 'long java.lang.Long.longValue()' on a null object
reference
private void populateMeta(final ContentValues values)
{
if (values == null)
return;
Date d = new Date(values.getAsLong(Meta.Data.TIMESTAMP));
...
}
When I look in getAsLong I can't see how this could happen:
public Long getAsLong(String key) {
Object value = mValues.get(key);
try {
return value != null ? ((Number) value).longValue() : null;
} catch (ClassCastException e) {
if (value instanceof CharSequence) {
try {
return Long.valueOf(value.toString());
} catch (NumberFormatException e2) {
Log.e(TAG, "Cannot parse Long value for " + value + " at key " + key);
return null;
}
} else {
Log.e(TAG, "Cannot cast value for " + key + " to a Long: " + value, e);
return null;
}
}
}
It should just be returning null if the field is null, no?
Update:
Tried a few things to recreate that stack trace and in the end this narrowed it down:
values = new ContentValues();
Long timestamp = values.getAsLong(Meta.Data.TIMESTAMP); // null, as expected
Date d2 = new Date(timestamp); // source of error
Now here's the interesting thing. Adding a watch on new Date(timestamp) throws
NullPointerException: cannot unbox null value
which makes sense. However, letting that same line execute normally in code yields:
Attempt to invoke virtual method 'long java.lang.Long.longValue()' on a null object reference
Which I'm guessing is the root cause of the unbox error. I grasp unboxing, but I'm no expert, so I'd love a better explanation for why the stack trace seems so odd (and finicky) for this error. Thanks!
I had the same error, worked around by checking if such key exists with containsKey().
values.containsKey(Meta.Data.TIMESTAMP)
I am suspecting usage of weakreference to database results. Not exactly sure. Just adding a workaround here for this strange error.

How can I create Android logcat entries that provide a link to source code in Eclipse? [duplicate]

Is there any way to access automatically any Log in Logcat by a double click ?
Actually, when there is an error crashing my Android Application, I can double click on the line saying for instance
at com.myapp.mypackage$Class.function(File.java:117)
And by Double-clicking on this line, I am automatically redirected to the related line of my code.
But, when I try to generate the same line in another Log, example :
Log.e("TAG", "at com.myapp.mypackage$Class.function(File.java:117)");
The Double-Click doesn't work anymore ...
Any ideas ?
If you want to create a log in logcat that can be clicked and go to your line use the following method to create it:
Enjoy!
public static void showLogCat(String tag, String msg) {
StackTraceElement[] stackTraceElement = Thread.currentThread()
.getStackTrace();
int currentIndex = -1;
for (int i = 0; i < stackTraceElement.length; i++) {
if (stackTraceElement[i].getMethodName().compareTo("showLogCat") == 0)
{
currentIndex = i + 1;
break;
}
}
String fullClassName = stackTraceElement[currentIndex].getClassName();
String className = fullClassName.substring(fullClassName
.lastIndexOf(".") + 1);
String methodName = stackTraceElement[currentIndex].getMethodName();
String lineNumber = String
.valueOf(stackTraceElement[currentIndex].getLineNumber());
Log.i(tag, msg);
Log.i(tag + " position", "at " + fullClassName + "." + methodName + "("
+ className + ".java:" + lineNumber + ")");
}
If you don't mind the clutter in your log, you can easily just add a new Exception() to the log message
Log.e("TAG", "Looky here see", new Exception());

How can I write a regular expression for this in android?

I am having a string(number) with special characters. I want to search for a sub-string(comprising of digits only) & also I want to detect the starting index & ending index of matching sub-string in the string.
For example: main string: (+91)-1231212 1231
Sub-string to search: 1212
Currently I am using the following code to do this but in place of 1212,it searched for 12312. For other cases, it works fine.
String sss0 = "1212";
String sss1 = "(+91)-1231212 1231";
sss0 = sss0.replaceAll("[^\\d]","");
System.out.println("*************************"+sss0);
String ptn = "" + sss0.charAt(0);
for(int jj=0; jj<sss0.length()-1; jj++){
ptn += "[^" + sss0.charAt(jj) + sss0.charAt(jj+1) + "]*?" + sss0.charAt(jj+1);
}
System.out.println("ptn: " + ptn);
Pattern p300 = Pattern.compile(ptn);
Matcher m300 = p300.matcher(sss1);
if(m300.find()){
System.out.println("start, stop: " + m300.start() + "," + (m300.end()-1 ));
System.out.println("substring: " + sss1.substring(m300.start(), m300.end()));
}
Please help me. Thanks in advance.
Try this :
int start = sss1.indexOf(sss0);
if(start != -1) {
System.out.println("Start : " + start);
System.out.println("End : " + start.length()); //maybe add +1 here depending on what you mean by end index.
}
You can also put this in a loop to find all occurences of the substring.
pseudocode:
pattern = ""
foreach char c in sss0:
pattern += c + "[^0-9]*"
found_substring = match(pattern, sss1)
the idea being to intersperse the literal characters you're looking for with the pattern that you're willing to skip over.

Is there any way to access automatically any Log in Logcat by a double click?

Is there any way to access automatically any Log in Logcat by a double click ?
Actually, when there is an error crashing my Android Application, I can double click on the line saying for instance
at com.myapp.mypackage$Class.function(File.java:117)
And by Double-clicking on this line, I am automatically redirected to the related line of my code.
But, when I try to generate the same line in another Log, example :
Log.e("TAG", "at com.myapp.mypackage$Class.function(File.java:117)");
The Double-Click doesn't work anymore ...
Any ideas ?
If you want to create a log in logcat that can be clicked and go to your line use the following method to create it:
Enjoy!
public static void showLogCat(String tag, String msg) {
StackTraceElement[] stackTraceElement = Thread.currentThread()
.getStackTrace();
int currentIndex = -1;
for (int i = 0; i < stackTraceElement.length; i++) {
if (stackTraceElement[i].getMethodName().compareTo("showLogCat") == 0)
{
currentIndex = i + 1;
break;
}
}
String fullClassName = stackTraceElement[currentIndex].getClassName();
String className = fullClassName.substring(fullClassName
.lastIndexOf(".") + 1);
String methodName = stackTraceElement[currentIndex].getMethodName();
String lineNumber = String
.valueOf(stackTraceElement[currentIndex].getLineNumber());
Log.i(tag, msg);
Log.i(tag + " position", "at " + fullClassName + "." + methodName + "("
+ className + ".java:" + lineNumber + ")");
}
If you don't mind the clutter in your log, you can easily just add a new Exception() to the log message
Log.e("TAG", "Looky here see", new Exception());

Simple If Statement

I am trying to pass two variables from one screen to another. From the previous screeen you click a button, 1 or 2 and it passes that value on. It also passes the value 2 as the correct value. I know they are both working as I output each variable on the next screen. Here is the code. It always outputs wrong though.
Intent i = getIntent();
Bundle b = i.getExtras();
String newText = b.getString("PICKED");
String correct = b.getString("CORRECT");
TextView titles = (TextView)findViewById(R.id.TextView01);
if(newText == correct){
titles.setText("Correct" + newText + " " + correct + "");
}
else{
titles.setText("Wrong" + newText + " " + correct + "");
}
because you are not comparing the string. you are comparing if both are pointing to same object.
to compare string use
if(nexText.equals(correct))
if(newText == correct)
This will always be false. To compare the contents of two Strings character by character, use the .equals method:
if( newText.equals(correct) )
Using == on objects in Java means you are comparing the values of the memory address stored in these pointers/references. Since they are different String objects, they will never have the same address.
You don't compare Strings this way, rewrite code this way to get things done:
Intent i = getIntent();
Bundle b = i.getExtras();
String newText = b.getString("PICKED");
String correct = b.getString("CORRECT");
TextView titles = (TextView)findViewById(R.id.TextView01);
if(newText.equals(correct)){
titles.setText("Correct" + newText + " " + correct + "");
}
else{
titles.setText("Wrong" + newText + " " + correct + "");
}

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